Chad, no words can explain how thankful I am for your easy and concise explanation of the topic. I don't usually leave comments on RU-vid, but I seriously have to express my graditude. I am someone who struggles with chemistry, causing me to panic weeks before exams and quizzes. After watching your video can I just say that it all clicks now? The car analogy, the arrows you drew when explaining the doubling, it may not mean much to you but these actions truly played a role in my understanding of the topic. From one of the many students you've helped, thank you.
You sir are truly a noble gentleman. I read the chapter in the textbook on this subject and attempted the practice problems: failed. I watched your video and then re-attempted the SAME practice problems: easily completed. Mr. Chad is not the hero we deserve, but the hero we need
I cannot thank you enough for this video! You explained what I didn’t understand in just a couple of sentences! Thanks for getting straight to the point, definitely gonna check out your prep courses.
absolutely incredible video, tied everything together perfectly in the end as well. I got a A in gen chem 1 last semester and went into gen chem 2 overconfident, and still studied a lot for the first big exam but did extremely poorly. Exam 2 is next week on solids and Chemical Kinetics, your videos are great and extremely helpful, with lots of practice, I am aiming to do much better and a large thanks of that is going to you. Thank you from a future Dentist, your videos are life saving!!
Your videos are awesome. So succinct and precise. It's a great supplement to my professors lectures. Why you don't have more subscribers, I am stunned. Thanks so much and you've gained a subscriber in me for sure.
Phenomenal video Chad - this was explained by our professor in let's just say *not the greatest fashion*, and you somehow delivered a succinct and effective lesson on a tough topic. Thank you for continuing to democratize education!
Mr Chad, Professor Chad, oh my gosh I think your channel just saved my Gen Chem 2 grade. Thank you so much for sharing your knowledge, I'm at a point with my chem professor where I'm not following his methods of teaching AT ALL, he seems like a great guy and his qualifications are excellent and all those wonderful things but I'm not sure he knows that we are not all PhDs lol your videos are easy to digest and very very clear to follow. Thank you so much.
Thank You so much! I was stuck and frustared. Thank you thank you. They should show your videos in online classes honestly, my professors had me so confused and never give good examples to solve my labs. I have a question though, how do you solve when instead of doubling or tripling, they divide, for example, from 0.02 to 0.01, what would be the order?
Hey Zachary - yes we would end up with a fractional exponent in that case. BUT! if the NO concentration halved and the rate halved also it would still be first order :)
Wow. Great lesson. I love your shirt. God bless you. I pray that for helping us may God bless you massively. Eternal life with Christ is my prayer for you Prof❤Amen.
I have a question here, so the rate we calculated is the rate of change in concentration of Cl2 or NO? As I understand it, the rate for NO is double that of Cl2 because of NO's coefficient, so what is the reaction rate representing here?
Hi Leo! If you look back at the previous video in the playlist, I introduce rate expressions and explain that the rate of reaction can be expressed in terms of any reactant or product. The absolute value of the rate of reaction will be the same as the rate of change for a reactant or product with a coefficient of 1, half the absolute value of the rate of change for a reactant/product with a coefficient of 2, one-third of the absolute value of the rate of change for a reactant/product with a coefficient of 3, etc. This way, regardless of which reactant or product you consider, the overall rate of reaction will have the same value. Hope this helps!
Hello Chad, I just recently found this channel and I gotta say, I love all your videos, they're very helpful... You are literally one of my favorite online tutors 🤩
I get everything but I’m super confused when it comes to scientific notation. Every time I try to divide it gives me a scientific notation number, not a regular whole number, then I don’t know how to put that decimal to equal a power. Can you please help?
@@emily191 This is late, but maybe for someone else needing the same help. Remember an exponent in the denominator can be raised to the numerator by flipping the sign. So I always tell people, in the example you gave, divide the front numbers alone 7/2.8 = 2.5 then flip the exponent in the denominator which pushes it to the numerator (10^-4/10^-3) becomes (10^-4 × 10^3). Multiplying exponents means you add the exponents which now gives you 10^(-4+3) = 10^-1. Now combine it all..2.5 x 10^-1 or .25. Hope that's useful for whomever may need it.
@@josphellihsilak4588 thank you for your response! I ended up asking my brother and he figured it out in less than a minute lol. You can imagine the look on my face haha
Oh my god. I did not understand the lecture at all in my class. I immedietly turned to you and am glad I did. Please do every student a solid and never stop creating. The world is lucky and fortunate to have you. Also could you also make a chem video for easily telling if a molecule is polar without the need to use full vsepr theory and without access to electronegativity numbers becuase in AP Chemistry, you only have the periodic table. Thanks :)
I can't explain how useful these videos are. Thanks a lot. You are really saving me to pass the gen. chem. Also, I can consider naming my firstborn child Chad.
I am currently preparing to take over AP Chem at my school in 2 years. Your videos are really fantastic. You are a great teacher and explain everything thoroughly. Thank you!
I know what's wrong wit it. It ain't got no gas innet. Anyways thank you for being better than my professor. I learn more from you in 20 min than a semesters worth of class
So we have (0.18M.s^-1)/[(0.1M^2)(0.1M)]..... just looking at the unit that gives us: (M.s^-1)/[(M^2)(M)].... anything that is on the top and bottom we can cross out.... (-M-.s^-1)/[(M^2)(-M-)] which just leaves us with s^-1 on the top and M^2 on the bottom which is M^-2 s^-1
