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14.1 Rates and Rate Expressions 

Chad's Prep
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Struggling with Chemical Kinetics? Chad explains the Rate of a Reaction and how to determine valid Rate Expressions so that even a novice will understand!
If you want all my study guides, quizzes, and practice exams, check out my premium course at www.chadsprep.com/genchem-you...
Happy Studying!
00:00 - Kinetics
01:47 - Rate Expressions
04:51 - Practice Problem

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26 июл 2024

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Комментарии : 34   
@Morganwmahan
@Morganwmahan 4 года назад
This helped me more than you know. Simple, Clear, Concise. Teachers should strive to master the skills you have. Unfortunately most teachers are overly concerned with students perception of themselves and complicate a simple subject trying to display themselves as smart.
@thesn0wcone
@thesn0wcone 3 года назад
chads a god sent, change my mind.
@leticiaaguirre8126
@leticiaaguirre8126 3 года назад
you took the words right out of my mouth
@ChristianSpencer-c9g
@ChristianSpencer-c9g 20 дней назад
agreed
@cardiacmyxoma4073
@cardiacmyxoma4073 3 года назад
Hi Chad, I just wanted you to know that I scored a 517 on my MCAT with a 131 on the chem/phys section. I 100% believe that it's due to your videos. They've been a great help. Thank you so much for all you do!
@ChadsPrep
@ChadsPrep 3 года назад
Nice work, Situs - glad to hear you scored so well! Thanks for letting us know!
@monpetitgarcon
@monpetitgarcon Год назад
@cardiac myxoma lol I am anxiously preparing to sit for mine and I am very happy to discover Chad's channel for my prep!
@user-ko7wi8vc1j
@user-ko7wi8vc1j 9 месяцев назад
@@monpetitgarconش
@emmafisher8033
@emmafisher8033 4 года назад
Thank you so much for all of your videos! You have taught me exponentially more than my current professor.
@ChadsPrep
@ChadsPrep 4 года назад
You're very welcome Emma! Glad you're finding them helpful!
@emilyeskiw2744
@emilyeskiw2744 Год назад
I have one of the worst profs I have EVER had in my gen chem 2 course this year, I am not kidding when I say that these videos hands down saved me. Thank you so so much
@ChadsPrep
@ChadsPrep Год назад
Glad the channel is helping you - Happy Studying!
@meiyaoli2258
@meiyaoli2258 3 года назад
So simple and clear that even I can understand, love your teaching style...
@ChadsPrep
@ChadsPrep 3 года назад
Thank you very much! So glad you found this lesson helpful!
@Julian-tf8nj
@Julian-tf8nj 2 года назад
SUPERB teacher! Thanks 😀
@ChadsPrep
@ChadsPrep 2 года назад
You're welcome, Julian - and thank you!
@mosokodimichellemawasha6191
I am repeating my final year in bsc.. However i just came across your chanel today.hoping for great results😀 Will comeback and give an update pf how its going.
@ChadsPrep
@ChadsPrep Год назад
Glad you found the channel - Happy Studying!
@abdinasirabdukadir9783
@abdinasirabdukadir9783 2 года назад
Thank you teacher, you gave me great hand to get it easily coz have confused mi teachers' expressions thank you more from Somali.
@ChadsPrep
@ChadsPrep 2 года назад
You're welcome!
@dani3002el
@dani3002el 3 года назад
Hey Chad, when calculating the rate of change of NH3 can you explain why it’s 8 & not 6? Why wouldn’t we just divide 12 by the coefficient of NH3?
@jasonlan7475
@jasonlan7475 3 года назад
Not Chad but I think I got that part. For every 3 moles of H2 produced, it took 2 moles of NH3 (shown through the stoichiometry). For 12 moles of H2 to be produced, the reaction "occurred" 4 times (because 4 x 3 =12). Therefore 2 x 4 = 8 moles of NH3 is required.
@benjaminfranklin4149
@benjaminfranklin4149 9 месяцев назад
Are all states of species included in rate expressions? We know that solids and pure liquids are not included in the rate law for a reaction, but I'm not sure for rate expressions. Thank you!
@ChadsPrep
@ChadsPrep 9 месяцев назад
Be careful on this one Benjamin ;) Solids and liquids generally are not included in *equilibrium constant expressions* , but quite commonly appear in *rate laws* and *rate expressions* . Hope this helps!
@benjaminfranklin4149
@benjaminfranklin4149 9 месяцев назад
@@ChadsPrep Very helpful. Thank you so much!
@ChadsPrep
@ChadsPrep 9 месяцев назад
@@benjaminfranklin4149You are welcome!
@youngcoreana3760
@youngcoreana3760 Год назад
I wish he was my chemisty professor,,,
@ChadsPrep
@ChadsPrep Год назад
Thanks for saying so.
@williamcripfoe6754
@williamcripfoe6754 Год назад
You have saved me, thanks so much
@ChadsPrep
@ChadsPrep Год назад
You're welcome, William - Happy Studying!
@alissa7760
@alissa7760 3 года назад
Why does the concentration go down? How do we know? I get how we have to put ”-” sign to make the answer positive but I just don't get why the answer would be negative if we don't put ”-” sign.. Please help, my chem teacher at school isn't very helpful lol
@ChadsPrep
@ChadsPrep 3 года назад
It would work the same way with your bank account and may make a little more sense in that context. If you deposit money into your account that is a positive change reflecting the increase in money in your account, but if you spend or withdraw money from your account that is a negative change reflecting the decrease in money in your account. So, Increase = + change Decrease = - change You can also see this by simply calculating the change in concentration as "final - initial." For a product the final concentration is greater than the initial so the change in concentration comes out positive. But for a reactant the final concentration is smaller than the initial and so the change in concentration comes out negative. So rate is defined as change in concentration over change in time. For the reactant the change in concentration is negative as stated above so the rate would be negative as well. A proper rate expression gives the rate of the reaction in terms of any species in the reaction and the lords of chemistry decided that it should always be defined as being positive which is why we need to multiply the rates of reactants by -1. Hope this helps!
@be.alrightx5386
@be.alrightx5386 4 года назад
Be my teacher please
@ChadsPrep
@ChadsPrep 4 года назад
If you're in AZ there's a chance, otherwise youtube and chadsprep.com will have to do! Best in your studies!
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