Simple Snippets is a Tech -Educational channel for everyone who wants knowledge about Information Technology (IT) & Computer Science (CS) oriented subjects such as Programming, Database, Networking, Computer Architecture, Operating Systems, Mathematics etc.
My name is Tanmay Sakpal and I love Technology and wish share all my knowledge in the form of high quality, simple and easy to understand videos on this channel. If you happen to read this, checkout my videos or come across any of Simple Snippet content (website article, Instagram post, FB post, MEMEs :-P ) do respond or hit me up with a hi or hello. I would love to interact with you all.
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guy help, my project is pdf file not only img , so i have to make the admin uplode the file and the user can download it if they sigh in , pllleaaasss heeelppp😭😭😢😢😭😭😭
Really good explanation, but even after watching your video I had some doubts, resovling them I came across the fact that ; when the jvm uses the jit compilation the interpretation process is completely skipped. The jit produces the native machine code directly, which is ready to be executed.
It's a very helpful video like for me as a beginner and I also want to know from you how you understand these concepts because I forgot easily ❤please reply and give me some tips
Two greater weaknesses in your effort to be pointed out in order that you are useful in what you are doing...1st speak slowly clearly and well which is very important in sending message 2ndly have the board not in the dark so people can see what you trying to share..
Hi my dear sir!I am feel very pleasure and stastified about this course . i have learnet completely from your course.And your course is my most Favourite. i am intrested. sir please sir if you have do phyton course or data science course sir please give me link. i want to sea!
The reason why P2 didn't run after P1 at time 6 is that in Round Robin scheduling, the processes are executed in a cyclic order based on their arrival times. When P1 finishes its time quantum at time 6, P0 is the next in line because it was already in the queue before P2. Therefore, P0 gets another turn before P2, which only arrived at time 4. After P0 gets its next time quantum, then P2, which has been waiting since time 4, finally gets its turn to run. The Round Robin scheduler prioritises the order in which processes entered the queue, which explains why P0 runs again before P2 at that point. Thanks @SimpleSnippets
Am I mistaken or there's a slight incorrect approach in the video as in step 2. all the bits should be taken for xor operation whereas, you are taking first 8 bits.. I need enlightenment)
While solving for 202 in second iteration I got 10 and at the 3rd iteration I got 20, by 1 and 3 iteration by adding it will be 202 I guess but what about that 10?? at the second iteration
Is it only for web developers bcoz I just created my acc and I'm not a web developers or i doesn't know any coding am i eligible for this freelancing 😮
Super learning project tutorial. Post seperate video how publish and deploy the localhost for dynamic web application project. and also add usingy crytal reports application for report view..
From East Africa.......I really appreciate your efforts bro 🤜🤛...I'm in love with this series ...it teaches me a lot in my self teaching Software development journey✌✌✌...God bless you 🙏🙏🙏
Thanks so much for this lecture. It's one of the best I've seen. It really helps me understand how to convert infix to postfix expressions using the stack data structure.
for those still struggling to get a deeper understanding, hopefully it being expanded can help; x = x + y y = x - y x = x - y is really x = x+y therefore, with substitution y = (x+y)-y = y and x = (x+y) - ((x+y)-y) = (x+y) - ((x)) = (x+y) - x = y its taking the fact that if we turned one of the values into a sum of both, we can always get that information back by subtracting by the other variable, and vice versa x+y-y=x x+y-x=y so once we change x into x+y, we can set y to the same but with it being subtracted by the value it's storying, so we get x = x + y y = x which since it works vice versa, we can do the same operation like it never changed since the last state, only switched, subtracting x by the y
