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Nice video. Try making sure your drawings are constrained. This will help your drawing act or move in a predicated way whenever you want to adjust dimensions. Makes your drawing not get distorted after few changes are made to the dimensions.
thank you so much for this video. your explanation is so good! thx for helping me with my assignment. now I've come to understand this topic more and more🙏🙏
you doing completely wrong. you should learn yourself how to make it 3d models. you don't close drawing, like circles you should draw all of them and then you apply all what you need. and not the way you do it.
7:37 where b=2R√2 If you solve disregarding R: a²+ a² = b² b= a√2 in bcc Then go ahead solving the longer main Triangle. a² +b² =c² a² + (a√2 )² = (4R)²
I’m thankful you understand Yes, cos = adj/hyp In the triangle, I labeled my hyp (a) and my Adj was (height h). That’s where the misunderstanding came in. a = length of unit cell, not adj h= height not hyp In my diagram and calculation
@user-op5fm4pk3u -z origin is up, so when I travel negative direction I go downwards (on or in the cube)…… imagine I chose down as origin when I have -z , I’ll trace a line down outside the cube… which isn’t wrong, just best to do thing in the cube
because the angle 20 is part of the ( a ) angle the whole angle ( a ) = 35.9167 but we only need the angle that is in the positive direction of the x axis to determine the direction of the R
Why are -1 always =0? Does it mean that the coordinate ststem centre is in the centre of the cube? And that the cube measurements are not 1x1x1 unit, but 2x2x2 units?
