The "s" quantum number is not often taught in general chemistry because s=1/2 for every electron. But this quantum number is taught in inorganic or quantum chemistry. "m_s" is to "s" as "m_l" to "l".
Good one. I have query that how to find ground state energy of any molecule with excellent accuracy? Is SPE is nothing but ground state energy? Can you please clarify? Thanks @physicalchemistry_pchem
The single-point energy is the electronic energy + the nucleus-nucleus repulsion calculated at the given atomic structure (usually from the user's input). The electronic energy is the sum of the kinetic energy of the electrons, the electron-electron repulsion, and the nucleus-electron attraction. If you aim to get the ground state energy (assuming at the equilibrium structure), a geometry optimization calculation must be carried out.
Hi, thank you for the very helpful and needed tutorial! I just wanted to let you know you actually need a 7mm nut driver for the glovebox nuts (you have a different size in the video description)
Thank you so much for the video. It only took a minute or so to replace the blade after watching it. I see you can buy an official Subaru replacement blade online directly from Subaru-- Replaces Part Number: 86548XA09A, 86542AG09A, SOA591U314R, SOA591R514, 86542AG080 currently $11.50. That is a safe purchase! Walmart has it for the same price online but a review indicated an installation problem "This sensor does NOT have the connector included - it needs to be CUT and SPLICED. No where in the description does it mention that fact!! I would never cut and splice one of these units - it opens the door for more problems down the line and more than likely need replacing - especially being exposed to water and weather under the vehicle."
For example, assuming that the enthalpy of fusion of two chemicals A and B are 25 and 35 kJ/mol, respectively, and that the melting points of these two pure chemicals are 420 and 480 K, respectively, you may type up the following request on the Wolfram Alpha page: Solve e^(25000/8.31446*(1/420-β))+e^(35000/8.31446*(1/480-β))=1 The result is β = 0.00245793 T_eutectic=(1 K)/β=(1 K)/0.00245793=406.846 K=407 K
Typical drain cleaner or clog remover contains only ~1% NaOH by mass, while we are using ~10% in the video. Kitchen granules or crystal lye drain opener contains 60-100% NaOH.
Hey sir , can I ask something about C-O bond length? Can we confirm [MnCo5(PF3)3 and [MnCo5(PPh3)3 ] complexes, what should will be expected to longer C-O bond . I know PF3 greater Pi acceptor and back bonding but I don’t know that the confirm these complexes about their length . Thanks for answer sir
The formulas look weird. Any typos? In general, when the transition metal center donates its d electrons to the pi* antibonding orbital of a CO ligand, it reduces the CO bond order and makes the CO bond longer. Now, I will let you compare PF3 and PPh3 yourself in their abilities to withdraw electrons from or donate electrons to the transition metal.
Transition Metal Complexation. Pi electrons of the alkene flow into the empty d orbitals of Rh; d electrons of Rh slows into the pi* antibonding orbital of the alkene.
Thank you for this video I had a flawless install. Once the hook is on you have to pull up hard until it clicks down into position then you flip the little plastic flap. If the j hook is not down all the way the flap wont close.
i have a question. I see values for 'gibbs energy of formation' and then i see values for the same species for 'gibbs energy of hydration or solvation' and 'enthalpy of hydration or solvation'. For my equations I am coming up with to explain my thesis work (and to calculate by free energy change which equations are most likely to occur), do I only need to use the 'gibbs energy of formation' values and not use the 'gibbs energy of hydration or solvation' and 'enthalpy of hydration or solvation' values (it was hinted to me that the 'gibbs energy of formation' values already account for hydration or solvation considerations so I may only need to use the the 'gibbs energy of formation' values). For example, some of my equations involves aqueous species: 2 Al(s or l) + 6 [OH]-(aq) + 6 H+(aq) → 2 Al(OH)3, (s, gibbsite) + 3 H2, (g) and 2 Al(s or l) + 6 [OH]-(aq) + 6 H3O+(aq) → 2 Al(OH)3, (s, gibbsite) + 3 H2, (g) + 6 H2O(l) and 2 Al(s or l) + 6 H2O(l) + 2 [OH]-(aq) → 2 [Al(OH)4 ]-(aq) + 3 H2(g). (i also can't find a literature value for gibbs energy for H3O+ ion)
The Gibbs energy of formation of a species is the Gibbs energy of this species relative to elements in their standard states at room temperature. The Gibbs energy of hydration is the Gibbs energy change in a solvation process. They are different concepts.
@@physicalchemistry_pchem yes thanks, i think i agree from what i stumbled across. this is a subsection of a chapter in my thesis which is why its not my cup of tea. i also found an online preprint paper called Thermodynamics of Hydronium, Zundel and Eigen ions that gave gibbs energy of formation of h3o+(aq) as -228kj/mol, close to that of water. this paper also has equations that get conventional standard gibbs energy of formation for aqueous h3o+ by plugging in all the other gibbs energies (gibbs solvation energy and gas phase gibbs energy and another) so i think this makes sense (and chatgpt was wrong as usual but also gave hints alluding to what might be correct)
