I am someone like maths and puzzles. I think maths is interesting in exploring or even drilling IF you understand the REASONS behind, but not only following certain procedures like black magic. Therefore, even this channel is for my DSE students, I seldom share some specific tricks(神技🤪). And sometimes I will post some proofs or explanation which may not directly related to exam questions. Finally, I am still a learner, lets growth together.
I'm glad to hear that, I upload those video few years before since i want to support my students and who eager to achieve better result in maths. However, i am no longer teaching non-chinese speaking students. It quite difficult for me to prepare new video in English. Sorry for letting you disappointed. Hope you get good result in coming exam.
hello , really love ur channel and the way u explain how to do each questions! btw was wondering if u could make more dse question videos for the preparation of 2024 dse?
Thanks so much for your appreciation!! It is a ready great support for me. I may upload some video for my students in the coming month, but i am not sure whether those video suitable to you, hope you can enjoy practicing and get good result
for the minimum total area case we assumed the removing square length is 2.5, while the actual length is <2.5 that's why 13 is a limit, but not really 13
b(i) Another way is to straight up calculate the area of PQSR at u=12 and at u="any number between 0 and 20 not equal to 12". I picked u=8 because sqrt(64+36) is just nice. Then find that the latter area is smaller than the former. Hence the claim is disproved. Definitely defeats the purpose of the question, and maybe require some intuition on the graphs F and G, but it's a valid argument (although DSE marking can be oddly specific at times, huh). Here's the desmos graph for those who likes to play around. www.desmos.com/calculator/srxjtndllz
@@kenleung5735 I think yours looks cleverer (and probably what DSE is looking for)! But then, of course, it would be really annoying if you expand out u*PQ and then differentiate the expression rather than leaving PQ as is.
可否用incentre 1:2 關係搵radius of inscribed circle？因為S, incenter 同mid point of RQ is collinear 所以ratio of radius to distance from incenter to S is equal to 1:2
