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2.15 | Practice problem on Partial Order Relations, POSET in HINDI POSET lattice Hasse Diagram

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5 сен 2024

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Комментарии : 220

@ShahbazMalikAnsari 6 лет назад

Dear Sanchit apka effort bhut respecful hein ..aap aise hi logo ko ek behtrin CS engineer banate rahiye .....All the best

@bartosz3667 2 года назад

Tu bangaya behetrin CS engineer

@fouziarani9902 Год назад

after 1 day is my final exam.. and thank you so muchfor these helpful vedios. Your videos are giving me a lot of help

@KNOWLEDGEGATE_kg Год назад

Glad it's helpful❤ Wish you good luck for the exam, do well👍😊 Stay connected for more amazing videos, you can also check out our course for all Computer Science subjects, sharing the link below: www.knowledgegate.in/learn/Zero-to-Hero-in-Computer-Science

@TheRadioStar96 6 лет назад

Sir, The last example where Relation = { (a,b) | a,b ∈ Z ∧ (b/a) ∈ Z } couldn't be Partial Order Relation as it is not reflexive. It is not reflexive because, 0 ∈ Z and (0/0) ∉ Z. I remember you teaching where you say 0 as "Nalayak" and mostly causes the problem. Correct me if I am wrong. And yes, excellent teaching! Thank You!!

@siddharthsathya8973 2 года назад

true!

@MMAguyAritra Год назад

Hmm, shi bole

@Islam-tu5di 4 года назад

Thank you sir...Allah bless you sir

@SUBRONEEL 6 лет назад

your lecturesss are amazingggg... :D

@utkarshgsarmy7561 3 года назад

Katai zehar sir

@Huntyoudown2020 2 года назад

Brilliantly explained

@KNOWLEDGEGATE_kg 2 года назад

Thanks a lot dear student..Keep learning & supporting !! Do visit our website www.knowledgegate.in for more courses & contents !!

@ShubhamSingh-uj1ht 5 лет назад

For reflexive there must be 0/0 Which is not possible so this is not a reflexive relation hence not a partial order relation

@vandanasonkar1223 4 года назад

0/0 is not defined then how can you say 0/0 belongs to Z. So how can we take (0,0)? It will be reflexive. choose perfect example according given condition.

@manhalrahman5785 4 года назад

Yeah you're right. Question should mention Z+ ( all integers greater than 0) or simply Z- {0}

@soumilyade1057 2 года назад

If 0 is considered, it won't even be taken a question... The absence of 0 is implied here... 😅 But, if it's a subjective question, both the scenarios must be mentioned

@hjgjjhgjjg6397 3 года назад

4 the option me 0/0 integer nai milega to reflexive kaise hoga ?

@nehapande1321 3 года назад

Thank you sir for this precise and super useful video. 🙏🙏🙏🙏🙏🙏

@GeneralMathematics1 3 года назад

Very good video and more understandable

@technicallife2654 Год назад

Sir in 3rd option we know the power set of the option also include { ϕ } and ϕ is not included in reflexive case so it is not in partial order relation

@ekjotnanda6832 4 года назад

Excellent video 👍👍👍👏

@SanjeevKumar-hl9ql 4 года назад

Sir, aapko jitni v tariff karu kamm hoga Jhakas sir

@purnima53 3 года назад

really helpful sir...

@KNOWLEDGEGATE_kg 3 года назад

Thanks a lot Poonam..Keep learning and supporting !! Do visit our website www.knowledgegate.in for more courses and contents !!

@vaishalisupare1159 6 лет назад

Very nice sir aap jaisa koi nahi ap Jo smzhate hai sub smj aata hai thanks so much muzhe apke vedio see bhot mdat mili hai

@gourav1163 3 года назад

Sir If We Have (3,4) then we won't have (4,3) then if we don't have (4,3) How can i apply transitive property?😶

@Rahul.G.Paikaray27 Год назад

Sir in last question D option is wrong because (0,0) doesn't satisfy the condition that's why it is not reflexive implies not partial ordered relation

@sangrampattanaik4354 4 года назад

aap best ho sir g.

@hafsaabbasi3761 3 года назад

Sir i have a question if any one know plz answer .how relexifity is satisfy in R4: because zero cannot divide it self....its beome indefinite form

@zubaidthakur5760 6 лет назад

Tq so much sir apne meri buhat help hi h tq again

@gourav1163 3 года назад

If a condition is anti-symmetric then won't it be transitive automatically....cause if we have (1,2) then we won't have (2,1)...then the condition of transitive wont apply??

@pranvigarg9205 4 года назад

Dear sanchit sir u r doing really well sir Maine binary representation Vali video dekhi this usme aapki addition and subtraction using 1's complement and 2's complement Vali video nahi mili plz sir ho sake to you tube par daal Dena plz

@crazygeek5825 4 года назад

10:33 in 3rd it can be antisymmetric if {1} is a subset of {1, 2}, {1, 2} cant be a subset of {1} so since A is a subset of B, B is not subset of A

@fanimahmood644 20 дней назад

In 4th part mension that a,b € Z, we can take any two integers i.e 2,3 € Z. Implies 2|3 = 1.5 which doesn't € Z. So, this relation is not antisymmetric.

@viratkaushik7352 6 лет назад

Sir , please add lectures on lattice , hasse diagram and posets and also on iso and homomorphism etc. In discrete mathemtics as soon as possible... please..

@zainabehsan9079 3 года назад

Sir plz comparable or non comparable elements or linearly order sets with examples... Py bhi aik lecture dijiay ga...

@ankushsingh0 6 лет назад

Bahut Achchha Sir... 👏👏

@KUNAL22able 6 лет назад

4th example is not a partial ordered relation as (2,-2) and (-2,2) both exist in the set. It can be defined on Natural Nos.

@sidkumthekar4614 2 года назад

It can be ....if you simply dont include the pair in the relation ....and also (2,-2)and (-2,2) defy the reflexive law

@rohitpathak5710 5 лет назад

if mera gate clear hua 2020 ka so uska credit aapko jayega. God bless you sir. thank you so much.

@welovepakistan6982 4 года назад

Sir your teaching method is very Good👌

@adeelkhokhar9638 3 года назад

Ap k concepts bht clear hoty h sir

@arpitbharadwaj8799 6 лет назад

Sir (2,-2) aur (-2,2) to 4th example me symmetric ho jaega to kaise partial order hoga

@jyotikute202 3 года назад

Sir ... You are superb 😍.... Tooo good...

@nihaltahariya8858 6 лет назад

Thank you so much for the videos sir...

@gullapallimythri2915 3 года назад

Thank you sir 🙏

@bharatmishra250 5 лет назад

clear concept .

@mr.nobody4498 5 лет назад

Yes sir, you are going to Good. Can you create videos for BSc. IT subjects because when you cover topics it's our half topics only. So try else no problem you are going to Good.

@venkatsai817 3 года назад

Sir it doesnt satisfy reflexive property when a ,b are 0,0 .And for pair 1,-1 it doesnt satisfy antisymmetric property .Clearly option 4 is not partial order relation

@VijayKumar-nc8si 3 года назад

I had same doubt

@sajidali7228 5 лет назад

Awsm teacher .... well explained sir

@veereshkumar3470 5 лет назад

Ur explanation power is amazing

@rituparnapradhan8615 4 года назад

Very nice sir

@sub_inspector_deepak 4 года назад

very helpful

@harshupadhyay737 6 лет назад

very nice sir n thanks

@mdfuadhasancanada 5 лет назад

Thanks, brother love from Bangladesh

@uditgupta6997 6 лет назад

Amazing video like always

@bijayasabar8192 6 месяцев назад

you are great sir

@ramtiwari4727 5 лет назад

in 4 th example ,it is not reflexive as 0/0 is not defined, please correct it.

@saiishitha8365 6 лет назад

Can U plz upload English version of these videos as well

@debmalyasur2879 3 года назад

Sir kindly recheck... The 4th option will not be right... Bcz 0 is belonging to Z but 0/0 will not be defined... Thus that will be the only diagonal element that will be missing in the relation, so the relation will not be reflexive... Thus it's not a partial order also!!!

@ankitvaghela3402 5 лет назад

Excellent

@Ankit-we8ym 6 лет назад

Just perfect sir

@ShivanshMishra2409 5 лет назад

@pratikpatil5214 6 лет назад

Very nice explanation sir......

@rawatvipul 6 лет назад

4th option me Z gdbd hai. (1,-1) pair anti symmetry follow n krta. Correct me if I am wrong.

@shahzebansari6585 3 года назад

I am also confused here, If you have found any explanation please let me know.

@hjgjjhgjjg6397 3 года назад

Same in reflexivity( 0,0 ) belong nai karta relation me

@saniyamaan4444 5 лет назад

Thnku sir ....

@lightofasia5079 5 лет назад

Nice classes....You are great sir....

@puneetsingla8819 6 лет назад

Thank You so much for this great effort! Keep up the spirit. :)

@kumarramayanammangalam3575 6 лет назад

in fourth question, for anti-symmetric, take example of (2,-2)....then anti-symmetric condition is not satisfied.

@piyachaudhary4361 6 лет назад

sir your vedios are very helpful thank you. can you please make vedios on Random variables ,distributions

@raj-nq8ke 4 года назад

Thanks sir

@tanutanu4751 5 лет назад

Super sir

@soumambanerjee1816 5 лет назад

u r god sir...u r the best

@shaunpaul9584 2 года назад

thanks man

@KNOWLEDGEGATE_kg 2 года назад

You are welcome dear, keep learning & supporting !! Do visit our website www.knowledgegate.in for more courses & contents !!

@ishukori9574 Год назад

Dekh to rhe honge man h 😮 0:22

@knowledgebhajja2019 4 года назад

Thank u sir what a explaination

@Naveen-xz6ml 6 лет назад

in option b, if we consider (2,2) -> is allowed by anti symmetric. this is a

@AbhishekKumaraevii 6 лет назад

(2,2) is covered in diagonal set.

@ishusaini8552 6 лет назад

great job sir...thanks a lot

@moahnpal9282 6 лет назад

sir app bhut aacha padate ho sir Kya ap data structure PDA skate ho algo

@kishankumar-ln4ok 5 лет назад

Sir, In last 4th option a\b. How can I proof reflexive if we take 0/0 it's not define.. How can this reflexive. And when we take( - 2/2) and (2/-2) then 2 is not equal to( - 2) so how we can say it is antisymmetric

@pratikkumar6148 3 года назад

Even I thought the same

@gujaratgovstudy 5 лет назад

Dear sanchit, 4th is incorrect, (2,-2) and (-2,2) are anti symmetric

@beststocks8555 6 лет назад

great. lattice please

@amanjain3339 6 лет назад

plz sir upload more videos on counter...

@dishankjindal7110 6 лет назад

Sir you are making good videos. Try to do daily 1 hour livestream session. And turn on sponsorship button

@depanjanroy7278 4 года назад

Sir R4 does not have (0, 0) then it shouldn't be reflexive in the first place...isn't it?

@santanukumarbehera4079 3 года назад

🙏🙏🙏🙏🙏🙏🙏

@dipalikhatua4978 5 лет назад

thank u very much sir, sir plz make videos on numerical maths which is in mca 3rd semester..

@letsfixedit572 3 года назад

thank you, sir!

@kaliakon3756 6 лет назад

Baut badiya sir

@harshitverma6026 6 лет назад

Sir, please make a video on Hasse Diagram.

@krutarthtrivedi5716 5 лет назад

In 4rth option...take pair (-2,2) then it is not anti-symetric..so also option D is not partial order relation !

@akashmondal9063 Год назад

in the last example if a==0 then it is not reflexive.

@shubhamshastri160 5 лет назад

sir ye last wale example m doubt h kyuki zero bhi interger hai but us se divisibility posible nahi h...... to kya ye poset hai ?? plz reply sir.......

@divewithshubham 6 лет назад

Sir toc complete kr dijiye.. and CO kb start kriyega?

@sahilsoni558 6 лет назад

Please make a video ofJob-scheduling problems

@shalinijaiswal309 Год назад

Sir ...in (4) ... If I take (0,0) then it is not reflexive na ?

@ravimaurya5851 6 лет назад

sir what about (0,0)in last example..how we can say 0/0 is integer..???i think it should not be a reflexive relation..

@satyamrai2577 6 лет назад

great help!!

@varsharao9257 5 лет назад

Sir plz make video on index class and indexing set

@akanchaagrawal2704 6 лет назад

I think R4 for checking partial order relation is wrong. R4 can't be antisymmetric because it is allowing (1, -1) and (-1,1) in its relation R4 and 1, -1 belongs to Z.

@gulshangorge5789 6 лет назад

For pair (0,0) reflexivity not satisfied sr then how would the reln be por??

@pragyarani8185 5 лет назад

4th option is also incorrect...Make a pair (5,-5) and (-5,5) both give -1 which is also comes in the set Z..And they are symmetric pair...So Not Antisymmetric

@AbhishekThakur-wl1pl 3 года назад

Also 0/0 is not defined. Hence reflexive property fails at 0.

@prateekjain596 3 года назад

5 and -5 both units are same but they have different mean so we cant use 5,-5 as symmetric or reflexive(diagonal ordered pair)

@laibaasghar3588 3 года назад

Sir plz tell us short trick method to solve this question it's a long method also consume a time in examination.

@PrathamKashyap7 4 года назад

Yeah sir

@akashgupta-tc1og 6 лет назад

sir please upload the videos of predicate and quantifiers

@divyalakhotia2309 5 лет назад

hello sir, 4th is not a partial order set because it dose not satisfy the antisymmetric condition. there can be a possiblity of having two elements like (-2,2) and (2,-2). if i am wrong then plz tell me`

@RN-Ashlesha Год назад

correct. Z+ set of positive integers is a partial order relation.

@zainabehsan9079 3 года назад

Awesome 👏👏👏👏

@KNOWLEDGEGATE_kg 3 года назад

Thank you Zainab.. Keep learning and supporting !!

@swetaroy4054 5 лет назад

Amazing sir tqsm

@abhaysharma-ps9sq 5 лет назад

nice explantion

@KNOWLEDGEGATE_kg 5 лет назад

Thank you Abhay.. Keep following and learning..

@SharmaScribe 6 лет назад

Video on graphs pls sir

@siddharthadhar2231 3 года назад

Sir in case of the R4, (5, -5) belongs to R4 as well as (-5, 5) also belongs to R4 but (5 != -5) which essentially violates anti-symmetric property then how R4 becomes Partially Ordered?

@KNOWLEDGEGATE_kg 3 года назад

Drop all ur queries in our official discussion group t.me/KGgatefreeclasse