I am glad to hear that my video has helped you to understand how to add fractions with unlike denominators. My other math videos are available here: m.youtube.com/@MathEnabler Do watch them too and let me know your feedback on them. I hope they will be of help to you too!
I would like yo know from the honourable author whether you are adding or subtracting. I dont know much maths but it seems that you are addind. Correct me if i am wrong. I would like to learn from great mathematicians like you. Thanks
@@iamtheboneofmysword728clarification: we were indeed given tools to solve this at 13/14 but i doubt most sgporeans wld be able to solve this if you picked one out at random. but yeah maybe at most theyll ask us to find x^2 + y^2 from this in an exam question.
@friepima499 That's true, you probably wouldn't see a question like this in sec 1 so the average student may not be able to solve it. While I don't recall my sec 1-2 exams I know that there are similar questions in the earlier sections of O level papers, which are the easier ones that test sec 1-2 concepts. If you pick out a sec 1 student getting As for math which isn't difficult, they'd probably be able to solve this though
you can solve for x by getting y from the first formula, and using it in the second. I.d., x + y = 12 -> y = 12 - x | xy = 10 -> x(12 - x) = 10 -> 12x - x² - 10 =0 -> x ≈ 11.1 or x ≈ 0.9
A bike has 2 wheels, car has 4 wheels (2 more than 2). There are 7 total, which is a minimum of 14 wheels. There are 24 total wheels, and the difference is 10 ( 24 - 14 = 10 ) A car comes with 2 extra wheels, so < 10 / 2 = 5 >. There are 5 cars and 2 bikes in the car park
What do you mean adults cannot solve this. This is just basic 3rd grade math! And assumption method. Assume all are the greatest, multiply by total. Minus if total by actual total. Divide by difference And replace.
Thank you for your feedback. No offense, I hope. This video is to illustrate how to solve a 3rd-grade math question that has stumbled many adults. I am glad that you know how to solve it right away!
Hi, as the total number of pupils is also fixed (8 pupils) in the question, there is only one combination of the number of girls and number of boys for their sum of money to be $25 which is 5 girls and 3 boys. Thank you for your comments!
