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The Bald Chemistry Teacher
The Bald Chemistry Teacher
The Bald Chemistry Teacher
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@SpruceX
@SpruceX 23 часа назад
Youre the bomb yo
@SpruceX
@SpruceX 23 часа назад
Thanks boss ❤
@VaLy-zk5fv
@VaLy-zk5fv 11 дней назад
Its h²so⁴
@heywhatsupnerd.7793
@heywhatsupnerd.7793 15 дней назад
My savior
@Iamhonor-s2x
@Iamhonor-s2x Месяц назад
Thanks a bunch 😊
@monahassan1089
@monahassan1089 Месяц назад
Thanks
@Ariel-bz7hs
@Ariel-bz7hs 2 месяца назад
Why didn't you round up to whole number like you did in previous example of finding molar mass of a compound? Is there a rule of when you do or don't???
@ASHUTOSHKUMAR-oe7xx
@ASHUTOSHKUMAR-oe7xx 2 месяца назад
Great teacher , and so thankful to you sir , 🙏
@yukimonday
@yukimonday 2 месяца назад
There a much easier way than using fractions when given a question to find moles We know that 1 mole of carbon contains 12 grams of carbon So 2.5 mole of carbon contains , 12*2.5 grams of carbon = 30 grams of carbon
@AshuraBoxing
@AshuraBoxing 5 дней назад
That’s literally what he did😭🙏
@linesskatunga7739
@linesskatunga7739 2 месяца назад
This is easy than how we been taught
@Damnbro747
@Damnbro747 2 месяца назад
Why not just divive the mass by the Mr?
@misschaosxD
@misschaosxD 2 месяца назад
You are the only one to make me understand this! Thank you!
@SadekZiad
@SadekZiad 3 месяца назад
Yeah bro I’m cooked for this NYS regents today
@B760B
@B760B 3 месяца назад
I have my chemistry final in 10 minutes.
@SandaraPaera
@SandaraPaera 3 месяца назад
I learned a lot. You explained it in a very detailed manner. Thank you so much. This video is a gold.
@kalebbeley4687
@kalebbeley4687 3 месяца назад
Jesus Christ is Lord
@DerekIzzi
@DerekIzzi 3 месяца назад
I learned more from this video than I did in my high school chemistry class. Partly me and partly poor presentation methods.
@nechamalampert7705
@nechamalampert7705 3 месяца назад
Exam in 30 minutes my fingers are crossed
@kwingg
@kwingg 3 месяца назад
Dumbass i ain't doing alla that confusing the shit for no reason just divide 215.8g by 342.3 and you get the same answer Great video by the way❤
@sirp00per35
@sirp00per35 3 месяца назад
This really helped, thank you for this
@ur_adit
@ur_adit 4 месяца назад
how the heck are you so underrated
@محمدعليآلغبان-غ5ف
@محمدعليآلغبان-غ5ف 4 месяца назад
You better name your channel "Heisenberg".. 🗿
@Viablepride
@Viablepride 3 месяца назад
😂😂 that's right
@microwavedalmonds3363
@microwavedalmonds3363 4 месяца назад
This helped so much dude omg
@HuzaifaMalic
@HuzaifaMalic 4 месяца назад
Hi, Mam ! I Need Your Help In My Stoichiometry Problems. Please Gave Me Your Instagram Account, So That I Contact You !
@bluebarry5393
@bluebarry5393 4 месяца назад
My chem test is in 3 minutes and i don’t understand a thing
@cjracergaming1015
@cjracergaming1015 3 месяца назад
Did you pass?
@OrdenJust
@OrdenJust 5 месяцев назад
This is a really good explanation! What I am wondering about are some tables that I find in the CRC Handbook of Chemistry and Physics, 54th ed., (1973-1974) , that have the title "Gravimetric Factors and Their Logarithms." How do I make a correspondence between this table and what you just did? For example, the CRC table shows Weighed: Al (aluminum, of course) Sought: Al2O3 (aluminum oxide) Factor: 1.88946 Log of Factor +10: 10.27634 Reciprocal of Factor: 0.52925 Log of Reciprocal of Factor +10: 9.72366 Now, some calculation shows that the "Factor" is the ratio of the molecular weight of Al2O3 to the molecular weight of Al2. So that matches nicely with your explanation in the video. What I am wondering about is, why does this table go on to include "log of factor", "reciprocal of factor" and "log of reciprocal of factor"? These seem as if they are not needed for the sort of gravimetric analysis you demonstrated. Are these relics from the days before calculators when one had to do computations by hand?
@kashifyounus2926
@kashifyounus2926 5 месяцев назад
Keep it up!¡!!!!
@SyedMubarakOfficial
@SyedMubarakOfficial 5 месяцев назад
Mr Neil your video is good make more video you will earn a lot
@BocchiManga
@BocchiManga 5 месяцев назад
Me watching this after the test I Turned in blank
@ZChrist_jesus
@ZChrist_jesus 5 месяцев назад
wow u make it easy to understand ,thank u
@vanny10
@vanny10 5 месяцев назад
Thank you sm ❤
@vanny10
@vanny10 5 месяцев назад
Bro explained it better than my teacher for many class periods and every other RU-vid video in just one minute
@CheshireCat30
@CheshireCat30 5 месяцев назад
You explained 75 minutes of a lecture to me on 30 seconds, you’re a life saver🙏🏻🙏🏻🙏🏻
@gabrielmcpherson5756
@gabrielmcpherson5756 5 месяцев назад
Thank you so much sir. It is completely clear to me now.
@ericpark462
@ericpark462 5 месяцев назад
This is easy
@karlkrewneck1665
@karlkrewneck1665 6 месяцев назад
I’m so fucking cooked for this chemistry test y’all don’t even understand😭😭😭
@xanthostemoncandido1178
@xanthostemoncandido1178 5 месяцев назад
our exam in chemisty is literally a couple of hours away and im cramming my ass out rn
@leeknowyourlimits
@leeknowyourlimits 2 месяца назад
dang i hope u passed😭
@PardonNkandu
@PardonNkandu 6 месяцев назад
Thank you so much...i really needed this.
@Eunice828
@Eunice828 6 месяцев назад
Thank you so much for this
@danielmwikisa4920
@danielmwikisa4920 6 месяцев назад
Thank I needed this
@isaidcallmesusu-6323
@isaidcallmesusu-6323 6 месяцев назад
Exam in 1 hr and this is making me feel sm better
@mivineotnabab9669
@mivineotnabab9669 7 месяцев назад
Please make a video about titration method
@mivineotnabab9669
@mivineotnabab9669 7 месяцев назад
Please do titration method
@tysanameleo5633
@tysanameleo5633 7 месяцев назад
Thank you sir
@joeygonzalez6979
@joeygonzalez6979 7 месяцев назад
Keep up the Good Work Mr Neil love the videos
@mr.mafubeangamer2675
@mr.mafubeangamer2675 7 месяцев назад
You wrote it down as 36.5 but u say it’s 35.5? I also divided 35.5/71 but all I got was 0.5, when I tried it with 36.5 I got 0.514
@micahldean
@micahldean 6 месяцев назад
The problem says 36.5 moles, but he wrote 35.5 because that is the atomic mass of a Cl atom (in amu). And he put it over 71 because it’s Cl2 so you’d need to multiply the 35.5x2, which equals 71. Hope this helps!
@e.naomi17
@e.naomi17 7 месяцев назад
I have an exam tomorrow thank you
@nurveelanie1942
@nurveelanie1942 8 месяцев назад
3 hours before my exam😃☝️ and i don't understand why mole from C4H10 have to be multiplied with 8/2 to get 1.72 mol😭
@OntiretseMontshioagae
@OntiretseMontshioagae 6 месяцев назад
😂did you pass?
@atomic_girth_gamez3243
@atomic_girth_gamez3243 5 месяцев назад
🤣 ik this is way late but it's the ratio of moles Butane and moles CO2
@JeremiahJobin
@JeremiahJobin 3 месяца назад
its just a convention where you multiply the moles by a mole ratio
@MatthewVivanco
@MatthewVivanco 8 месяцев назад
Ay bro great vid
@muhammadabubakar8166
@muhammadabubakar8166 8 месяцев назад
Beautiful voice 😂😂
@AnnoyedChocolateStrawber-pd4dr
@AnnoyedChocolateStrawber-pd4dr 9 месяцев назад
Bring number of C4H10 by mass over molar mass than by stoichiometry n of C4H10=n of co2 than mass of co2 =n ×M