Is it a mistake that there is no 13, 17, and 30 anywhere in the leaf nodes of this tree?

how can solve the left-deep in a query

Very clear explanation, easy to understand

god

The "between" OP should also be allowed in the composite search key.

u saved my life broo thanks a lott

thank u

Thank you man, very helpful. 2 hours till exams and you made everything really clear

What are the steps of computing the average case of sorted file?

This is gonna save me.

zhian

🥲

yo that's complicated but so cool

The range search of sorted file can be faster!!! Keep using binary search when you get the first number!

god

god

Berkeley professor i cant understand sab you make me sleep

This is really good. Thank you sir.

Hi

This was very helpful!!! Thank you 🙏

awesome

its great

Thanks for the good videos. I am confused about writing an END log record for an Xact in the 'Committing' state without flushing the dirty pages before it. ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-wED22gICTd4.html. I searched the original paper, and the pseudo code shows that: "The only log records that may be written by this routine are end records for transactions that had totally rolled back before system failure, but for whom end records are missing". Is the paper talking about a different version of ARIES?

Better: use a thread library that works.

I actually thought databases were boring. :-)

Not buying the hash/sort duality. But mergesort and quicksort are informally dual: mergesort = simple split, recursive sort, fancy join quicksort = fancy split, recursive sort, simple join.

It's not 100% obvious how sorting and hashing work for duplicate detection. For sorting, see en.wikipedia.org/wiki/Weak_ordering For hashing, suppose we have a bucket with 100 elements in it. Are the elements unique ? Maybe, maybe not. So hashing by itself doesn't completely solve the problem.

Suppose we hash by gender, as in the earlier video. Then we have three values (M, F, O). This video makes it sound like all men are duplicates of each other, which makes no sense.

When we compare numbers, we have n1 <= n2 and n2 <= n1 implies n1 = n2. But when we compare address records by name, this axiom fails: r1 = "Smith, John, New York" and r2 = "Smith, John, California". To solve this problem, the C++ sort function uses a strict weak ordering: en.wikipedia.org/wiki/Weak_ordering

gigantic s

great content

why i have not discovered you earlier

Thank you

These concepts are very well explained! Thanks

4:35 on the final why 17 is pointer to 30 not 24 ?

Ege Bilmuh burada. Bakalım işimize yarayacak mı

EECS484 students have watched this life saving video 100 times :)

That video is really helpful. Thank u so much for this video ❤😊

Where can we get these ppts

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Very clear!

But what if the tuples of R in partition 1 don't fit Hash table buffer, how should we handle it? It might indicate we should look back some tuples?

power point explanation is bad. hard to follow. If you use power point you have no teaching power

Does he read a text? Sound weird

Swaraj Bro said, You're the best.. Thank you

Why cost for PageBased Nested Loop Join is [R] + ([R] * [S]) but not [R] * [S]?

mind clear after watching this visualized explanation! thank you!

3:47 SHOTS FIRED