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MathTheBeautiful
MathTheBeautiful
MathTheBeautiful
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MathTheBeautiful is devoted to topics in mathematics ranging from High School Algebra to advanced subjects such as Linear Algebra,
The Torsion of a Curve
16:50
Месяц назад
Linear Decomposition by the Dot Product
19:33
3 месяца назад
The Arc Length Parameterization
14:17
3 месяца назад
Kinematic Analysis of a Rigid Bar
11:57
3 месяца назад
The Properties of Vector Differentiation
14:20
4 месяца назад
Комментарии
@Sachdev23
@Sachdev23 2 дня назад
I finished it!!! On my way to part 4. What a blessing to be able to learn from someone like you.
@MathTheBeautiful
@MathTheBeautiful День назад
Way to go! And thank you!
@chet-i9i
@chet-i9i 3 дня назад
I am an old guy with a lot of formal technical education behind me. I have found minimally three qualities in great teachers: knowledge of the subject matter, ability to communicate at several levels but most importantly enthusiasm. All three qualities are in this series.
@MathTheBeautiful
@MathTheBeautiful 3 дня назад
Thank you for the kind words, it means a lot!
@Sachdev23
@Sachdev23 3 дня назад
Just one word for this lecture. Beautiful
@MathTheBeautiful
@MathTheBeautiful 3 дня назад
Thank you!
@Sachdev23
@Sachdev23 3 дня назад
eureka moment when you talked about the matrix between Alpha_tranpose and alpha. It feels like a movie. Amazing!!
@MathTheBeautiful
@MathTheBeautiful 3 дня назад
Thank you! I often feel that exploring math is like watching a movie?
@Sachdev23
@Sachdev23 3 дня назад
Finally after 3-4 re-watches and practice it made sense. You were explaining it very simply i don't know why i confused myself. Great lecture actually! Thank you
@MathTheBeautiful
@MathTheBeautiful 2 дня назад
This one takes a while to get used to.
@mahmoudalaa4924
@mahmoudalaa4924 3 дня назад
These lectures are very similar to Vector Calculus lectures or am i wrong ?
@MathTheBeautiful
@MathTheBeautiful 3 дня назад
Yes, but by a slightly older and wiser individual.
@Sachdev23
@Sachdev23 4 дня назад
For someone who may have hard time understanding how (3a-b) in B was converted in (3a-b) in standard basis (I'll call standard basis set as E {e1, e2, e3}). Let me give a simple algebraic equation. Now initially a = [7, 2, 0]^T (^T to denote that its column) Or you can say a = 7*e1 + 2*e2 + 3*e3 (e_i is a column vector)....... (Equation 1) And when we wrote a in B we got a = [0,1,0]^T Or you can say a = 0*b1 + 1*b2 + 0*b3 (again b_i is column vector as the prof. Wrote in the video).......... (Equation 2) Now since both a are numerically same, we can say from equation 1 and 2 : a = 7*e1 + 2*e2 + 3*e3 = 0*b1 + 1*b2 + 0*b3 Or in matrix term: E * [7,2,0]^T = B * [0,1,0]^T Here E is standard basis matrix and B is new basis matrix So it becomes very clear that multiplying B with a in B (which was [0,1,0]^T) will return a in standard basis I know it was very obvious, the whole reason i did that in matrix form was to make it apparent that it only works of E is standard basis. If E is some other matrix (not Indentity i mean) then we will have to multiply with the E inverse to get the original coordinate (i.e. coordinates of vector a in previous E). I don't know if it's worth exploring or not.
@Sachdev23
@Sachdev23 4 дня назад
No messi at 11:51 😩
@MathTheBeautiful
@MathTheBeautiful 4 дня назад
My apologies!
@Sachdev23
@Sachdev23 5 дней назад
In all the 200 lectures that I watched, this was super confusing. I mean what if v is not in the column space of X inverse, how can you take X_inverse * u = v as a generalised form, this doesn't feel right, what am I missing? That means X can't be arbitrary right? But in the beginning you said take arbitrary X that is invertible. It's very confusing.
@Sachdev23
@Sachdev23 6 дней назад
Finished deterninant series, been binge watching your lectures. Series 2 was simple and complete. Does this part cover everything in linear algebra or did you exclude some topics?
@MathTheBeautiful
@MathTheBeautiful 6 дней назад
I cover the three pillars: linear spaces, linear transformation, and inner products.
@Sachdev23
@Sachdev23 6 дней назад
Praiseworthy intro! Finished part 1, now gonna finish this determinant series.
@MathTheBeautiful
@MathTheBeautiful 6 дней назад
Enjoy!
@Romulo_Cunha
@Romulo_Cunha 7 дней назад
where can I find the proof for that? I searched on the internet and i can't find a general proof for the sum of rows as a constant implying it is an eigenvalue. Thank you in advance.
@MathTheBeautiful
@MathTheBeautiful 6 дней назад
The proof is that if A*[1 1 1 1 1] = [ 7 7 7 7 7], then 7 is an eigenvalue and [1 1 1 1 1] is the corresponding eigenvector.
@electric_sand
@electric_sand 7 дней назад
Whenever Dr. Grinfeld speaks on a topic, you know your search for explanations is at an end. One of the few educators I know to shed light on the seemingly trivial underpinnings behind ideas. The type of teacher whose students are always different (in a good way), you feel you are actually learning the ideas behind mathematics itself.
@MathTheBeautiful
@MathTheBeautiful 6 дней назад
Thank you for the kind words!
@sm-pz8er
@sm-pz8er 9 дней назад
Perfect
@clevergyan
@clevergyan 9 дней назад
Such a shame that this channel is not popular, every video on this channel is worth so much, I can't thank you enough, I wish I had money to help support this channel
@MathTheBeautiful
@MathTheBeautiful 8 дней назад
Thank you - that means a lot!
@Pluralist
@Pluralist 9 дней назад
@pacchutubu
@pacchutubu 12 дней назад
Thanks for the great lectures. I have a question w.r.t covariant derivative of a Tensor with one index, w.r.t alpha. In addition to the two usual terms, does it have a term with normal vector component? Since Christoffel symbol resolves vectors only in tangential plane.
@MathTheBeautiful
@MathTheBeautiful 12 дней назад
Thank you. I think I adress your question in a later video.
@boutiquemaths
@boutiquemaths 14 дней назад
"The word proof is not something I'm fond of..." - gosh it means so much to hear a mathematician say that. Thank you for these videos, came back a second time because the title was funny 😂
@brahmahum
@brahmahum 15 дней назад
Light years, my a..
@Burkard42
@Burkard42 15 дней назад
Danke!
@MathTheBeautiful
@MathTheBeautiful 14 дней назад
Thank you - much appreciated! -Pavel
@thevegg3275
@thevegg3275 15 дней назад
Thank you. So let’s see if I have it correct. Re a 2D curvilinear coordinate system. The Christoffel symbol Gamna with 3 indices. A and BC. A describes a choice of two vectors. Each of them being velocity vectors based on the point of intersection of longitudinal or latitude for sake of description. B and C describe the same velocity of vectors, each of which could be longitudinal or latitudinal. So with that I can now describe the Christoffel symbol as the rate of change of B with a small change in C in the A direction. An example of a Christoffel symbol has two values that describe the vector caused by parallel transport between B and C. Therefore, if this new vector pointed directly longitudinally, it would have zero for the latitude, no value. Does that sound correct? Thank you for your help!
@tonywang7933
@tonywang7933 15 дней назад
Thank you!!! That's so beautiful
@matthewsarsam8920
@matthewsarsam8920 18 дней назад
This new matrix isn’t unitary, but still represents the same exact transformation. So if I take a vector V in the old basis and use its components with the old matrix, and the same vector V in this new basis, the output will have different components but represent the same vector. So therefore length is preserved with respect to the new basis, but the matrix isn’t unitary. I guess the question is, if the matrix isn’t unitary, then it can’t preserve length with respect to an orthonormal basis. Please see if I’m on the right path here thank you
@MathTheBeautiful
@MathTheBeautiful 18 дней назад
You're asking the right questions but some things you're saying are not right. For instance, there's something wrong with the sentence "length is preserved with respect to the new basis" since the length is independent of the basis. Try separate the actual vectors and their geometric characteristics such as length from the component space representations.
@matthewsarsam8920
@matthewsarsam8920 18 дней назад
@@MathTheBeautiful I meant to say the length is preserved with respect to the components of the new basis. Hence if I was to take the dot product it would be invariant since the components transform plus the basis. Is what I’m saying about the unitary part correct?
@MathTheBeautiful
@MathTheBeautiful 18 дней назад
@@matthewsarsam8920 Still not quite clear to be honest. Tell me if this is helpful: the length of a vector in *not* given by √x₁y₁+x₂y₂. when the basis is not orthonormal.
@matthewsarsam8920
@matthewsarsam8920 18 дней назад
@@MathTheBeautiful I understand that. It would involve the metric for that new basis. I’m pretty much saying when u take the dot product in the new coordinates, you end up with an invariant expression since the coordinates and vectors scale oppositely. Im just trying to see how the unitary part comes in
@jayrashamiya2810
@jayrashamiya2810 20 дней назад
If you add the damping term, resonance does indeed occur even when the driving frequency is not exactly the same as the natural frequency of the system. Your equation models a system with "NO damping", which is called "very high Q" system. Indeed, higher the Q of your system, the closer your driving frequency has to be to cause resonance. If you plot the graph of steady state amplitude for the solution of damped equation, you can clearly observe the effect on resonance due to different damping parameters. This graph is quite common in physics classes or experiments.
@Andre-Linoge
@Andre-Linoge 23 дня назад
Holly Cow!
@ccbabu6326
@ccbabu6326 24 дня назад
Basic thoughts behind 'Determinants'. This is 'Root Learning' but not 'Rote Learning' ! Thanks alot!
@Onyabacklikeabooksack
@Onyabacklikeabooksack 25 дней назад
Meet Calcea Johnson and Ne'Kiya Jackson. These two young Black students are mathematical prodigies who attended St. Mary's Academy in New Orleans. They are history-making teens who solved and showed proof of the age-old math giant, the Pythagorean Theorem ( a² + b² = c²).May 6, 2024
@MathTheBeautiful
@MathTheBeautiful 20 дней назад
I would love to learn more about their proof!
@davidboettcher1900
@davidboettcher1900 27 дней назад
Excellent, very tight and clear, explanation, thanks!
@seola4365
@seola4365 27 дней назад
Well, now i don't feel that bad about calling it the Gram-Smith method 😪
@kingplunger6033
@kingplunger6033 28 дней назад
Is this the end of the series ?
@stevejohnston7501
@stevejohnston7501 28 дней назад
Thank you…that explanation was excellent!…and much needed on the net.
@danishfiraaz4057
@danishfiraaz4057 Месяц назад
beyblade x song
@matthewsarsam8920
@matthewsarsam8920 Месяц назад
So can I say a vector is a tensor with order 0, and the components are tensors with order 1? People keep telling me the vector has a rank of 1, which is confusing
@MathTheBeautiful
@MathTheBeautiful Месяц назад
You're exactly correct. People who tell you that a vector has rank 1 are referring to the components of the vector when they say "vector".
@TeslaTesla-c6i
@TeslaTesla-c6i Месяц назад
In support of @APaleDot’s comment: the dot product is a scalar function of vector arguments. And we can differentiate dot products.
@user-wg4cm6xl5x
@user-wg4cm6xl5x Месяц назад
Great lecture!
@jakubmichalak
@jakubmichalak Месяц назад
Masterclass
@manayelhanafi434
@manayelhanafi434 Месяц назад
Thank you sir ❤
@pacchutubu
@pacchutubu Месяц назад
Is there a video where above problems are solved using Tensors?
@mausplunder5313
@mausplunder5313 Месяц назад
the best lecture series out there for people starting to learn linear algebra. great concept building for a solid foundation to understand more complex problems. way better than the vast collection of calculation tutorials that just throw algorithm after algorithm at you. great work.
@MathTheBeautiful
@MathTheBeautiful Месяц назад
Thank you! (Also, your assessment is correct)
@safourashafie
@safourashafie Месяц назад
Thanks a lot dear professor , I just watched this lecture and I am struggling with sth I couldn't come up with, How can we prove that the RCT is related to the intrinsic properties of the surface?
@AbhigyanKeshav169
@AbhigyanKeshav169 Месяц назад
Helpful lecture
@EddieVBlueIsland
@EddieVBlueIsland Месяц назад
Well done Pavel
@MathTheBeautiful
@MathTheBeautiful Месяц назад
Thank you! Much appreciated!
@EddieVBlueIsland
@EddieVBlueIsland Месяц назад
Thanks!
@MathTheBeautiful
@MathTheBeautiful Месяц назад
It's a first!
@Fractured_Scholar
@Fractured_Scholar Месяц назад
Earlier in the series you mentioned that some of the geometry problems "become a joke" when we start solving solving them with vectors. Can we expect examples of that in the near future?
@MathTheBeautiful
@MathTheBeautiful Месяц назад
There are some in the past! This and the following four videos: ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-erqHJeEsMPc.html
@Fractured_Scholar
@Fractured_Scholar Месяц назад
@@MathTheBeautiful - Thank you kindly, sir.
@alegian7934
@alegian7934 Месяц назад
I've finished my MSc in Computer Science, and I watch these lectures out of interest, and they make me feel like a student again :D
@zubairkhan-en6ze
@zubairkhan-en6ze Месяц назад
Very few may understand the depth of these lectures..
@MathTheBeautiful
@MathTheBeautiful Месяц назад
I hope that's not true!
@zubairkhan-en6ze
@zubairkhan-en6ze Месяц назад
@@MathTheBeautiful I meant that if someone has read history of geometry, linear algebra, calculus of variation and then watch your lectures he will appreciate the depth of these lectures.