5-10 Equilibrium of a Rigid Body (Chapter 5) Hibbeler Statics 14th Edition Engineers Academy

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Equilibrium of a Rigid Body (2D Equilibrium)
How to solve Equilibrium Problems | Engineers Academy
Engineering Statics by Hibbeler 14th Edition
5-10. Determine the components of the support reactions at the fixed support A on the cantilevered beam.
3d equilibrium statics,
Particle equilibrium in 3d
#EngineeringMechanics #EngineeringStatics #Statics #Hibbeler #Equilibrium
Hibbeler Statics - Chapter Playlists
Chapter 2: Force Vectors - • Chapter 2: Force Vecto...
Chapter 3: Equilibrium of a Particle - • Chapter 3: Equilibrium...
Chapter 4: Force System Resultants - • Chapter 4: Force Syste...
Chapter 5: Equilibrium of a Rigid Body - • Chapter 5: Equilibrium...
Chapter 6: Structural Analysis - • Chapter 6: Structural ...
Chapter 8: Friction - • Chapter 6: Structural ...

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19 сен 2024

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Комментарии : 18

@fenixfyre Год назад

Thank you so much for this content! No one is posting statics problems like you!🙌

@EngineersAcademy2020 Год назад

Welcome. Keep learning share with ur colleagues

@phoellymoe4267 Год назад

man you're doing amazing job thanks

@EngineersAcademy2020 Год назад

Thanks for the appreciation! Keep learning and do share

@gbemisolarahmon54 Год назад

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@EngineersAcademy2020 Год назад

Always welcome share with your friends too

@yigitcan824 10 месяцев назад

Professor.I have a question.I know Fx,Fy and sum of the moments must be equal to zero.But respect to which point we must take a moment?Could you explain me?

@EngineersAcademy2020 10 месяцев назад

The moment at any point must be zero, as the whole beam is in equilibrium

@yigitcan824 10 месяцев назад

@@EngineersAcademy2020So for example,if I took a moment at where 6kN is located ,it's gonna be zero also right?🤔

@Abenezer499 9 месяцев назад

Why didn't we use the tension of the centilevered beam

@nooreyliananajwa4518 9 месяцев назад

Sir, I want to ask for your help in solving question that my teacher had given to me , may I know how can I contacg you to give you the details of the question?

@OGShitposter69 6 месяцев назад

I understand everything, but i guess concept isn't clear what must i do to make my concept strong and don't you have concept explaining video?

@egedurcan Год назад

why didn't we add 3m to 4cos30(1,5sin30)?

@tharindudhananjaya2125 Год назад

my question is you one

@NattyPi 10 месяцев назад

@@tharindudhananjaya2125 Only multiply by perpendicular distance

@aldrianperez3440 6 месяцев назад

3m is the total of all horizontal distance, while 1.5 sin30 is the only vertical distance. Both are multiplied by the perpendicular force, acting upon the opposite distance.