for option (b) I was thinking that sqrt of x- 2sqrtx*sqrty + y = sqrt of (root x + rooty) = sqrt x - sqrt y Hence (c). Please let me know if my method of solving is correct??
I gave my GRE (wrong ) ...I took my GRE ( correct ) How you managed that score without basic grammar rules attests that the GRE is not a measure of intelligence in math and language but how well one takes tests
1. Babble: chatter idly or foolishly (Bla Bla) 2. Badger: persuade by asking again and again ( Bad+gen) 3. Baffle: frustate, perplex (Buffolos perplex people with their crazy acts) 4. Bait: harass, tease/ used to capture fish 5. Bedizen: dress with vulgar (bad citizen) 5.
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Excellent work! Really enjoyed your videos and got a lot of useful information. I have a question about this particular problem: isn't option A incorrect, since the value of z can't be equal to 1 (with absolute value less than 1) and option A states that z^2 is less than 1 or EQUAL to 1?
Good observation Artur. In a way you are correct but for the sake of question , we can say that for all the values that z can take; Option A will hold true. Hence it is correct option.