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Sorry, I'm confused. If x = 1, then wouldn't f(x) = 4(1-1)^2 = 0? Isn't the mode the highest value? So wouldn't x = 0 be the highest value because 4(1-0)^2 = 4 and f(x) decreases as x increases?
Thanks bro i am from india i saw the same answer in some another channel but i was having problems in the last step but now after watching from your channel i got crystal clear answer
Prove that the series Σ1/(n(n+1)) from 1 up to infinity converges and find its sum ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-818-X9fiMX4.html Watch the update
Prove that the series Σ1/((n+1)(n+2)) converges and find its sum ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-wwKRqfPzBjs.html This one too may be of help to you
Perhaps an easier way to solve it is by breaking the fraction into two parts: 6^x/2^x-2^x/2^x=8. This yields 3^x-1=8, which gets you to 3*x=9. which means x=2.
Nice points! In my imagination, I am intrigued by the idea of evaluating two RU-vidrs to compare the excellence of their content and who is better at math. PreMath vs Nikonta Papapaa. Also they should collaborate with each other. "When an unstoppable force meets an immovable object"
I thought this would be hard since I thought (9m^2 -12mn+4n^2) wasn't factorable. I didn't expect an extra letter in middle term and in the last term. 😅
I converted it to exponents right away. X^1/3 = (3X)^1/2 I raised each side to the 6th power. (X^1/3)^6 = [(3X)^1/2]^6 will yield X^2 = (3X)^3 X^2 = 27X^3 then you divide both sides by x^2 to yield 1 = 27X X = 1/27 I still remember the rules for exponents after all these years. Looks like my approach was different, but still yielded the answer.
6 is a common multiple of 2 and 3 so 6 times 1/2=3 and 6 times 1/3=2 This method is a bit more advanced And starters will find it difficult. That’s why I used the immediate approach
Check this one with more improved voice quality Prove that 1.2+2.3+3.4+…+n(n+1)=(n(n+1)(n+2))/3 using mathematical induction ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-XCXtzY0iHA8.html
