Simply brilliant! Ive seen many Chemistry Olympiad/ IIT JEE coaches in India actually give a more circuitous explanation on this. Thank you for your insights, I hope you keep sharing them with us!
Thank you! To clarify core electrons mean that the valence shell is full correct? While valence electrons mean they are in a shell that is not yet full?
Hi! I just purchased your book and I'm excited to learn this way to solve problems. I was doing this practice question and I couldn't figure out how to break the units open. Could you please demonstrate how to in this problem? Thank you for your help in advance. What is the energy of the photons) emitted by the LED at the frequency of 610 THz? (Note: h= 6.6 x 10^-34 J*s) and the answer choices are in J.
First, thank you for watching the video! Second, thank you for purchasing the book; it'll be a game changer on MCAT! As far as solving for the question you posted: since Planck's constant already has the J you need in the answer and we just need to cancel the s out, start by converting 610 THz to 610x10^-12 Hz, and then Hz breaks open into 1/s giving 610x10^-12 1/s which should be written as 610x10^-12/s (610x10^-12 in the numerator and s in the denominator). Now, dimensional analysis: 6.6x10^-34 Js • 610x10^-12/s The s will cancel out leaving only J, so then multiply 6.6x10^-34 times 610x10^-12 to get 4026x10^-22 J, and if the answers are in exact scientific notation, then move the decimal to the left 3 places to get 4.026x10^-19 J. I used calculator cuz I'm lazy tonight, but you'll learn some math-without-calculator and rounding tricks in the book.
If you'd like to see an image of the work I described above, simply email the question to inquiry@praxisacademic.com, and I'll send it... unless you know how to post images in replies here... lol... I don't.
@@PraxisAcademic Thank you so much for taking the time to write this all out! I will be emailing you for the image. I kept getting confused as to why the exponent came out to -22. I thought when you multiply in scientific notation, you add the exponents. So -34 + -12 = -46 not -22 but then I realized Tera is positive 12 not -12. I definitely need math-without-calculator tricks, I had no idea how to multiply 6.6 by 610 any quicker than using lattice lol. Thank you again.
Thank You for pointing that out. I forgot to dash-out one bond on each of the O atoms to show resonance in the nitro, and there's not way of editing it now. I did include the correction in the description. Thank You for watching! And thanks for the feedback!
Thank you for teaching this in a way that doesn't require a masters degree in quantum physics, no one knows how to teach people that have practically no prior knowledge.
Here's one more trick.....if the central atom of the attached group has a lone pair it is ortho para directing but if it has a pi bond then it is a meta directing 😅 hope it helps 😊
I am glad this helped. I hope it helps on more BP-VP Qs... they can be a bit tricky on MCAT. I appreciate your feedback; all my videos, except Significant Figures... lol... are MCAT and DAT geared! Thanks for watching!
True... cyclooctatetraene predominantly exists as tub-shape due to its irregular bond lengths, however, I intended to show its planar transition state between its tub-shapes which is antiaromatic. I showed its antiaromatic state because that's how they usually show it on DAT or MCAT. If they were to show the 3D tub-shape, then indeed it would be nonaromatic. Thank You for watching!
Atmospheric (gas) pressure is constant (ie: 1atm at sea level). The vapor pressure of liquids and solids are lower than atmospheric pressure (solids are lowest). When the surface molecules of a liquid or solid reach 1atm, usually due to temperature increase, the surface molecules of the liquid or solid will become gaseous. Liquids or solids reaching 1atm does not cancel out atmospheric pressure since that is constant (cannot be changed); liquid or solid molecules that reach 1atm vaporize into gas molecules--think of this as, if gases have a vapor pressure of 1atm, then any liquid or solid that obtains a vapor pressure of 1atm will become one with the atmosphere gas.
I was unable to understand these things before watching this video... And you made it such a way... Wow i don't have words to express how i feel now!!! Thank you so much!!!❤
