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A good question, so first thing first you have to start your application for which you need executable. app = Application(backend="uia").start('notepad.exe') Now, if you have a popup/dialog on the application then you need to get your dialog using it's name like this. # describe the window inside Notepad.exe process dlg_spec = app.UntitledNotepad

Don't be sorry about this. Try installing Python of 32 bit and then run the same code.

It won't matter much even if the window has a complicated name. Two things to do here- 1. First use print_control_identifiers to get the list the names of that window that you can use. 2. Choose the one which seems easy enough

@@PrashantSharmaOfficial thanks for your reply, but I mean when I do print_control_identifiers, I have to put the window name before it in a special form like (app.UntitledNotepad.print_control_identifiers). So, how can I do this with a window title has many special characters and numbers?

@@mohamedemad4675 from pywinauto import application app = application.Application(backend='uia').connect(handle=0x203f0) handle = app.window(title_re="THE TITLE")

Yes, but sometimes you don't need to type the full name. Sometimes, even "Login" would also work. Please try both ways.

Even i am facing issue