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7.5.2 How to sketch the antiderivative of a function represented by a graph 

Cinema M119
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23 авг 2024

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Комментарии : 13   
@jacobc1355
@jacobc1355 Год назад
4 minutes of explaning taught me more than my professor spending an hour explaining, thank you so much.
@reverbflange
@reverbflange 10 лет назад
You have a great way of explaining! Thank you for the video!
@192ali1
@192ali1 2 года назад
Thank you. Good lecture. I wonder about your graph of F. I suppose in (2,3) interval graph should be concave up and from 3 to 5 (3,5) interval the graph of F should be concave down according to the information of derivative. Am I correct?
@hellodunyah
@hellodunyah 7 лет назад
Your handwriting is so gorgeous. Best I've ever seen.
@pranavravella9239
@pranavravella9239 4 года назад
Shouldn't the graph between (2,3) be concave down since F'(x) is decreasing
@mathatpcc7887
@mathatpcc7887 3 года назад
Yes, Pranav is correct: this video is incorrect and one of the errors is the concavity on (2,3). Another error is the concavity on (3,5) (it should also be concave down). Other errors are that F must be differentiable (so "smooth and curvy" not "sharp and pointy") at both 2 and 3 since f=F' exists at those values but the graph drawn in the video is nondifferentiable at 2 and 3. More specifically, since f(3)=0, the slope of F should be 0 at 3.
@mathatpcc7887
@mathatpcc7887 3 года назад
Here's my version of this video: ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-Zz8mE0RtO78.html.
@bcnicholas123
@bcnicholas123 7 лет назад
very helpful, thanks
@glassunicorn1525
@glassunicorn1525 6 лет назад
thank you
@AndreFerreira180
@AndreFerreira180 6 лет назад
you're a god
@delvianflemmings4871
@delvianflemmings4871 10 лет назад
Good vid
@hadiahamed9188
@hadiahamed9188 Год назад
Wonder what happened to this dude.
@baolongnguyen7844
@baolongnguyen7844 8 месяцев назад
One year after your comment, I came across this guy and wondered the same
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