@@stevendovi Hi Steve there is a formulation of the Geometric distribution where this is true but note that is the count of failures whilst this formulation is for the number of trials till the first success.
Hi Boer, really appreciate the work you're doing! Know that you probably get it a lot from the commentors, but you really do teach better than my lecturers! Cheers Boer :)
I really appreciate your video and that you chose show us how to derive both parameters of the Gamma distribution. Especially deriving alpha. I have a stat question that involved finding the MLE of the Gamma distribution. Thanks.
Hi, since the since identity matrix multiplied by the other matrix that remains in that equation (the inverse of X transpose times X) itll just leave the XTX inverse behind with the Sigma squared in front
don't have the same result with this command for likelihood for negative exponential distribution: L1=dgamma(theta1,shape=n,rate=sum(x)) L.NEXP=function(x,theta){ n=length(x) s=sum(x) L=(theta^n)*exp(-theta*s) return(L) }