In this video you will learn, how to determine which stations are affected by LOCAL ATTRACTION by simply BEARINGS OF THE LINES. This one is the easiest method and will enable you to determine LA quickly !
No...use this process for open traverse only ! If you use it for closed traverse then you might end up with different values of a particular bearing. For closed traverse problem, first you need to close the traverse by correcting all the included angles and then only you correct all the bearings...
Possibly...but make sure after correcting the bearings, the sum of all included angles must be equal to (2n-4)*90. If it is so, then your solution is correct !
Simply superb explaination. Corrected bearings can be calculated without finding included angles which saves a lot of time. Thank you very much sir for the help ✌
ek jgha corection CD ka positive btya h or dusri jgha negative ..... or digram mai B ke fore bearing ko interior angle bta diya h ....correction kdijiye sir yha bhi
The difference between FB and BB of line CD is 179 degrees 25 mins, which is 35 mins less than 180 degrees. At this stage, just observe whether the magnitude of the difference is less than, greater than or equal to 180 degrees. So it doesn't matter whether you are doing BB-FB or FB-BB, what matters is that what is the relation of difference with respect to 180. Since it is 35 mins less than 180 (error), so in order to make the difference 180, just add 35 mins (correction).
All the angles are from North direction, whether it is FB or BB. However, in the figure I have mistakenly wrote 96 degree and 55 minutes as an interior angle of B. It is a FB of BC which will come in 2nd quadrant. So the figure will remain the same.
@@thirumalasaivardhan1677 Nope...looking at the table, can you tell me which point is the last point that is connecting back to A? Now try to make figure by yourself ! Happy learning !!
@@CivilModules sir This is the condition and I have to create a question and solve it Like Full question is What is Closed traverse? When the bearing of closed sides is not given in a closed traverse. Solve 2 numericals
For this numerical you have to provide at least one bearing and all included angles in order to find the bearings of other sides. If this is what you are trying to do...
That's because now your instrument is at station C where location attraction is detected.Take observation in any direction from C, you will get an error of 35 mins. Thats y from C towards D , error cant be zero.
Hi Ritwik... Let me reframe this question. What to do when ALL the lines are having LOCAL attraction? There are two cases:- Case 1: There exists at least ONE line in which the difference between FB and BB is 180 degrees. In this case, solve the numerical as shown in this video. Case2: Not even a single line exists that has a difference of 180 degrees, in this case: a) Search the line that has the least error for eg. difference in FB and BB is 180 degrees and 10 minutes. b) Here 10 minutes is the least error among all the lines. c) Now divide 10 minutes into 2 parts i.e 5 minutes. Adjust 5 mins in FB and 5 mins in BB in such a way so that their difference becomes exact 180 degrees. d) Now the difference is 180 degrees, use this line as your reference line and solve the rest of the numerical as shown in this video.
It turns out that any observation taken from station B and C is wrong, hence it needs to be corrected by fixing the error. That is why station B and C have local attraction. Got it ?
Ur concept failed .when i tried SOLVE it on ESE2015 QUESTION where in FB and BB are given in quadrantal bearing and u have to find internal angle and corrected bearings.u can pick that question and make a video solution von that
@@CivilModules the question contain table which is difficult to copy here u can send mee ur email id i will send u there or u can find in internet the question start with "four cars started from O -S1-S2-S3-S4-O.
@@khadeers14 Before answering your query I need to know two things: 1) Have you understood how +25 ' error at B was calculated? 2) In this part of your comment " in station BC, u took only 10' ", how did you arrive at this point that 10 ' error has been taken?
