No of divisible by 2 =n(2)=450 No of divisible by 3=n(3)=300 No of divisible by5=n(5)=180 No of element divisible by (2and3)=150: No of elements divisible by(3and5)=60: No of elements divisible by(2and5)=90: No of elements divisible by(3and5)=60: No of element divisible by (2 and 3 and5)=30: According to set theory: Aubuc=n(A)+n(B)+n(c)-n(a and b)-n(b and c)-n(a and c)+n(a and b and c) 180+450+300+30-150-60-90=no divisivle by 2,3or5 660=no od divisible by 2,3,5 Not divisible by 2,3,5=900-660 240 numbers are not divisible by 2,3,5: It is a mixed concept of arithmetic progression and set theory
Sir ji aap best hai , mja aata hai aapse padh ke , mai pahle maths se darta tha aapse padhne ke baad aaj maths bnane me sabse jyada mja aata hai ❤️❤️😍😍😍🙏🙏
Sir aapne bahut hi achchi method batayi hai,aapke tricks se mujhe upsc ke csat paper ke questions mein bhi kafi help milti hai.Lucky to have teachers like you.
form 1-100 there are 26 no not divisible by 2,3 and 5 but by your method, the answer is 80/3 = 26.66 isko 26 bna dete h 0.66 kam form 1-200 there are 54 no not divisible by 2,3 and 5 but by your method, the answer is 160/3 = 53.33 isko 54 bna dete h 0.66 jayda kab kam krna h kab jayda kase pta kare ye bhi btana
Ratta lagakar baithe huye hain aur Maths ke teacher banne ka dhong karte hain...ghanta kuch nahi aata ...har question ke liye naya solution.....basics naam ki cheez hi nahi hai.....
श्रीमान 1 से 900 के बिच की संख्याकी बात हो रही हैं न कि 1 से 900 तक की संख्याओ की.. . 1 से 900 के बिच मे 898 संख्या होती है... अगर मै गलत हूँ तो pls समझाए...
@@himanhuhk9337 bilkul tab nahi karna chahiye par time kam ho to risk le sakte hain. Aur 'NOT' option me ssc me jyadatar nahi rehta bank me rehta hai. Nahi to AP laga ke number of terms find karni hi padegi.
This will only work in the following conditions: 1. The LCM of 3 numbers should be their product 2. The chosen number should perfectly divide the 3 numbers. If (1) is not true, common divisors should be taken only once. If (2) is not true the problem should be first solved for up to highest number which perfectly divides the product of 3 numbers, and then the leftover numbers should be considered.
You are the best Guruji, please provide your telegram channel,PDF of all of your best tricks,Sir I wanted to join your Math classes ,How much it cost ,could you please tell me ,my request.
@@rj0323pyare bhai ye number theory ka question h ... Trick nhi ye formula h ...aur ye 2 me se ak ktegi nhi hota .... Ye hota h no. Of prime divisor of 2 upon 2 similary aage wale concept euler function
@@imranhasan4109 haan include kar skte par yhan "between" likha hai.. jaise Maine kaha ki 1 and 5 k between kitne numbers hain , aapka answer hoga 3 ( 2,3,4) na ki 5 .. Yhan par agar sawal mai ye likha hota ki "from" 1 to 900 .. toh 900 hoti bhaii .
1 से 10 तक ऐसी कितनी संख्याये जो 2 व 3 से नही कटती 10*1/2*2/3=10/3=3.333...😂😂😂😂😂 आप पढ़ाना कब छोड़ोगे अब ? गुरु जी रूल वो बताए जो हर जगह लागू हो या फिर पूरी तरह क्लियर करें कि कब क्या किया जाना है?
are sir jahar bata diye ❤❤❤❤ isiliye apki video aa jati hai to mai sabar kar ke dekhta hu jab bhi aap ki video dekhta hu to kuch naya jarur sikhta hu ❤❤❤❤😊😊🎉🎉