This channel is for cambridge board students of A LEVEL, AS LEVEL AND IGCSE who wants to make their physics concept strong Full video solution of past papers is available on the channel
in question 4 b ii. isnt the curve of displacement negative sin. so velocity will be negative cosine. and I proportional to v so so current graph will be negative cosine?
Could you please explain How is the wavelength radiation too high sir? Bcoz l thought it is low since they said redshift was not corrected by student meaning not considered by student....
let say true value is 650 nm and observed value will be higher than that for redshift redshift correction means value should be lowered to write actual value and if it is not corrected means vale written by student is high i hope it will be clear to you
