Duuuuuuuuuuude!!!!!!! I spent around 20 minutes re-reading over this so many times. A few minutes into your video and I was like "oooooooh! That's simple!" Thank you so much!!!
@@rhgames2018 The second condition is stated correctly. For any two subsets of A, they are either identical or disjoint. Your statement is a little different from what we need to define a partition.
I'm so angry the professor who taught me this couldn't explain it like you did and made it look very complicated ... Thank you very much , very helpful!
@@Nockoutz1 I've noticed videos are better, because you can stop an rewind to parts that you don't understand. You can't rewind your prof. in the lecture hall, unless you record him/her.
Dear Atikur: The condition is correct. I completely understand your confusion, and it is very common. X and Y are arbitrarily chosen, and we also allow X = Y. So, they are either identical or disjoint. Clear as mud?
