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So if friction zero na F applied is not sufficient to break the static friction and move the body. So in this case f=0. Ipa intha case consider pannuna, F applied is equal to f. So the friction now becomes limiting friction. In this case frictional force acting is equal to F applied. Apa 4 options la ethu f = F applied nu iruko athu tha choose pannanuma anna?
We calculated f= 12N ( consider ). But applied force is only 8N. Apa in this case friction f=0. Correct ah ithu anna?. I get a lot of confusion where to put zero and where to put f=F applied. Because friction static = F applied.
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Hey... Nicely recorded, l am in 2nd yr too... in Kolkata.... I love southern India ... want to go there for my residency.... ❤ , l also know tamil but very little 😂