Being a math enthusiast, a tutor and software engineer for 28 yrs., I have often noticed that some concepts of high school-level mathematics could be explained in a simpler & more intuitive way, and that’s what I aspire to accomplish by uploading math videos in this channel where each & every concept will be explained in great details so that everyone can understand the math concepts & appreciate the beauty of math!
Currently, I am working on the JEE (India) Main/Advanced syllabus. After that, I plan on covering Algebra1, Algebra2, Geometry, Trigonometry, Precalculus, Calculus1/2/3 as per the US curriculum. And finally Olympiad mathematics!
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Hi - If you are talking about 140° as in interior angle of a regular ploygon, then we can try this formula to find the type of the regular polygon / no. of sides. Each Interior angle of a regular polygon = ((n-2)*180°)/n ⇒ 140° = ((n - 2)*180°)/n ⇒ 140°.n = (n - 2)*180° = n.180° - 360° ⇒ n(180° - 140°) = 360° ⇒ n.40° = 360° ⇒ n = 360°/40° = 9 So, the no. of sides of the regular polygon is equal to 9, which means it is a Nonagon. Thank you for your support!
Hi - Thank you for your suggestion! After completing Conic Sections, I am planning to start working on topics from Algebra. After completing Algebra, I will start working on Vector and 3-D Geometry. After that, I will move on to Precalculus & Calculus. Along with Precalculus, I will cover Inverse Trigonometric Functions & Trigonometric Inequalities. Thank you for your support!
May God abundantly bless you with a plethora of earthly and above all Heavenly treasures and blessings!!! Thank you so much for your help on a seemingly difficult problem! However, I have a question, How did you determine that EB/BC = cos60? Thanks again and may God send a deluge of blessings your way!!!
Hi - Thank you for the kind words! If you carefully look at △CEB, it is actually a right triangle because ∠CEB is a right angle since CE is perpendicular to AB. In a right triangle, the Cosine ratio of an acute angle = adjacent side / hypotenuse. In the right triangle △CEB, the adjacent side for ∠CBE (which is equal to 60°) is EB and the hypotenuse is BC. That's why, in △CEB, Cos 60° = EB/BC. Hope it is clear now. Appreciate your blessings & support !!!
@@finemath You're welcome, anytime for the kind words! Wow, I'm stunned at how well you expounded it in the video and how I somehow didn't understand it the first time; when I was in the middle of reading your compendious explanation, I scrolled back to the video, it all clicked, and I solved the problem in about 25-30 seconds. It's crystal-clear now, for you made it a seemingly difficult problem become relatively easy! You're very welcome; your pure-hearted help is admirable and exemplary, so please firmly grasp it forevermore!
Please see that at 7-50 we have got the required distance with relation to what have been given. Hence may not understand what the utility to enhance the video time is. Thanks
Hi - In fact I could have stopped at 10:13 because the expression was reduced to a simple enough form. That form can be used if we are given: R, A, B and C. However, I decided to continue a little further to express it in terms of the circumradius and the radius of the 1st excircle. So, we should use whichever expression/formula is most suitable depending on the info provided in the actual question. Thank you for your support!
After getting c we may find area by 1/2absinC(take 🔺 ) Then 1/2bcsinA=🔺 SinA=2 🔺 /bc Then angle A will be known. 1/2casinB=🔺 SinB=2 🔺 /ca Angle B will be known. Thanks. Plz offer views
Hi - Your approach will work fine, too. In fact all of these formulae are inter-connected. For example:- Let's assume, a, b, C are given. Using Cosine Law, we can easily calculate the value of the 3rd side length c. After that, to find the angle A, as you have suggested, ∆ = (1/2)bcSinA => SinA = 2∆/bc Now, if we substitute ∆ with (1/2)abSinC, we will get:, SinA = 2((1/2)abSinC)/bc = (a/c)SinC which is what I have derived in the video. So, whichever way we go, we will get the same result. :) In the real exam paper, based on the provided data, take whichever approach would make the calculation easy or whichever approach you are most comfortable with. Thank you for your support!
Hi - The "n" here is the "degree of the polynomial expression/function". The degree of a polynomial is the highest exponent of the variable 'x' in the expression/function. For example, what is the degree of the polynomial expression: 10 + 9x + 3x^5 - 7x^2 + 11x^4 ? Well, among the five terms, the 3rd term has the highest degree/exponent of x which is 5. Therefore, the degree of this polynomial expression is actually 5. Hope it's clear now!
Hi - I have not done any videos on Trigonometric Inequalities yet. I plan on doing it after I start working on Function graphs (right before Calculus). Though some simple Trigonometric Inequalities can be solved with the help of Unit Circle, more complex Trigonometric Inequalities will require trigonometric function graphs to easily understand the solutions set. Thank you for your support!!!
