6.10 Paging | Calculate number of Pages | Memory Management in Operating System in Hindi

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13 окт 2024

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Комментарии : 162

@KNOWLEDGEGATE_kg Год назад

For complete Operating System, check out this video: ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-xw_OuOhjauw.html

@chakshujain7557 4 года назад

If someone confused like me about page size at 9:34 then here is the explanation --> "Size of a Location and Size of a Page are two different things. We have a separate address for each Location and can have a base address for a Page. A Page is made up of Locations." I realised this after watching the video twice and spending some time :) Also at 9:04, it is "64" and not "32". Thanks, sir for such a great explanation and god bless you. Also, a humble request to complete this series by covering other important topics like multithreading, kernel, etc. After studying from Knowledge Gate I started enjoying these subjects. My college teachers made these subjects quite boring while teaching in the class and forced me to consider these subjects waste. But a good teacher like you can make anything interesting. Thanks again :)

@Sk-rm8ed 4 года назад

Here i want to say something , if the page size is 1kb then the secondary memory size equal to 2^24×1kb and the main memory size is 2^16×1kb because the page size is ramain same in the secondary memory as well as in the main memory also.

@akshatjain2222 5 лет назад

This one is a hidden gem . After watching this i never regret skipping my OS classes xD

@radicalengineer2331 Год назад

So what you doing nowadays?

@Saim_mir 5 лет назад

No words to describe your effort and knowledge power.. Stay blessed and keep sharing as much as you can ..From Pakistan

@aarohigupta2020 7 лет назад

sir ur knowledge is very good and your explanation mind-blowing...... sir please provide us computer organization lecture....... KG👍

@vinaychahal2654 6 лет назад

you can visit that link for watching COA Vedios

@suryasikharej5511 3 года назад

I guess no one ever had taught os with so much clarity. Thank you so much and please provide us with more videos . God bless you sir.

@KNOWLEDGEGATE_kg 3 года назад

It's my pleasure Surya, thank you for your valuable feedback. You can also visit our website www.knowledgegate.in for more courses and contents. Keep learning and supporting !!

@nidhinandani1827 4 года назад

Nicely explained with a very good example. I never get sleepy while attending your lectures as I felt during my study period. GOD GIFTED TALENT to make any topic interesting.Thanks!!!!!!!!!!!

@rishabhjain7487 7 лет назад

2^6 is 64 not 32, please rectify. It might cause doubt to others.

@Afiffing 6 лет назад

I came here to rectify this.

@nitskrishna 6 лет назад

yes it should be 64 but its a small un intentional mistake, other than that the knowledge shared is excellent, the energy level is also good.

@AmazingDwarkaa 4 года назад

Bro This Is Mistake by Sir Butt.... You people only Find Mistake . Sir Teach us Free This Whole syllabus but you people Are Talking about One Mistake. Why you not appreciate This Amazing work.

@adarshgupta5418 4 года назад

@@AmazingDwarkaa I think he didn't mean to criticize him but just telling him to correct the mistake.

@tumtum6910 4 года назад

@@AmazingDwarkaa finding out mistakes and asking doubts is also a way to learn.

@wasimhayder7719 7 лет назад

Sir, Thank u for making such videos which helps thousand of students who can't afford coaching classes. I watch ur videos on TOC and I find it very informative . I like ur style of teaching and smiling face .I request to u please make such videos on networking & Communication and Compiler.

@ANKITKUMARapple 7 лет назад

U made the Concept of OS Very Easy Sir!! Thanks a lot :)

@amolagarwal5336 7 лет назад

great teacher mr. sanchit.. itna sahi college me padhane lage to maza hi aa jaye.. great effort sir.

@techspertts4141 4 года назад

Your way of delivering knowledge is extremely good.

@alpeshrodage 7 лет назад

great series!! Helped me a lot to refresh my knowledge of memory management concepts quickly. I have not checked all your videos yet. By any chance you have any session on VMX technology (EPT - Extended page table and VPID - Virtual processor identifier) from Intel to support hardware virtualization? Thank you very much for all your efforts!!

@aswina8053 6 лет назад

Thanks a lot Sir....Waiting for lectures on COMPILER. Great teaching style and methodology. Really blesses teacher. May god bless you.

@mindpower421 4 года назад

sanchit sir mere paas sirf ek dil hai, aap kitni baar ek hi dil jeetoge

@souravkumar-ue8uj 6 лет назад

The video was really great ! i understood the main concept of paging ! thankx for the video !

@chandanisanthiyagu3786 3 года назад

It's much appreciated with much respect sir. Thank you

@apurvsawant5703 5 лет назад

I always rely on your videos to get good pointer. Thanks a lot

@sanashaikh-ib1yc 4 года назад

Sir you are just awesome...you explain every topic so effortlessly

@purushottam2010 4 года назад

sir aap bahut amazing ho!! Learned a lot about teaching from you

@snehakulkarni149 6 лет назад

Sir hats off to you . Your way of teaching is really great .This video or rather I must say all your videos are awesome and was very very useful for me . Thank you so much sir .

@CreativeWorldbyAbial 7 лет назад

sir,you explain the concepts very well...thanks

@manishpurve6161 6 лет назад

sir you have amazing ability to explain plzz make more videos and jagat ka kalyaan kare.

@chinmaytiwari9272 Год назад

I like the way he taught in Hindi in this video...

@KNOWLEDGEGATE_kg Год назад

Thanks a lot dear❤Keep learning & supporting! Stay connected for more amazing videos & upcoming contents 👍😊You can also check out our CS bundle course for complete preparation of Computer Science subjects & free notes, sharing course link below: www.knowledgegate.in/learn/Zero-to-Hero-in-Computer-Science

@sanketchidrewar1867 6 лет назад

U'r way of explaining is too good.... I had seen u'r all videos on memory management...just awesome explanation.. U had done one mistake in this video..2^6=64 u have written it as 32..

@vishwanathgarrepalli731 4 года назад

yes i too fiound this issue

@cha5848 2 года назад

This was really helpful

@KNOWLEDGEGATE_kg 2 года назад

Thanks a lot dear 😍 Keep learning & supporting ! Do visit our website www.knowledgegate.in for more amazing courses & contents 👍😊

@bohemia6708 4 года назад

Thank u bhai... first time I got it

@surajpatil449 6 лет назад

thank you sir .... os paper was so easy because of you....understood !!!

@harpreetv761 6 лет назад

You are very good teacher.. very nyce sir

@SomneelMaity 6 лет назад

Sir aap humlogo ka bahut help kiye ho

@biswajitsadhu3607 5 лет назад

superb explanation n analogy !

@nahajyoti9837 7 лет назад

sir,we get more benefits by watching your videos. thank you so much.

@khursheekhan 5 лет назад

Sir sb samajh aa gaya thxx sir ji

@mohammadazad8433 4 года назад

Thanku sir ur video is very 👍💯best

@janavivaghasiya761 6 лет назад

Fall in love with your fruit full lectures....Great job Sir & Thank you so much...

@alamkhan-mc5xk 6 лет назад

me too...

@rishigoley3521 7 лет назад

Nice video sir. It cleared my concepts.

@HarshRaj-fp6pv 5 лет назад

Sir change channel name to "Knowledge Heaven"

@numaanjaved Год назад

I am not going to get any question about it but getting curious, how will the calculation be done when there are 2 secondary memories and 1 primary memory

@mukhtarbimurat5106 6 лет назад

Thank you very match, but i have question what was the main memory was it hard disk(but you say it is smaller than secondary memory) or cache or RAM, and what was secondary memory? I did not see previous videos(before 22)

@engineer_miss 6 лет назад

Tysm...Sir for providing us such depth knowledge ...☺

@ramanujkumar3834 7 лет назад

nice videos sir ...i request to you make on all subjects soon

@MohitK96 7 лет назад

Seriously, you are a great teacher. . . . .

@ronnybanerjee6020 7 лет назад

Hello sir, I only have one question. Why is that value ( here 10 bit in your example) which is used to address a each location in page table becoming the value of instruction offset?? i.e. Offset = 10 bits???

@manishsemwal5 5 лет назад

d is instruction offset i.e. the instruction no. in a frame If 1 page's size = 2KB Then there will be 2^11 instructions ( if memory is Byte addressable ( mostly, by default ) ) And 2^11 instructions need 11 bits to represent them hence d = 11

@mohammadazad8433 4 года назад

Nice lacture sir

@aprajitasinha8995 6 лет назад

Thanku so much I am completely able to understand paging

@maniaharshil 6 лет назад

Excellent explanation...thanks a lot....keep it up

@AmarKumar-bu1ec 7 лет назад

thank you sir.. all leacture videos are very helpful for us..

@shouryasingh9057 7 лет назад

you are too gud sir the way you u explains i just love it thankew a lot

@mohanlalsantolia9653 6 лет назад

Thanku sir, for the useful video.

@sumanbishnoi2286 7 лет назад

thanku sir ,well explained everything about how the paging system will work actually...thanku so much

@KNOWLEDGEGATE_kg 7 лет назад

Hi SUMAN, Thank you so much for your encouraging words.We upload more topics every week, Please subscribe this channel for best GATE tutorials. :)

@MANISHKUMAR-jr7sx 7 лет назад

Sir,Please upload videos on Virtual memory management as soon as possible because my END TERM EXAMS are near.

@priyajaganathakumar669 6 лет назад

Thank you sir. Well explained

@harendrasingh_22 5 лет назад

5:50 after dividing bhi I don't think we can go directly to a sector. Aise toh then directly goto that memory block.

@SomneelMaity 6 лет назад

Thank you very much sir

@RaviSingh-qt9mp 3 года назад

can't we use binary search instead of block and instruction number?

@awalktoinfinity665 5 лет назад

Sir but in one of previous videos you told that no of frames = no of pages .. But here in this example it is not so The statement said was while teaching page table that the no of indices a page table contains= no of pages in secondary memory and page table contains frame base address so no of pages should be equal to no of frames Please clarify this doubt... Request sir

@whatuhfacts 5 лет назад

He said page size=frame size, not the number of pages=number of frames.

@mayankpratapsingh4241 7 лет назад

sir u are too good

@yashjain1449 7 лет назад

awesome sir

@pns_news 5 лет назад

Sir there is a little mistake 2^6=64. In mm.

@9467430590 6 лет назад

Osum sir ji

@dilshadhassan4305 6 лет назад

sir how to create virtual memory using paging technique.....please try to explain in hindi

@fatimaejaz9779 5 лет назад

Sir, you are awesome!

@SHUBHAMSINGH-yj9lu 5 лет назад

no of pages in logical adress is no of pages in a single process or whole of secondary process??

@kookaburra2374 4 года назад

No. of pages in a process because if it total processes in secondary memory then there should be another field in logical address which is process no.. Like this Process no | page no | process offset.

@AakarshDarla 5 лет назад

7:58 - 8:37 We have 24 bits, so the combinations is 2^24 bits which is 16 Mega Bits not Mega Bytes ! So actually we have 2 MBytes !

@adibakhan2340 6 лет назад

Sir haven't u uploaded video for "segmentation"? Please answer

@rajatgupta6043 6 лет назад

sir, you have done one mistake while calculating 2^6 =64(correct) but you've written it 32

@sandysharma2858 7 лет назад

best teacher ever

@ashish7898 5 лет назад

What is size of page means?size of page table?

@mridulmarkandey9404 4 года назад

Sir how can P be the Total number of pages. Earlier you explained that P is the page number which we want to access in the Secondary Memory? PLEASE SOMEBODY EXPLAIN ME THIS??????

@ktejaakshithagoriparthi9106 7 лет назад

Tnq u sir

@kislayapant6119 7 лет назад

Sir could you please help me out solve the following question...This is gate 2013 question.. A computer uses 46-bit virtual address, 32-bit physical address, and a three-level paged page table organization. The page table base register stores the base address of the first-level table (T1), which occupies exactly one page. Each entry of T1 stores the base address of a page of the second-level table (T2). Each entry of T2 stores the base address of a page of the third-level table (T3). Each entry of T3 stores a page table entry (PTE). The PTE is 32 bits in size. The processor used in the computer has a 1 MB 16 way set associative virtually indexed physically tagged cache. The cache block size is 64 bytes. What is the size of a page in KB in this computer? A) 2B) 4C) 8D) 16

@ankitagupta8511 4 года назад

Can u share its solution...??

@AshishPrajapat009 7 лет назад

9:18

@dreaming_vin 4 года назад

While computing size of SM, why do we multiply 2^24 with size of each location instead of page size? Please solve this doubt. Please

@kevalkishan3824 4 года назад

beacuse inside 24 bits both bits for total page(14) and bits of pages size(10 as given 1 KB and it is byte adressable) we can get size of SM through (2^14 * page size ) = 2^14*1KB = 16MB

@vishalvins 5 лет назад

So, does this mean if Page Size is given to be say 1 KB = 2^10 bytes, the main memory is 10 byte addressable?

@AryanSingh-kt6ur 5 лет назад

yes, because size of page = size of frame and main memory is divided into equal no. of frames.

@bajrangimonkey 7 лет назад

If if a microprocessor having 24 address lines 32 data lines if it used 10 bit awkward than what will bethe size of memory buffer register ?please tell me answer.

@bajrangimonkey 7 лет назад

Sir that is 10bit Opcode

@sirsendubeheraakash6745 7 лет назад

sir u do one mistake in this vidio that is 2^6=64 ............sir i am big fan of your i see your every lecture so deeply...

@raghavatreya7423 7 лет назад

thank you sir !!

@manglammishra686 4 года назад

Please make it more clearand use Hindi and English combination

@pankajj4589 5 лет назад

os made easy!!!

@brijkishorarya4788 Год назад

sir esme PA m 2^6 to 64 k hoga na 32 to 2^5 hota h to answer 64kb hoga na ki 32 kb am I right or wrong

@bravodj1795 4 года назад

Can the number of pages be greater than the number of frames why they are not same because number of pages =no of frames for every process

@Rishi-nv7bp 5 лет назад

can someone explain what exactly size of location means and how it's different from size of page

@saquelainmokhtar6016 5 лет назад

i think it should b size of memory, and not size of page...

@quantumthoughts2698 4 года назад

size of memory = total no of blocks in MM or 2^n * size of 1block, size of location is actually not correct way to say but its the (size) no of bits required to represent MM address that is "n" page size is the fixed partition in which the Memory (primary and secondary) have been divided , page size = block size = frame size

@rohitvishwakarma9261 3 года назад

Sir if page size is equal to frame size and if a process is loaded completely into main memory then why not the number of frames = number of pages. Anyone please ?

@shaggy29073 6 лет назад

sir, please explain "memory overhead "

@parthpercy3210 7 лет назад

sir ,here the no of pages in seconadary memory or no of pages for a process in s.m

@universal4334 4 года назад

same doubt if it is in process how a 8k frames handle 4M pages

@ankitmehta6875 Год назад

In question number 2: 2k is equal to 2 raise to power 10 not 11.

@KNOWLEDGEGATE_kg Год назад

Dear @Ankit, 1K = 1024 = 2^10; 2K = 2 x 1K = 2x 2^10 2^11

@poojamann5181 7 лет назад

a memory management system has 64 pages wid 512 bytes page size. physical memory consist of 32 page framer....then how we calculate no. of bits required in logical nd physical address....sir how to solve it.....pls hlp ..

@adarshsasidharan254 5 лет назад

I think we would want to access sector number 93 instead of 92

@9910330934 7 лет назад

sir I want o get yur more videos

@swadhindas5853 7 лет назад

sir please upload multilevel paging concept

@saptarshibose9718 3 года назад

9:23 it would be 64kb instead of 32kb.

@arnabchatterjee1703 5 лет назад

sir i think the main memory size will be 64kb

@mohanlalsantolia9653 6 лет назад

Sir I liked your video. But sir please speak slowly. I cant get your speed of teaching

@superyRun 7 лет назад

Yes or No? - Yes.

@JasmeetSingh-oh8fq 4 года назад

main memory size was 64 kb though....2^6= 64

@aishwaryaraman6419 5 лет назад

Where are the videos of segmentation pls help

@mayankpratapsingh4241 7 лет назад

i'll share ur video

@NoorAhmad-yl5im 6 лет назад

Sir plz tell me one thing that 2^3o= 1G how? sir plz tell me because 2^10= 1024

@anubhavbarnwal940 6 лет назад

2^10*2^10*2^10=2^30=1024*1024*1024=1 GB

@ankitagrawal7399 6 лет назад

bhi koi btaiga ki ye you tube ads ka interference kaise kam kr

@stonecoldxi9138 6 лет назад

Agar koi ads pe click krta hai ya fir skippable ads ko atleast 30 seconds dekhta hai to youtube creator ko paise deti hai. RU-vid khud advertisers se paise leti hai for a certain amount of ads clicked/viewed(Ex 1000$ for 10000 views). So har 10 ad click ke youtube ko 1$ milta hai jisme se wo 45% rakhte hai and 55% channel creator ko milte hai.