OK. So Arle has made a 103 CHAIN of puyo. And she reached 6 comets at the 49th chain. A comet equals 1440 nuisance puyos. 1440 x 6 = 8640. 49 X 2 =98, which is very close to 103 chains. 8640 x 2 = 17280. So let's just say that arle had dropped at least 17280 nuisance puyos. How many boards will you need to fit all these nuisance puyos? Let's see. The board is 12 x 6, which means that 72 puyos at max... 17280 ÷ 72 equals.... *240 BOARDS.* In other words, This chain will fill up AT LEAST 240 boards. [Keep in mind that Amitie has done some of her chains, so my calculations wouldn't be accurate, but c'mon, a 4 chain can't beat a chain in the triple digits] All we need now is a puyo puyo /math expert to tell us the exact amount of nuisance puyos arle sent. BAYOEN! BAYOEN! PAYOEN! PA YO EAN! PACK YOUR EARS!
Randomly decided to actually calculate the amount of nuisance dropped because I felt like it. Sorry the Puyo Puyo and math expert was a year late! - The amount of nuisance you send over to your opponent is (roughly) equal to [your score ÷ target points] - For this particular game, chains less than 20 don't send any nuisance at all. Therefore, the total nuisance sent = [(your score - scores from
