#12 Conditional Statements If Else in JavaScript 

n=4 If(n%2==0) console. log(evennumber) ; Else if(n%2==1) console. log( odd number) ; Else Console(end the program)

Wow sir you finally changed the contrast thank you soooooo much❤️ we love your content👍

The ternary operator would be a nice addition to learning how if-else statements work.

You made if else conditions complicated for beginners in other videos its showcased very simply and clearly.

very very basics that no one is telling but are. that's awesome!! plz make more videos for this playlist

"yeee" lololol IDK why that made me laugh so hard. I love the way you teach....thank you so much.

Are you going to create videos on C language too, it will be very helpful for me and my college mate, cause I have problem to learn it, and the way you taught java last Sunday was phenomenal

Clean and nice let n = 12; if(n/2 === 0){ console.log("even") }; console.log("odd")

So if num1 > num2 is the condition but it is not satisfied then we can use both a console.log after } or else and console.log with a new set of 2 curly brackets?

Sir it would really be halpful if u start a tutorial on Data science

thank you very much!

Thank you very much

really enjoying

at 9.18 the operator we use is &&

Sir I know the series is very helpful and informative but there is a huge delay in videos. For completing the actual js client part that the series aimed at, it will take 4-5 months i think, please consider that Sir :)

FInding if a number is Even or Odd , time stamp 12:00 function oddEven(num) { if(num % 2 === 0) { num = 'even'; }else { num = 'odd'; } return num; } console.log(oddEven(4));

9:21 logical AND(&& )

5:35 is Eye Opening to me 😍😍😍😍. 9:25 its very tough for me to guess 😞

I love Javascript its like reading code from wordpress and after Js, if U know what I mean, U will say,omg f wp who can working with that, u havnt freedom, with JS U have freedom enough. I start love JS . Its my secend best friend :P

Timestamp 12:00 Checking if number is odd or even: let num = 232; let result = num % 2 ; if (result ===0){ console.log("num is even")} else console.log("num is odd") // output: num is even

Question for Video length 9:20 minutes.. The logical operator to you use would be &&

9:21 I should use and "&&" operator

Thanks.

i learned basics of c already, js is heaven comparably to c 😹

The number is divided by 2 that is even or its odd number If the condition num1%2==0 that is even or that is odd number

I guess I'm the 1st commenter

// sir ur example has a bug if 2 no. r equal then?? // Assignment let num = 8; if (num%2===0){ console.log("number is even") } else{ console.log("number is odd") }

If(n%2==0) //We are checking Number is divided exactly by 2 or not console.log("even"); else console.log("odd");

my assignment: I took hours racking my head on displaying the different variable calculations in a single block, but I couldn't,😉🙂 it was fun. let num1 = 10 / 2; let num2 = 9 / 2; let num3 = 7 / 2; if (num1 % 1) { console.log("odd"); } else { console.log("even"); }; if (num2 % 1) { console.log("odd"); } else { console.log("even"); }; if (num3 % 1) { console.log("odd"); } else { console.log("even"); };

Perfect vscode them

"Java Script say:its your choice! " :D :D 3:42

I found a simpler way, you can only compare the remaining two values: let num1 = 15; let num2 = 10; let num3 = 20; if (num1 > num2 && num1 > num3) { console.log("num1 is greatest"); } else if (num2 > num3) { console.log("num2 is greatest"); } else { console.log("num3 is greatest") } console.log("Exit")

let a=3; // to check whether number is odd or even if(a%2===0) console.log("the number is even"); else console.log("the number is odd");

9:12 AND operator

Let num = 15; If(num % 2 === 1){console.log(‘num is an odd number’)} Else{console.log(‘num is an even number);}

if(num1%2==0){ console.log("Its an even number"); } else{ console.log("Its a odd number"); }

Assignment let num1 = 2 if (num1 % 2 == 0) { console.log("num1 is even") } else { console.log("num1 is odd") }

whats the difference between system.out.printIn() and console.log()

I can only imagine how hard it is to explain things for a beginner to understand when you have explained same concepts earlier in other videos. I would have always be like: 'As I said earlier....'

9:25 AND &&

// Given assignment let num1 = 3 if ((num1 % 2) == 0) { console.log("num1 is even") } else { console.log("num1 is odd") }

Finding number is even or odd. Let a=prompt("enter a value") If(a%2===0){ Console.log("even"); }else{ Console.log("odd"); }

I/p:- Let n=12; If(n%2==0) { Console.log(number is even); } else { console.log(number is odd); } O/p:-number is even.

let a = prompt("enter a value"); if(a%2 == 0){ console.log("even"); } else{ console.log("odd"); }

4:35 i copied it exactly same and checked it multiple time but num1 is greater is not printing and it say process finished with exit code 0

let num = parseInt(prompt("Enter a number: ")); if (number %2 == 0) console.log("Number is Even"); else console.log("Number is Odd');

let num=5 if (num%2) console.log("Number is odd") else console.log("Number is even")

The answer is: let num = 10; if(num % 2 == 0){ console.log('The number is even number') } else{ console.log('The number is odd number') }

let x = 3; let y = 2; let result = x%y; if (result === 0) console.log(" Number is even") else console.log("Number is odd")

Hello Sir, I tried this on my console and what I observed that if I put ; at the end of if (result); then its still showing the output as num1 is greater though it is false. kindly suggest why this is happening. let num1 = 3; let num2 = 4; let result = num1 > num2; if(result); console.log("Num 1 is greater"); console.log("Bye.."); output : [Running] node "c:\Users\Desktop\js\IfElse.js" Num 1 is greater Bye.. [Done] exited with code=0 in 0.166 seconds

let num1 = 86 if (num1 % 2 == 0){ console.log("the given number is even") } else console.log("the given number is odd") console.log("Bye...")

let a=10; if(a%2==0) console.log(a,'is a even number') else console.log(a," is a odd number.")

I am a mechanical engg with zero programming kngle

And operator

and operator

Is using brackets even if you have 1 statement in the block best practice?

And opeartor

Let num = 5; Let result= num % 2; If (result===0) Console.log(num, "is an even number"); else Console.log(num, "is an odd number");

🙏👍

I m bit confused about what lang to chooce

//Assignment let num=99; if(num%2==0){ console.log("num is even number") } else{ console.log("num is odd number"); }

Sir but when I try using else it says unexpected token

and operator(&&)

// it is a even or odd number let num = 145 if (num%2==0){ console.log("it is a even number ", num) } else{ console.log("it is a odd number", num) }

1 st view and comment😋

Hi Naveen, What if, I will write code like this: let num1 = 9; let num2 = 9; let result = num1 > num2; if (result){ console.log("num1 is greater"); } else { console.log("num2 is greater"); } Here the output is showing num2 is greater, could you explain it?

Hello sir

How to give functions in conditions

let number = 8 if(number % 2 == 0){ console.log("number is even") } else{ console.log("number is odd") }

if thee number is ever or odd let num = 54 if (num%2 === 0){ console.log("num is even"); }else { console.log("num is odd"); }

not a good practice but an unnecessary practice. you can put semi columns in python too :)

let num = 1; if(num%2==0) { console.log("num is even"); } else{ console.log("the num is odd"); }

AND(&) operator

@9:18 AND Operator &&

Semi colon (;) seems just a habit of java developer.

Find out given number is even or off Let num = 2 If (num%2 === 0) { Console.log("given number is even"); }//% says 2/2 remainer is 0 else { Console.log("given number is off"); }

let x = 10; let result = x % 2; if(result) console.log("x is odd"); else console.log("x is even");

let num1 = 6; if (num1 % 2 === 0) { console.log(num1 + " is even"); } else { console.log(num1 + " is odd"); }

// check no is either odd or even let x = 146; if(x%2===0){ console.log(x is even) } else{ console.log(x is odd) } // output: x is even

//Assignment let n = 30 if (n%2==0) { console.log(n,'is an even number.'); } else { console.log(n, 'is an odd number.'); }

x = 10; y = 2; if (x%y == 0){ console.log('even') } else{ console.log('odd') }

1st view and 1st like

And

AND

num = 19; if (num%2==0) { console.log("the number is even"); } else{ console.log("the number is odd"); }

Elif

i like your series in general sir, but you should have told us how to take inputs before gioin into these stuff.... is FRUSTRATING not knowing how to get input and doing these operations , it makes programming boring, i already have experience in python

9:23 &&

The if else is not clear sir, it's complex

let a = number ("17"); if(a%2===0){ console.log("even"); } else{ console.log("odd"); {

let x=8 if(x%2==0) console.log("even") else console.log("odd") console.log("Happy coding") /* 💻🖥📱*/

default

If(n%2) console.log("odd"); else console.log("even");

let num1=5 if((num1)%2==0) console.log('number is even'); else console.log('number is odd');

Dude, improve your accent when talking in english

let num = 10; if (num%2===0) { console.log(String(num) +' '+'is an even number'); } else{ console.log(String(num) +' '+'is an odd number'); }

//Task let num1 = 10, num2 = 4, num3 = 7; function isCheck(ele) { return ele % 2 == 0; } isCheck(num1) ? console.log("Even") : console.log("Odd");//Even isCheck(num2) ? console.log("Even") : console.log("Odd");//Even isCheck(num3) ? console.log("Even") : console.log("Odd");//Odd

Answer of the Assignment : let num = 4 num%2==0?console.log("Even"):console.log("Odd")

let num = 69; if (num & 1) console.log ("The number is odd!"); else console.log ("The number is even");

let number = 5 if(number % 2 == 0){ console.log('This number is even.') } else{ console.log('This number is odd.') }