In this channel, I will upload step by step animation of "Engineering drawing by N. D. Bhatt" Problems with solutions, Engineering drawing solutions in AutoCAD, CATIA, Ansys tutorials, MATLAB tutorials, Finite element methods, AUTOMOBILE ENGINEERING tutorials, Computer aided design, Power Plant Engineering, MCQ on various courses. projections of points ru-vid.com/group/PLGkoY1NcxeIbh3bVe98O3E9wk_p6_o9Zq projections of straight lines-1 ru-vid.com/group/PLGkoY1NcxeIYuZrBuvQIqMLCjMh4OVB5D projections of straight lines-2 ru-vid.com/group/PLGkoY1NcxeIYompl7lAi84oZbhLo_UAxw projections of planes ru-vid.com/group/PLGkoY1NcxeIZqYAyvAIdVxUuQqCD84hZ1 projections of solids-2 ru-vid.com/group/PLGkoY1NcxeIZXntFcCPh1tnEg4kDUGsmo sections of solids ru-vid.com/group/PLGkoY1NcxeIZDdWzjgjlhacyCms_Vw3kW
line of 100 mm long makes an angle of 350 with H.P and 450 with V.P. Its midpoint is50mm above H.P and 50 mm in front of V.P. Draw the projections of the line
line of 100 mm long makes an angle of 350 with H.P and 450 with V.P. Its midpoint is50mm above H.P and 50 mm in front of V.P. Draw the projections of the line
The projections of the ends of a line EF are on the same projector. The end E is 10mm above HP and 15mm in front of VP. The end F is 35mm above HP and 45mm in front of VP. Draw the projections. Find the true length, true inclinations and traces.
A point P is 50 mm from both the reference planes. Draw its projections in all possible positions.Two points A and B are in the HP. The point A is 30mm in front of the VP while B isbehind the VP. The distance between their projectors is75mm and the line joining theirtop views makes an angle of 450 with xy. Find the distance of the point B from the VP.
A point 30mm above xy line is the plan view of two points P and Q. The elevation of P is 45mm above the HP while that of the point Q is 35mm below the HP. Draw the projections of the points and state their position with reference to the principle planes and the quadrant in which they lie
but in the given question they mentioned that a side parallel right , why you have choosen that pentagon instaed of normal pentagon reply fast sir tomorrow i have exam .
relations b/w angular and linear motion: s=r(theta) v=r(omega) a=r(omega)^2 kurtzbach-grubler criteria for plane: F=3(n-1)-2j-h shortcut=L-(2N+1) N=no of loops in mechanism L=Links No of ICs: Lc2=L(L-1)/2 No of joints: terinery-->3=j-1= 2 Binary quarternary-->4=j-1= 3 BInary good session👍
Same question but has a corner of its base on the ground its axis is inclined at 30 to the ground and parallel to vp ani vachindhi sir exam lo ee answer aa ga sir dhaniki rayali
