I found Sam,but it was because 5 like S,4 like A,9 becomes m by little modification, Then again 9 becomes S by some modifications,4 is A and 5 becomes m by mirroring the upper part.
When dying no one coul have enough energy to think like sherlock holmes even sherlock holmes himself this is not pure intelligence it's only combinaison between Word and numbers
0:50 Sherlock Holmes of 0iq the murder framed Sam why would the murder give the detectives a hint to find him? Because he wants to get arrested or something?
How can some one write with blood before his death ???? that clearly means he was tortured ..... And out of 3 friends no one noticed his screams ???? Is it logical ??
Kisi ke naam agar 3 akshar ke ho.. Aur koi banda, agar maar raha ho to uske dimag mein itne creative idea kaise aa sakta hai.. O simply uska naam likhega... Aur agar tum soch rahe ho, ke naam likhane per katil Naam Mita Sakta he,, ye soch ke usne number likha.. To jo katil Naam Mita sakta he, oo number kyun nahi Mita Sakta..
That man who is being murdered deserve it ....that idiot can plan that riddle rather writing the killers name and btw all the names and clues include just 3 .......such an idiot 😂
yeah, why would the killer literally confess what he did by telling the detectives who commited the murder? to entertain himself watching the police trying to solve it? I don’t think this was Moriarty....
you could find out who did it by looking at how big and how small it was written. If it had been written a little thicker and Sam had thin hands then we would know immediately that it was just a feint. One would have specialized in people in his environment: neighbors, friends or asked whether he had "enemies"
But if the Sam would have seen his name on the wall, he would have wiped it off clean, so the man had to write a code so Sam would think nothing of it.
Ok...each prisoner may switch on and off the light. Each prisoner has to switch the light ON and OFF on their FIRST visit and ignore on any subsequent visits. The prisoners must keep a tally of every on/off switch. The prisoner that enters the room after the 49th on/off light should say it to ensure every prisoner is set free.
It is not stated in the premise that a prisoner will be able to visit more than once. It is setup in such a way that it seems the prisoners will only appear in the room once, then never go back.
1. All of them 2. Jump from the lowest step 3. Didn't get that one 4. 9 and 0 5. 8lbs 6. Still 4 years 7. Broken clock 8. depends on the hemisphere 9. entropy in closed system 10. Tom
1. He was in a tunnel 2. C+S=1.10 C = S + 1 S+1 = 1.10 - S 2*S = .10 S = 0.05 C = 1.10 - 0.05 = 1.05 3. Empty 3g bucket into 5g bucket, fill 3g again and pour to 5g untill full - now you have 1g in 3g bucket, empty 5g - pour the 1g in and add 3g - now you have 4g in the 5bucket all in time, 2nd barely
Additional note to the solution: prisoners don't necessarily have to turn the light on during their first visit. If on their first visit the light is already on, they should remember to turn on the light later in one of their subsequent visits.
So they can see the light from their cells. At first i thought they couldnt which is harder and got a solution for that too. Also, the prisoner has to be inside the room to say that all the prisoners have already been to the room, which can take ages because the guard picks the prisoner randomly, so they can wait forever for that special prisoner to go to the room. i suggest this : 1) The prisoners must count the days. 2) if a prisoner walks in the room for the first time : if (the light is off and its past 50 days he says the magic sentence) else ( if the light is on he switches it off or if the light is off he ignores it). 3) if a prisoner walks in the room another time, he turns the light on or leaves it on if it is already on. this should work even if they cant see the light from their cells and doesnt need only one person to be in the room to save the rest.
Is it? For example if there has only been 30 prisoners in 49 days. And on 50th day theres new prisoner who turn off the light (because the prisoner before him is not new). The next prisoner on day 51(if he's new) would be wrong if he said the magic sentence even though it past 50 days, because there's only 32 prisoners (including him) that have been there.
Maybe what you mean is that 49 prisoners should turn the light on (when its off obviously) once, and only once for each prisoner. It doesn't necessarily has to be on their first visit. If on their first visit the light is already on, they should remember to turn on the light later in one of their subsequent visits. "...turn the light on when they get to the room for the first time and ignore it on their subsequent visits" I think you worded that wrong, just want to point that out.
