That is confusing.

You should change 16 to 2 power 4. Then answer will be more simple (just root of two)

(X^15)+(x^10)=36 (x^15)+(x^10)=27+9=3^3+3^2 If X^15=27=3^3 X=(3^3)^(1/15) =(3)^(3/15) =3^(1/5) If X^10=9=3^2 X=(3^2)^(1/10)=3^(2/10) =3^(1/5) ^=read as to the power The above method may n't be accepted due to the ethical error of mathematics

Inaccurate calculation. X= to cube root of 6

Golden Ratio problem. Divide the given equation by 4^x and rearrange to [(5/2)^x]^2-(5/2)^x-1=0. Substitute Φ=(5/2)^x to obtain Φ^2-Φ-1=0, which has real root Φ=(√5+1)/2. Thus, x=lnΦ/ln(5/2)=0.5252....

Appears incorrect. If you plug the final value x=3/2 into the first equation you get (3/2^3/2)^6 which does not equal 144.

Also, using the base 10 log, we can simplify with log(0.1)=-1.

Instead of dividing by 100^x, one could simply recognize that 1^x = 1.

Was this from the Math Olympiad?

Cool video but why were there children crying sound in the background

At a quick glance. 5 * 5 * 5 = 125 and 5 * 5 = 25 then 125 - 25 = 100 and x= 5.

Question is wrong

x must be between 0 and 1, 0 gives too much, 2 > 1, but 1 + 10 is already less than 100. o you found the exact answer in terms of sqrt and ln, very good.

I might be dumb but how does 10 to the power of 4 = 100 to the power of 4

x=7 X3+x = 7³ +7 =343+7= 350

worst math video ever? He solves correctly a interesting problem, and then, at end of the video, solves a very simple program, also correctly.

I was not gonna watch, but then I saw someone write ‘x is not 4’ in the comments. Then I had to watch how in the world you could answer as 4. If you like your career, remove the video. If this is a prank, it is not funny. If you are doing this to get views, you suck.

Lol your answer x = 4 doesn't satisfy the equation. (I only watched the ending.) Solution: 1^x = 1 for any real x. Let a = 8^x. Then, 64^x = a^2. The equation becomes 1 + a = a^2. Solutions are a = - sqrt(5) / 2 + 1/2 and a = sqrt(5) / 2 + 1 / 2. Since 8^x can't be negative for any real x, a must be sqrt(5) / 2 + 1 / 2. Then, x = log_8 (sqrt(5) / 2 + 1/2). This shouldn't take 11 minutes.

X =0.209

1^x + 8^x = 64^x 1^x + 8^x = 8^2x 1^x can 1 or -1, and used Y = 8x (1) Solve 1, if 1^x = 1 1 + Y = Y² 0 = Y² - Y - 1 0 = -Y (Y+1) ... Y= -1, and can't solve it, so it's not the answer (2) Solve 2, if 1^x = -1 -1 + Y = Y² 0 = Y² - Y + 1 0= (Y -4) (Y+3) Y = 4 Y = -3 Because the true is 1^x = -1, so we use Y = 4 8^x = 4 (2³)^x = 2² 2^3x = 2² 3x = 2 X= 2/3

x ist not equal to 4. 1+10^4 is not 100^4 . The correct answer is x = 0,209

You also could say, -log(term), instead if log base (0,1)(term) ;)

7

Nice video, now go pray salat is more important than math

X(x^2+1)=350=7×50= 7×(7^2+1). 則x=7

Very long methodology

A very funny solution and unnecessary because if x^3 -x^2-125+25=0 then x=5

5

You can directly write x³ -x² = 125 - 25 x³ - x² = 5³ - 5² Looking at this we can conlude that x = 5

Delta = 4^2 - 4*1*16 = 4 - 80 = -64. x^2+4x+20 = 0 x = (-4 +/- sqrt(-64)) /2, -64 = (8i)^2 x = (-4 + 8i) /2 or x = (-4 - 8i) /2 x = -2 + 4i or x = -2 - 4i. X is the complex number in the solutions.

Math Problem: 49ˣ - 42ˣ = 36ˣ; x = ? 36ˣ > 0; (49ˣ - 42ˣ)/36ˣ = (49/36)ˣ - (42/36)ˣ = (7/6)²ˣ - (7/6)ˣ = 1, (7/6)ˣ > 0 [(7/6)ˣ]² - (7/6)ˣ - 1 = 0, (7/6)ˣ = (1 + √5)/2 > 0; x = log₇⸝₆[(1 + √5)/2] = 3.1217 Answer check: 49ˣ - 42ˣ = 49³⸱¹²¹⁷ - 42³⸱¹²¹⁷ = 72162, 36ˣ = 36³⸱¹²¹⁷ = 72162; Confirmed The calculation was achieved on a smartphone with a standard calculator app Final answer: x = log₇⸝₆[(1 + √5)/2] = 3.1217

Первое уравнение должно иметь 9 корней. Решить уравнение означает найти его корни, включая комплексные, и догазать, что других корней не существует.

Thanks

At a quick a glance I rewrite this equation x^3 + x = 7^3 + 7 =350 and hence x = 7.

-> 1+(10/4)^x=(25/4)^x , (10/4)^2=100/16 -> 25/4 , let u=(10/4)^x , u^2=((10/4)^2)^2 , 1+u=u^2 , u^2-u-1=0 , x=((1+sqrt5)/2)/ln(5/2) , test , 4^((1+sqrt5)/2)/ln(5/2)+10^((1+sqrt5)/2)/ln(5/2)=5.42202 , 25^((1+sqrt5)/2)/ln(5/2)=5.42202 , same , OK ,

At a quick glance I solve this by rewriting the equation as 2^(3x) + 2^x = 2^3 + 2 then take logs the 3x * log(2) + x * log(2) = 3 * log(2) + log(2). dividing by lg(2) then 3x + x = 3 +1 and 4x = 4 then x = 1.Then 2^3 + 2 = 10.

If x=0, then 1+1=1. Please stop posting your wrong opinion

x=3 by inspection.

At a quick glance, x will be fractional

x = 5 is the solution among the real numbers.

One if the best.

😂😂😂😂😂😂😂😂😂😂😂😂😂

But u made it though bro check out my method , let me solve again and upload(done)

Ya 5

Подбором на 3-м шаге. То, что после - уже не нужно. Так и я решил. Это не математика, это угадайка.

x^3 + x = 350 x(x^2 +1) = 350 = 7 × 50 By comparison, x = 7 and x^2 = 50-1 = 49 Hence, x = 7

7 was the first number I tested haha

This is a polynomial equation, not an exponential.

Cool but like for this you basically just have to know the answer to the question from the beginning. Approaching this randomly without any information, you would have no clue to just randomly separate 350 into 343 and 7. If we knew from the beginning that x was an integer then yes it makes sense but idk if trial and error is really all that useful of an example. Also I'm sure you were just elaborating but beyond the x^3 - 7^3 + x - 7 = 0 step you really didn't need to do anything else as it should be obvious there are no other real solutions.

It is difficult to be solved if we can't figure out that 350= 7^3 + 7