I have a degree in physics, a degree in Mechanical Engineering and I’m older than dirt. But I have to say, the phrase “3, 2, 1 integrate” is one of the funniest things I have ever heard. It makes me laugh every time I think of it.
How difficult is it to attain a degrees (minimum a masters) in physics? How has your experience in the field of physics been? I am considering a degree in physics on a path to medical physics.
Imagine the commentary: Its a good trick by Joe who looks to convert like into trigonometric form , while John makes excellent use of complex numbers to simplify the terms , it seems as if Joe has the upper hand here , but john now elegantly applies feynman's trick and gets the answer, what a twist in the tale
MIT almost seems like a parallel reality. A world where anti-differentiation is a sport and people film it on their phones is a world I desire to be a part of :)
I think that would distract the participants... math is a game of critical thinking and focus. If its added separately they must make sure it gives various possible solutions and some intellectual input instead of some crazy clown shit. I liked it as it is tho.
@@Snakesake2099lol. I did many Jee advanced problems but they’re never even CLOSE to MIT entrance exams or even these so called ‘avg high school’ questions.
Although I’m just a high school student, but I’m still trying to understand what are they doing. I found a quit intriguing part: The guy in the left he is using the blackboard as his eraser paper, writing down all the process and calculate. The guy in the right is different, he calculate the operation by mind and he use the blackboard as an extended-memory cache, to write down the process just for not forget and loss them, like a redstone repeater, which I found it was impressive for me.
if this is coming from what I assume is an IITian which means a JEE Advanced cleared candidate with less than 16k rank atleast, I cannot assume how smart or hardworking you have to be to reach Luke's level!@harsh_will_iit
I actually tried solving some of these and was able to solve a few (but none from the finals though, and none in the stipulated time period). Glad I've still got a bit of integration in me! :)
Luke I’ve been following him from his primary grades and always saying he’s the next big thing in maths One of the finest brain always winning now in college wow Congratulations! Inspiration his YT channel is also worth visiting
@@shashwatdubey5416 will not be revealed since that's part of creating the suspense around him. You will have to search YT and see if it really exists or not
@@JoshT13 It's not that creepy because he's literally everywhere. You see him somewhere in basically every video related to olympiad/competitive maths.
This seems like something I would have had a nightmare about during high school and woken up in a cold sweat. It's been over six years and I still have flashbacks to AP calculus.
@John They have to have some sort of great intelligence to get this far into the integration bee, don't see why there was any need for this comment lmao.
@John Understanding that these guys are judged to be smart enough to compete during an intergration bee is indeed very short sighted, but yet you were too blind to see that...
to me too. I don't know how they do it. I could solve the first one in 20 minutes :-) :-) ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-wOBf_MrQVNo.html
The answer of Q.4 should be 5 * 10^18 * ln(1001/999) ,which is equal to the answer written in decimal. Luke get almost right answer but he got ln(1003/1001) which is the only part wrong in the answer. The arbiter said there is no 5, but there is. We can't solve log on the board with time limit.
I'm surprised by the fact no one in the video or even in the comment section realised that, in 21:16 , they both got the answers correct! coz if you simplify their answers, you'll get the same answer as that given by the MIT. It's a shame to judge the answers as wrong just because they were not written exactly same or it should not be 'a multiple of 5'. Integral answers often exist in many forms. They both should have gotten a point for that.
@xxdxddddffwfegfg haha I actually am doing ok with the open university mathematics. mit is was just a hype in high school. of course, I am very realistic as open university mathematics and physics bsc is good enough for me.
@@RegisteredLate123 lol let me first finish my undergraduate. I meant not to get into MIT but being MIT level of smarts which comes with doing well enough in maths like in my current undergraduate mathematics and physics bsc degree at the open university uk.
@John I think I'm over Ivy League in terms of for prestige reasons. I'm better used to the content of the course available at that particular university and I'm happy with open university course description. so I'm good with uni at the moment just thinking about ability variation between various universities. so I am disabled and recovering from a genetic disease and I think that I can some day have exceptional ability so that's what I'm aiming for. right now I have above average performance at second year mathematics and physics bsc.
Problem 1 I=int ((tan x)^1/3/(sinx+cosx)^2)dx from 0 to pi/2 I= int ((tan x)^1/3/(cosx(sinx/cosx+1)^2)dx= int ((tanx)^(1/3)dx/(cosx)^2(tanx+1)^2) u=tanx I=int(((u)1/3)/(u+1)^2)du from 0 to infinity u=t^3 du=3t^2dt I=int(t*3t^2/(t^3+1)^2)dt from 0 to infinity, integrate by parts I=-t/(t^3+1)+int dt/(t^3+1) from 0 to infinity, -t/(t^3+1)=0 if t=0 and t=infinity int dt/(t^3+1)=( 1/3)*int dt/(t+1)-(1/3)*int (t-2)/(t^2-t+1)dt=1/3*log(t+1)-(1/6)*log (t^2-t+1)+(1/2)*int dt/(t^2-t+1), 1/3*log (t+1)-(1/6)*log (t^2-t+1)=log ((t^2+2t+1)/(t^2-t+1)^(1/6)=0 if t=0 and t=infinity I=(1/2)*int dt/(t^2-t+1)dt=(1/2)*int dt/((t-1/2)^2+(√3/2)=(1/2)* (2/√3*arctan(2t/√3-1/√3) from 0 to infinity I=1/√3 (pi/2+pi/6) =4/6√3=2√3pi/9
Mfs talkin bout how they kept up with these students, but you already know the moment they walk up to that chalkboard they gonna be 10x slower than anyone in there
Honestly, problems are doable and is not super hard. However it's important you finish in time before other person and dont make blunder under time pressure
The very first integral looks simple but is so HARD! Simplifying it into a different form (for the denominator) is easy, but trying to integrate it with typical integration techniques is seemingly impossible so that evaluation became a guess... I heard of Luke Robitaille from being an insane mathlete (MATHCOUNTS & IMO); thus, if he couldn't fully solve - who could? Jk
I got that one pretty quickly but I doubt I would have finished in four minutes. It follows pretty simply from doing the substitution u^3=tan x. It looked like he was overthinking it.
@@hbowman108 Yep the integral actually reduces to integral from 0 to inf of (3u^3/((u+1)^2)(u^2-u+1))du and then you just do parcial fractions. However, we all must admit that shit is not finished in less than 4 minutes lol
@@MiguelHD04 I reduced to 3/(1+x³) - 3/(1+x³)² and the second one obviously has a contour integral of zero. Then you just have the pole at exp(pi i/3).
I got the 3rd problem... but the rest of them were super hard. The last one was particularly tricky... I think we have to use the continuity of the function. Hoping someone can help me with the last solution.
The fact that they are writing in code to deter the other guy from looking is so mind boggling. Add on top of that an integral that would make you quit the calc if you saw it and it’s just insane.
I don't know if he has already explained it yet but, organic chemistry tutor. Guy made me understand the fundamentals of derivatives within an hour edit: organic
i the beginning i thought the luke was dumb because he was not even writing the integration sigh then i realised that he was doing the entire procedure in his mind💀🗿
Why were such questions asked during my Higher secondary school... .My love for maths Faded away, I tried to run away from it but boom bounces back again With economics even though it's just simple calculus
My reaction in chronological order: *First question revealed* Oh that’s not that bad *Plug in pi/2 to tangent* Oh shit, that’s undefined Oh shit this is an integral, I have to find the anti derivative Oh shit you can’t u substitute this Oh shit I’m fucking lost
Recently it was published a book about MIT integration bee, under the title " MIT Integration Bee, Solutions of Qualifying Tests from 2010 to 2023" You can simply find it!
its hard to believe its given in school exams in turkey and also on the most biggest exam for entering university the time also is 2 minutes for every question
