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Barry Van Veen
Barry Van Veen
Barry Van Veen
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My All Signal Processing channel contains short lectures on topics in signal processing. Many of the lectures have also been used with an inverted or "flipped" classroom paradigm at the University of Wisconsin.

The playlists provide a systematic progression through the material. Each playlist includes a list of prerequisite playlists for understanding the background material.

Signals- The Basics
11:46
2 года назад
Matrix Completion
7:57
3 года назад
Network Graphs and Page Rank Algorithm
14:43
3 года назад
Principal Component Analysis
14:10
3 года назад
The Singular Value Decomposition
17:05
3 года назад
Low Rank Decompositions of Matrices
14:41
3 года назад
Geometry of the Squared Error Surface
19:18
3 года назад
Representing Data with Bases
15:10
3 года назад
Subspaces in Machine Learning
12:48
3 года назад
Patterns in Data and Outer Products
17:58
3 года назад
Комментарии
@jameshopkins3541
@jameshopkins3541 День назад
THERE ARE A LOT OF THIS TYPE OF UNUSEFUL VIDEOS
@andou_ryuu3205
@andou_ryuu3205 2 дня назад
I wish my professor even explained 10% of this as effectively
@jameshopkins3541
@jameshopkins3541 6 дней назад
SI no vas a explicar y demosrar nada. PARA q haces videos. PARA ganarvisitas. ?????
@jameshopkins3541
@jameshopkins3541 7 дней назад
AT LEAST USE SUBTITLE'S. DONT DOIT LIKE A SCHOOLKID
@jameshopkins3541
@jameshopkins3541 7 дней назад
I THINK IS UNUSEFUL TO TRY TO UNDERSTAND THIS EGIP
@jameshopkins3541
@jameshopkins3541 7 дней назад
DO IT IN PDF
@jameshopkins3541
@jameshopkins3541 7 дней назад
NOLIKE FOR UGLY KIDDING GRAPHICS
@jameshopkins3541
@jameshopkins3541 7 дней назад
REDOIT BUT WELL USING BIG IMAGES
@jameshopkins3541
@jameshopkins3541 7 дней назад
WHY NO EXAMPLE????????? BECAUSE IT DOESN WORK
@jameshopkins3541
@jameshopkins3541 7 дней назад
CAN YOU EXPLAIN SOMETHING ABOUT THE ALGOFFT????????
@ibissantananavarro7586
@ibissantananavarro7586 9 дней назад
Refresh long a go known thank you.
@tonyxu4310
@tonyxu4310 16 дней назад
It's really helpful for me, thanks!
@r410a8
@r410a8 25 дней назад
What is the formula of u[n] in 3:26 such the a variable's value determes the value of x[n] such a way in each case,i don't understand. And why in 4:36 when you aply the z transform formula on to x[n] you write Sum n-oo to +oo a^n*z^-n instead of Sum -oo to +oo a^n*u[n]*z^-n suposed the x[n] is a^n*u[n] not only a^n ? I don't understand this neither.
@abnereliberganzahernandez6337
@abnereliberganzahernandez6337 Месяц назад
you sck bro
@theoryandapplication7197
@theoryandapplication7197 Месяц назад
thanks sir
@bachkhoa1975
@bachkhoa1975 Месяц назад
This is a good overview of FFT. It would be nice to explain how the DFT convolution sum is derived. Also, the de-interlacing of the inputs was glossed over (not explained clearly) but only the reversed binary notation was mentioned (this is just an after-the-fact observation of How, not an explanation of Why). Readers who dive deeper into the splitting of a larger N-point FFT into two smaller N/2-point FFT’s, or understand the relationships between the twiddle factors (and their periodic nature) would understand and retain better the FFT technique (and be able to conquer any arbitrary size of N-point FFT (N being a power of 2, of course).
@jeevanraju8834
@jeevanraju8834 Месяц назад
your the best sir . thanks it really helpedfor my exam :)
@smesui1799
@smesui1799 Месяц назад
Excellent !
@VolumetricTerrain-hz7ci
@VolumetricTerrain-hz7ci Месяц назад
There are unknown way to visualize subspace, or vector spaces. You can stretching the width of the x axis, for example, in the right line of a 3d stereo image, and also get depth, as shown below. L R |____| |______| TIP: To get the 3d depth, close one eye and focus on either left or right line, and then open it. This because the z axis uses x to get depth. Which means that you can get double depth to the image.... 4d depth??? :O p.s You're good teacher!
@PankajSingh-dc2qp
@PankajSingh-dc2qp Месяц назад
PFE @6:50 is wrong. The residues are 6/5 and 4/5.
@PankajSingh-dc2qp
@PankajSingh-dc2qp Месяц назад
@ 3:50 the direction of the vector is wrong... it should be in the opposite direction
@PankajSingh-dc2qp
@PankajSingh-dc2qp Месяц назад
@ 1:11 the product in pole-zero form should start from k=1.
@adrenochromeaddict4232
@adrenochromeaddict4232 Месяц назад
great video. short, straight to the point
@eng.ameeryaseen1602
@eng.ameeryaseen1602 Месяц назад
plz.can you support my (what is the conditions of the linearity in phase for FIR filters. Enhance your answer with formulas)
@ONoesBird
@ONoesBird 2 месяца назад
Beautiful explanation! Loved it.
@tuongnguyen9391
@tuongnguyen9391 2 месяца назад
Why the link to all signal processing has die
@kottapallisaiswaroop9849
@kottapallisaiswaroop9849 2 месяца назад
Could you please make a video on Fast Iterative shrinkage threshold Algorithm and denoise an audio signal using it.
@ushamemoriya5391
@ushamemoriya5391 2 месяца назад
Consider an at rest linear system described by y"+25y=2sint+5cos 5t The response of this system will be Decaying oscillations in time. Oscillatory in time. Growing oscillations in time: None of the above.
@user-xk5rx9xe6w
@user-xk5rx9xe6w 2 месяца назад
15:33 ♡♡
@user-on4yf8tj1c
@user-on4yf8tj1c 2 месяца назад
Hello, I need help clarifying two concepts. First, 4:31 makes perfect sense to me. We're just using the definition of Euler's Identity; if we wanted to re-expand back to regular Acos(x) + Aisin(x) notation, and our function didn't have an imaginary component, the second term would go to zero. I.e., I can represent any sinusoid with Euler - even if it doesn't have an imaginary component. This is nice because we can break up our sinusoid into time dependent & independent components. This makes perfect sense. Then, at 4:57 we seem to transition into something completely different. I understand the math for both, but I don't understand why I would use 4:57 over 4:31? What was wrong with just using Euler's Identity like 4:31? For example, at 7:59 I could have just as well used Euler's Identity like done at 4:31 instead of using this cos definition. Could you please help me connect these two ideas? Thank you, sir.
@komuna5984
@komuna5984 3 месяца назад
Thanks a lot for this awesome content!
@mrtoast244
@mrtoast244 3 месяца назад
This video is so underrated, it's literally the most straight forward explanation of this topic I've seen
@georgyurumov8095
@georgyurumov8095 3 месяца назад
Brilliant thank you you
@AlexAlex-fo9gt
@AlexAlex-fo9gt 4 месяца назад
4:35-5:40 In my calculation of DFT X[2]=-1, not 0. Is the picture of DFM 7:36 right?
@tomoliveri6251
@tomoliveri6251 4 месяца назад
I know some of these words
@gynxrm2237
@gynxrm2237 4 месяца назад
the best i have watched so far..
@paedrufernando2351
@paedrufernando2351 4 месяца назад
will it be online?I could attend online as I am based out of India
@PikaGMS
@PikaGMS 4 месяца назад
i just want to say that i love you man
@mariacedeno3068
@mariacedeno3068 4 месяца назад
this is great :) Thanks!!
@HKHasty
@HKHasty 4 месяца назад
Awesome channel! Really helping me through advanced DSP!
@Net_Flux
@Net_Flux 4 месяца назад
Not sure why you left out the recursive relation between the odd and even functions and the DFT. I was so confused where the speed gain was from.
@jimmy21584
@jimmy21584 5 месяцев назад
Came here because I’m reading the LoRA LLM paper. Thank you for the clear summary!
@user-wg7hu6xe1z
@user-wg7hu6xe1z 5 месяцев назад
after we get the optimized w, how to get the optimized b?
@user-hk7nf5gt4b
@user-hk7nf5gt4b 5 месяцев назад
On advantage of the DTFT is its ability to provide greater frequency resolution with a single dominant frequency than the DFT for a given N. One application could be trying to use a dsp to accurately estimate the frequency of a guitar string for tuning to the proper pitch. We wouldn't want our tuner to be limited to only 1/T. Also, the small battery powered DSP cannot do an very large FFT for more resolution. Can you derive or simulate the resolution enhancement limits with the W(e(-jw) convolution?
@user-hk7nf5gt4b
@user-hk7nf5gt4b 5 месяцев назад
One advantage of the DTFT is you get a continuous frequency domain. With a single dominating frequency, the peak frequency can be resolved with higher resolution than with the DFT with frequency samples of 1/T. Can you calculate or show a simulation of the limiting resolution of DTFT over the DFT based on your convolution of W(e^jw) factor? Give the same N.
@tuongnguyen9391
@tuongnguyen9391 5 месяцев назад
WHat happen to the website
@josecarlosribeiro3628
@josecarlosribeiro3628 6 месяцев назад
Congratulations Professor Van Veen for your ability and beautful presentation! Mary Christmans nas Happy New Year! Gos bless you! Jacareí -Sao Paulo-Brasil
@ajingolk7716
@ajingolk7716 6 месяцев назад
In the equation of 3rd order filter pll something called pole and zero pop up what are they? Thank you
@ZatoichiRCS
@ZatoichiRCS 6 месяцев назад
This video had so much potential but glossed over so so much.
@RajivSambasivan
@RajivSambasivan 6 месяцев назад
Awsome - thanks for putting this up.