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you need to decide whether you need a calculator or not. Your screenshot shows "No Calculator" whereas your problem solution uses it. Good problem though.
I thought you were going to find k! (k factorial) :) . You could divide both sides of 5^x=50 by 25=5^2 to simplify the problem to 5^(x-2)=2. It would be easier to apply log base 5
In my head, 3<x<4, and 3 is much closer than 4. Using a calculator, try m= 3.2 - LHS is too low. m =3.3, LHS ~ 119. RHS ~ 119. Close enough. ... Us engineers are a crude bunch, aren't we?
the leap to introduce the index 1/18 isn't explained. a simple written "e.g." might have convinced me not to switch off. So as far as I am concerned: "case unproven".
@@BZKnowHow I'm sure it is all logical, and my education isn't sufficient to fill the gaps. My point was "never overestimate the comprehension of the general public". But maybe you have a more maths (sic) oriented audience in mind.
your verification part is nonsense. you cannot simply change the exponent on the left hand side from -0.5 to 2 just by magic while leaving the right hand side untouched... a = -0.5 is also not the right solution. just plug in a = - 0.5 in your calculator and try to get 4 as a result...
At 03:50, you need to include the ± sign: √(u²) = ±√121 Otherwise, your next line is: u = √121 You cannot insert ± in that line, if the line before it doesn't have the ± sign.
dear ...it was log 25 so i wrote it as log5^2 and as per rule we will bring exponent to the left side of log so it became 2 log5. I hope its clear now.
At 04:00, you wrote log x¹⁰ = 0 , which doesn't make sense to do -- why raised x to the 10th power, only to discard that in the next step? If you meant log₁₀(x) then use subscripts in the proper location.
