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Thanks for video/ I have an issue with this way of sorting though. Because, when the first field is sorted , second one is ignored/ For ex suppose there are two fields Age and name , & i intend to sort on age and name both. So if there are two entries with age 34, and name as Abhi and Nutan, I need Abhi to appear first in the list and then Nutan. How do I achieve this?
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I am getting below error can anyone help me with this WARN: HHH000181: No appropriate connection provider encountered, assuming application will be supplying connections Exception in thread "main" javax.persistence.PersistenceException: [PersistenceUnit: EclipseJPA] Unable to build EntityManagerFactory at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:914) at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:889) at org.hibernate.ejb.HibernatePersistence.createEntityManagerFactory(HibernatePersistence.java:56) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:63) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:47) at com.neeru.First_JPA_Maven.Student_Test.main(Student_Test.java:9) Caused by: org.hibernate.HibernateException: Connection cannot be null when 'hibernate.dialect' not set at org.hibernate.service.jdbc.dialect.internal.DialectFactoryImpl.determineDialect(DialectFactoryImpl.java:97) at org.hibernate.service.jdbc.dialect.internal.DialectFactoryImpl.buildDialect(DialectFactoryImpl.java:67) at org.hibernate.engine.jdbc.internal.JdbcServicesImpl.configure(JdbcServicesImpl.java:176) at org.hibernate.service.internal.StandardServiceRegistryImpl.configureService(StandardServiceRegistryImpl.java:75)
In the anonymous class, the compare method returns a value of type int but you return a value of type String(getname()), why isn't that an error?, where does the method compareTo come from it's not implemented anywhere in the classes
Excellent explanation. Adding to your video.. we can do something like below in java8 with multiple fields: listOfEmps.stream().sorted(Comparator.comparing(Employee::getEmpId).thenComparing(Employee::getEmpName)).forEach(System.out::println);
Whoa this is a lot simpler than the method I had found, though slightly less flexible. I think I'll use this way of sorting on multiple fields in the future for a lot of 'one-time' sorting jobs where I don't necessarily need to sort the data in a lot of different ways.
Is it in a separate video that you said the lambda representation for supplier is, for example () -> new User(1, "John")? I didn't see that in the previous examples in this video. I'm confused by the syntax (1, "John"). Please explain.
User has an id and a name, thus when creating the object it needs two arguments, the 1 is the id and "John" is the name, so basically you instantiate the User object only inside the suppliers get() method. Sorry if I misunderstood your comment.
I am confused here... I have a list of ranks.. and I like to display the highest rank first... The following ranks are as follows from highest to lowest: Super Sleuth, Master Detective, Senior Detective, Detective, Junior Detective etc... how would I do that?
