so if at the end you are sending 12 v why the use of the 2 blue capacitors? or , what are the capacitors for ? can i simply charge a battery with AC current? and skip the blue cylinders?
Primary will be heated if u sue for long time u have to use dc voltage regulator to regulate the voltage
5 лет назад
Why primary winding will be heating up? This type of circuit with TRIAC voltage regulator is used widely and no problem so far. Of cause this type of circuit is not optimal to charge the battery -- but it will work nevertheless.
tension a vide du transfo multiplier par racine de 2 soit 1.44 puis les condos lissent le 100 HZ augmentant ainsi la tension issue du pont de diode. rien d'extraordinaire c'est de électronique simple. Le BA BA de l'electronique.
@@АнатолийАнтибандера и что там,на трансе написано 12 в.Навыходе 14 в.Поставь диодеый мост и конденсатор,и напряжение примерно на 1/3 поднимется.с 14 в до 19 в
5 лет назад
@@АлександрП-л7п Если мултиметр не ESR тогда выходное напряжение трансформатора необходимо помножить на корень из двух (~1.4142).
Nó Entiendo Nada , un buén Cargadór de Baterías , No Deve tener Capacitores Ní Ningún tipo de Filtros , Usted hizo una Fuente , Nó un Cargadór , púes Cómo Cargadór és muy Deficiente !!
buenas noches saludos desde venezuela. quiero hacer un cargador de12v tengo un transformador de 35v como ago para bajarlo a 12v para luego ponerle un puente rectificador de 12v y 50amp. gracias
Not safe...there is no current limiting and it's doesn't require capacitor to smoothen DC for battery charging.more over the transformer doesn't work it's full potential when you reduce primary voltage with regulator.means current will decrease...try something useful it can only destroy a good battery..flowing too much current will damage the cells.
@@AverageUnixGirl who said.better you learn the basics of electronics and then comment..battery chargers doesn't require capacitors as battery itself acts as a capacitor.
Hi can you help me . I have a project on electric power scooter using 18v driller, 550rpm I want to use it because of the controller of the driller and am using external battery. Please any idea will help me thank you
Je veux voir un voltmètre sur l'entrée 220V du transformateur pendant toute la démonstration !!!!! I want to see a voltmeter on the transformer 220V input during the whole demonstration !!!!! أريد أن أرى الفولتميتر على مدخلات 220 فولت محول خلال المظاهرة بأكملها !!!!!
5 лет назад
And what do you expect to see there except of 220V? It would make more sense to measure consumed current in primary winding.
good job... I have a simple question : can you advice how i can get up to 18 v DC from a car battery of 12 V? the car´s engine must be on. The final 18 V will be used for another purpose. I really need a simple schema. Thanks.
При долгой роботе,такого устройства.диодный мост быстро выйдет из строя...так как,нет одачи тепла на радиатор...схема собрана лижбы паказать что роботает!(я хоть и баран,в электроники) но маё мнение такое!
What if you were to cornet the battery to a 240v inverter and run the transformer off of the invert? Would you create a looped power system? Would it charge itself?
No no, that 18volt is the peakvalue of the 12volt RMS-value of the rectified 12volt AC. The peakvoltage is always the RMS times squareroot2, so 12volt AC always becomes √2*12= ±19volt after a capacitor smoothes the 50Hz ripple out of the rectified AC.
So close but i am sorry but your wrong. His meter read 14.1v ac. While not a true rms meter its probably fine to assume its a roughly pure ac and that 14.1vac is the rms value or effective value of the voltage off the transformer. That means the peak voltage is 14.1×sqrt(2)=19.94vac. Then it goes through a full bridge rectifyer. All diodes have a voltage drop, and a full bridge rectifier will have two diodes conducting in series at any moment during an ac signal. Each diode drops about .7 volts totaling about 1.4v are drops. Then it goes through a filter that under load will smooth out the voltage to something less than peak. But under no load, the output should be a rectified and smooth 18.54vdc. He measured 18.56vac, probably slightly better diodes. And seeing as its filtered and under no load, you can expect there is no ripple voltage. Its pure 18.56vac as he measured.
@@kreynolds1123 okay that is correct, but what did i say wrong? You repeat my comment as far as i can read? Or is it that i didnt mention diode voltagedrop, or why you find me so totally wrong before repeating me?
@@robson6285 I didn't say you were totally wrong. I said you were close. 1) he didn't have 12v anyware in his system. 2) 12vac (rms) × sqr(2) is close to 16.97vac peek, not 19v. 3) The peek vac can not be the same as the peek vdc because of diode voltage drop.
@@MrElectron Silicon diodes forward biased voltage drops are typically close to .7v, and do not start conducting until the forward biased voltage is more than about 0.7v. Actually diodes do represent a constant voltage drop to any voltage above their forward voltage drop that is independent of current. A multimeter will read 0.5v across a diode supplied 0.5v. But, the same meter will read 0.7v across the diode if the diode is supplied 0.7v, 1v, 10, or 100v, reguadless if the load is 1 ohm, 10 ohm, 100 ohm, or 1000 ohms. But that voltage drop × current does effect how much power is lost to diode heat. For instance, 1 amps of current × .7v drop = .7 watts wasted as heat; 10 amps × .7v = 7 watts wasted as heat. For anyone that didn't already know, a diode's capacity to dissipate heat is a complex function with various factors that include but is not limited to surface area of the diode, ambient temperatures, efficiency of heat sinks, and rate of air flow. For anyone that didn't already know, a full bridge rectifyer has 4 diodes. Two diodes conduct during one half of an AC cycle, and the other two conduct during the other half of an AC cycle.
i bought a cheap fan switch, it have a 500K potentiometer inside it and it is not working for me, it is just changing the values between 16.5v up to 16.2volts. What do you think what should i do to solve it like you ? normally without switch it outputs 18volts.
Could you tell me would it be OK to use a twin secondary transformer as I have a spare 240 volt primary and twin secondary. At 12 volt at 50 VA transformer.
Buenas noches que puedo hacer para mi lavadora gasta mucha luz no es te tarjeta ya cambié motor y sique igual. Lavadora es de 6 cables por favor puede subir como un vídeo de lavadoras muchas gracias salu
Всё таки прав был Задорнов. Они там взрослые люди с детскими мозгами. Если бы не выходцы из России они бы до сих пор на деревьях сидели.
5 лет назад
Ну ты друг так и остался сидеть на пальме жувать бананы. По крайней мере автор пытается что-то сделать, пусть даже не очень эффективно -- но устройство работает и выполняет свою функцию (конечно о правильной зарядке батареи постоянным током до преустановленного напряжения здесь и речи не может идти).
5 лет назад
@@aleksandrtasov6423 Хочешь узнать человека? Тогда задень его. Человек - это сосуд. Чем наполнен, то и начнет выплескиваться из него!
You have so much potential. There is one problem though. You are making only simple stuff. You should start learning transistors and logic if you want to go further.
Dear inventor, it that systems is possible to charged automatically the Power source 12v battery 15amp, No stop to working 24 hours, to be free Energy. It that possible ? please do a video let us seen . ..
to není žádný převodník ale usměrňovač s filtrem který má na výstupu špičkové napětí nikoliv převedené! sekundár trafa má špičkové taky 18V! střední hornota je 12 někteří jedinci bez elektrotechnického vzdělání to nechápou
Great video, i found here what i was searching for along, but wasn't able to find. This fan switch trick was what solved my problem to control the 18v to decrease to 14.4v to fully charge a 12v battery.
Me puede ayudar a construir un regulador volta je potente, mi moto tiene un generador trifasico de 20 a 200 voltios ac y me quema los reguladores el generador es nuevo mi batería es de 12 vdc 9 amps gracias
Hi! Very informative videos, thank you! Is checking for the resistance from the primary and secondary a test to see if the transformer hasn't short circuited?
