Calculation of Alchohol by Kozelka hine method ...where Alchohol Value is 103 mg%W/V. I want to know the amount of solute out of what amount of solution...l mean base value of liquid in this case is 100ml Or whether it is 1000ml
Molality = moles/ weight of solvent (kg) Weight of solvent = weight of solution - weight of solute Weight of solvent = 500 g - 2 g Weight of solvent = 498 g Weight of solvent = 0.498 kg Moles of solute = weight of solute / molar mass Moles of solute = 2 g/ 40 g/mol Moles of solute = 0.05 mol Molality = 0.05 mol / 0.498 kg Molality = 0.10 mol/kg
