A resource place for senior secondary school students who use New General Mathematics as their main maths text; and for anyone else who needs a graded senior secondary school (high school) maths study guide.
0:00 - Introduction of concepts 01:14 - Question 1 03:26 - Question 3 07:14 - SUBSCRIBE and turn on notifications www.youtube.com/@NonsoMaths?sub_confirmation=1 07:22 - Extras Thanks for watching, and see you in the next one.
Since you have already solved it, here is another method. Simplify the exponents on the right side, then take the Logarithm of both sides. (4x - 1)Log2 = Log 1 (4x - 1)Log2 = 0 (Log 1 = 0 by definition) Divide both sides by Log2. 4x - 1 = 0 4x = 1 (Transpose 1 to the right side) x = 1/4 (Divide both sides by 4).
I greatly appreciate your input. Thanks a lot!!! But i have a problem with dividing zero by anything (or worse still, dividing anything by zero 😣) From the point where: (4x - 1)Log2 = 0 My argument will be: "Since given the above product and knowing that Log2 is not 0, then" 4x - 1 must be equal to 0 from where x = 1/4 😁
@NonsoMaths Dividing 0 by Log2 is not the same as dividing by 0. Dividing 0 gives zero, but division by zero is undefined. The only reason for dividing by Log2 is to remove Log2 from both sides and leave 4x - 1 = 0, which can be solved as a linear function.
He never said they were the same. He said that instead of saying that you divided zero by a number, realize the fact that if the product of two items is zero, then they are either both zero, or one of them is zero. And since log 2 very clearly can NOT be zero, then (4x - 1) = 0.
@NkechiR I do not see a problem or the need for an argument over this. You can divide both sides by Log2 to get rid of it or use a Zero Product Property to reason it.
The correct answer is 6+1/4 (Choice C). Reasoning/Method. A quadratic function in the form of a (perfect square) trinomial has the discriminant b^2 - 4ac = 0. Therefore; b^2 = 4ac (Transpose 4ac to right side) Given; a = 1, b = 5, and c = k b^2 = 4ac 5^2 = (4)(1)(k) 25 = 4k 4k = 25 k = 25/4 k = 6 + 1/4 The correct answer is Choice C.
0:00 - Question 1: Counting parallelograms/rectangles 02:16 - Question 3: In the figure, ABCD and CDEF are parallelograms and ABEF is a straight line. If |BE| = 2 cm and |DC| = 3 cm, find |AF|. 03:43 - Question 5: In the figure, ABCD is a rhombus and APCQ is a square. If angle PAB = 21 degrees, calculate the four angles of ABCD. 08:25 - Question 7: ABCDEF is a regular hexagon with O at its centre. What kind of quadrilaterals are ABCO and ACDF? 13:26 - Question 9: ABC is a triangle and M is the mid-point of line BC. A line through C parallel to line AB cuts line AM produced at X. Prove |MX| = |MA|. Please subscribe, like and Share to support the channel. www.youtube.com/@NonsoMaths?sub_confirmation=1 Thanks for watching.
0:00 - Question 1: Give a formal proof that a quadrilateral with one pair of opposite sides equal and parallel is a parallelogram. 03:02 - A brief discussion on transversals, corresponding angles, vertically opposite angles and alternate angles. 07:46 - **The condition for congruence is SAS (Side - Angle - Side)** 11:15 - Question 2: Give a formal proof that the diagonals of a rhombus, i) bisect each other at right angles, ii) bisect the angles of the rhombus. 33:17 - Congruent Triangles.
0:00 - What is an isosceles triangle? 06:00 - Question 3 07:36 - Question 5 09:04 - Question 7 09:18 - Question 9 11:29 - Question 11 13:38 - Question 13 14:41 - Question 15 16:38 - Question 17 19:59 - Question 19 Thanks for watching. Please subscribe, like and Share to support the channel. www.youtube.com/@NonsoMaths?sub_confirmation=1 *All angles are measured in degrees. Please forgive my omission of some of the degree signs, and ALWAYS REMEMBER TO ADD YOURS.
0:00 - Introduction 07:06 - Question 1: The angles of a triangle are x, 2x and 3x. Find the value of x in degrees. 08:20 - Question 3: In a right-angled triangle, one of the acute angles is 20 degrees greater than the other, find the angles of the triangle. 10:19 - Question 5: Find the interior angles of a regular polygon which has (a) 6, (b) 10, (c) 20 sides. 14:47 - Question 7: A regular polygon has angles of size 150 degrees each. How many sides has the polygon? 16:36 - Question 9: Four angles of a pentagon are equal and the fifth is 60 degrees. Find the equal angles and show that two sides of the pentagon are parallel. 20:28 - Question 11: In triangle ABC, the bisectors of angle B and angle C meet at I. Prove that angle BIC = 90 degrees + half angle A. 26:54 - Question 13: In the figure shown, line BX is the bisector or angle ABC and line CX is the bisector of angle ACB. If angle A = 68 degrees, find the size of the obtuse angle BXC. 28:38 - Question 15: A regular polygon has an angle of size 160 degrees each. How many sides does the polygon have? [n=18] Question 17: A regular polygon of n sides has each exterior angle to be 45 degrees. Find the value of n. 30:05 - Closing remarks Thanks for watching. Ask any questions in the comments. SUBSCRIBE for more videos. Like and share to help out the channel.
