Great explanation. Thank you!!

Thank you Dr for this free knowledge. @ time 27:40 of the video, would appreciate if the drawing could be well simplified in plan form. Thanks sir.

Hello Dr am from East East Africa, Ethiopia. I really appreciate ur tutorial. Since as we now there are different adopted code on Rcc Design for instance in our country we are Using EBCS=CES ( which is similar to Euro code) ,so the design parameters and factors are varied. Bytheway when I was in university, I was taught by Indian teachers such as Dr. Vikas anyhow If u have willing to communicate with me please forward ur spread sheat

Sir, please can you share ur power point

For punching shear the critical section lies at 0.5d from face of column whereas you took 1.5d.Why?

Doctor thank you very much for all the videos on reinforced concrete design But in this exam I tried to determine the maximum moment by getting the area from shear force diagram and got it to be over 600kNm

Do you have any videos on a cantilever joined to a slab?

good day sir! I just want to ask how do we analyze the load transfer if the beam is curved along the horizontal plane?

Love the new sound

Please do a video on inelastic zone length of fully plastic beam under a point load

Please do a video on inelastic zone length of fully plastic beam under a point load

Hello brother can you try sharing the excel sheet again

The most important thing is to keep the most important thing, the most important thing, and that is the "foundation"

hello doctor, thank you for this. I do not understand why we can't in the case you cover for the collapse load, just find the load that will create a full plastic moment at the section of maximum moment. We know the moment diagram, and we know the value of the plastic modulus. So we can find the load that will causes Mp in the section. Max moment at the point load = 0.25*Wc*0.75*L = 0.1875*Wc*L (simple statics). Plastic moment Mp = Fy * Z, therefore collapse load Wc = Fy*Z/(0.1875*L). Is this correct? thanks. I just realized this gives the same result, as 1/01875 = 5.3333

Greatest teacher ever.....he keeps repeating thing till u get it

سهل ممتنع ❤

How did you calculate the maximum area of reinforcement in member when you where checking for cracking

Hello Doctor? Please your email address for good use; for questions about structural designs. Thanks.

Hollo Doctor? Help me how to get drift limit for BS8110 for factored loads because in part 2 of BS8110 gives for unfactored loads only Thanks.

Very excellent presentation thank you very much

Thank you very much this is excellent work and is very helpful

excellent video. is there any chance to have access to the powerpoint file?

Amazing 🇧🇩

this was very helpful. thank you

great explanation Sir, but it's unfortunate that Torsional moment is not considered in codes

Please, how did you get 523mm^2? 10:29

Thank you for your good and excellent work. very helpfull

Very excellent explanation and illustration. Thank you very much and continue with this good work.

Dr. El-Gamal, why are the loads w acting on the short and long beam of the two-way slab are both n x Lx/2 (for both triangular and trapezoidal area)?

thank you

شكراً جزيلاً وجعله الله في ميزان حسناتك اتمنى تشرح باقي البلاطات بجميع انواعها وباقي المواضيع الموجودة في كتاب نديم حسون

Hi Dr. Can i know. Why at some other book have 0.617d

Thankyou ❤❤

10xs

Salam Dr Sharif, could we have a video on structural design for strip foundation under a brick (9 inch) load bearing walls , I am your brother from Iraq, many thanks.

Great explanation thank you but please show the formula for required reinforcement.

This is such an informative and well explained presentation. Thank you so much Prof, you have saved my entire semester.

thank so much for coming back my lecturer God bless you

I dont understand how do they assume the value of -100 in sway, do we need to calculate or not from anywhere. Can we assume it also 500, 600...or only it should be less than or equal to 100

I have a question if you don't mind? In example 4: where did you get that there are 3 independent mechanisms? Nubmer of possibe hinges n = 3 Degree of redundancy r = 4-3 =1 Number of independent mechanisms = n-r = 3-1 = 2 Number of hinges for total collapse = r+1 = 1+1 = 2

شكرا لك دكتور شريف... و اذا امكن بالنسبة لاتجاه القصير ما هي اقصر مسافة يمكن استخدامها في البلاطة المصمتة ذات الاتجاهين

Hope to continue learning everyday

Hi sir, what's the factor 0.45 and 0.95?

well explained thank you

very clear and great teaching skills.