Wow mam, u cleared my big problem😅tq❤

Thanku Ma'am ❤

Thank you so much Ma'am 💗

I have always had doubts about this topic..but you made it crystal clear. Thank you mam...

maam u teach me very well tqsm its very helful

Thank you very much.

Thank you so much mam... really liked ur way of teaching

Maam your videos are very worth it... U are the BEST Plz do more content❤

Explained well

One small correction. Molality means No of moles of solute in 1 kg of solvent mam.but u mentioned 1 kg of solution mam.

great work

Tq so much mam

Wow…literally I have found the gem…concept was crystal clear !! Thank you so much mam❤

Excellent 🎉

Extraordinary teaching talent...Tq mam

Please start vedios again

Mam last ans. Alcl3 ka ans 1.8 araha he

Thank u😍

Superb explanation mam'm 🥰🤗 thnk uhh so much ...this video is helpful for me

Tq mam very well explain

Wow what a wonderful lecture? Thank you it helps me a lot

qn no17) bend shape and distorted tetrahedral

Great class !! It was really helpful!

Liked the teaching experience through illustrations

Awesome mam super Thankyou

Q10. ( gate 2007) the correct ans is option ( d) because in option d both the complex have d2sp3 hybridization but in option a the 1st one is sp3d2 and the other one is d2sp3...so please check it!!!

Superb mam

May I know where are you from ? Tamil Nad or North India? If you are from T.N then please post vidoes related to PG TRB exams. Thank you.

Hello, I am from Tamil Nadu. Your videos are good but I expect short tricks, exam point of view and different examples like Birch reduction of Heterocyclic compunds,ect. Thnak you. Please keep posting more vidoes.

Mam in pb no 17 ..why geometry is found using only quotient and lone pair is not taken

Thanks to you for a very neat, amazing presentation

Nice explanation madam

Very nice explanation Thank u mam

Thank you mam very nice explanation mam

Very good lecture!

Nice lecture mam 😍....make few more vedios for iit jam newly added topics mam...

really really helpful ma'am.... till now not sawn thiz much clear and patience explanation ma'am

Keep this good work going. Very Nice

It helps me a lot... Thank you so much mam

Mam pls upload full answer key

Thank you mam

No clear voice & questions are not visible ....

good

very Informative

good explaination for the questions, keep it up. Hope u will upload for other questions also.

Lot of thanks , keep it up ,excellent way of explaining hope you will upload solution of Remaining questions

Very well explained mam... really understood the concepts very clearly. Thankyou so much for the video 😇

Q.I'd 7720331196 option 1 or 2 is correct. I have doubt.

Madam Q.I'd: 7720331233 options 1 and are correct. According to relationship between H and G. Q.id: 7720331222 Anti log value didnot given Q.I'd:7720331204 Compound B easily from ozonide So option 3 is correct Q.I'd: 7720331206 Compound 4 form stable anion.So option 4 is correct. Q.I'd 7720331198 Ortho position is occupied by methyl group and para position is occupied by nitrogen atom. How claisen rearrangement is possible. Q.I'd 7720331184 Option 2 is possible. Option 4 is impossible. Q.I'd 7720331179 Cis isomer give one singlet and trans isomer give one singlet. So option 2 is correct. Q.I'd 7720331153 Options 1 and 3 are correct. Because ethanol and acetone give acetoform test Q.id 7720331149 Due to resonance and steric crowding compound b and C has low basicity. So option 1 is correct. Q.I'd.7720331155. In compound A no mention the node points. Q.I'd.7720331161 Options 2 and 3 give six signals Q.I'd 772031136 cyanide is strong ligand so rate of dehydration is difficult. Option 3 also correct. Can you suggest to CSIR about this corrections?