Hey, today I got the royal flush plus de 9, which was even more lucky than a normal royal flush(9,10,J,Q,K,A) could you help me determine the probability of getting this combination ? On a normal texas hold’em board of 7 cards. Thank you by advance
I don’t get why it wouldn’t involve some series. Or did you do that already on the denominator? 32/52 then (x(dunno what this should be)/n-1)! +_ x/n-2 etc
Hit one tonight! Playing with a bunch of 70 year old veterans, who play twice a month. & the 27 year old guy hit the coveted Royal Flush. No one had ever seen one before. I blacked out. My memory is gone from the time i rivered the 10 of spades to the time i called All In. My brain was going bezerk, while trying to keep a straight face. Such a cool moment.
This appears to be a high school math class. I stumbled upon it because I was looking for some numbers for my research. Great job on the series! These are some good examples to introduce probability as a subject. The actual math behind hitting a flush in poker is significantly more complicated. For example, suited hands have a significant "flush equity", which is the chance of hitting a flush with any two starting cards. The actual math of hitting the flush will be landing three cards of the same suit as your hand out of a 5 card draw. The math becomes even more complicated if you account for the other 5 players having any 2 remaining cards randomly.
This is correct for only 10 J Q K A in this order What about J 10 Q K A and other combinations ? For this we multiply top by 5! We get 2/10 829 Which is ≈ 0,00018 => 0,018%
Great video, but this won't help you if you don't memorize the first quadrant radiant measures or if the angle is not a round number (like 29 degrees for example). Is there a way to find sin cos tan without a calculator?
I remember one probability problem I had to solve when I was in school. None of my colleagues soved it and I still don't know how to solve it. From a deck of 52 cards (13 ranks and 4 suits) a sample of 16 cards is extracted. What is the probability that, for at least one of the ranks, we get at least three of that rank? I remember I've tried to use the hypergeometric distribution and obtained a value larger than one, which of course is wrong. Any ideas?
Excellent presentation! Explaining combinations based on previous examples of well laid out permutations helps greatly to distinct the two and their meanings! Well done !!!
