How do you know where to put the hydrogen if you have a methyl that is not on either side of the pie bond, rather its further down the chain. So it comes out to be that markovnikovs rule won't apply because when placing the hydrogen either side of the pie bond it wld have the same amount of hydrogens, but our final answer would have a difference because of the other methyl group which is already attached to the chain. Let's say if I'm adding HCl, the Cl would end up being farther or closer depending on where I place my hydrogen in step one. So which one would I choose? Thanks, awsome vids!
First of all David, you're welcome!🙂 Second, you ask a great question but it's a little challenging to answer it here in the comments...so I made another short video titled "Markovnikov's Rule with Rearrangements" and posted it on my facebook page: facebook.com/chadsprep365 Thanks for the great question!
Excellent video! I took organic chemistry I last semester and I felt so lost when the professor began covering more reactions, such as this. Thank you for being so clear and organized. I'm starting to feel more confident in approaching the book/homework problems!
Great videos, Professor Chad. Every semester I try to get your class & it is ALWAYS FULL 😩😩. I love the way you teach these chemistry classes, THANK YOU 😁👏🏼😁
Thanks Rachel! And I'm working on it. Unfortunately I've been down sick for the last several days which has slowed me down but I'm close to getting back to the whiteboard! Happy Studying!🙂
when you say that stereoselectivity is "none" around 2:09, do you mean there's no stereoselectivity just for the reaction you have shown, not that there's no stereoselectivity for all hydrohalogenation reactions? Because at the end, there is a hydrohalogenation reaction that does have chiral centers and stereoselectivity. Thanks!
Great videos, Professor Chad. Every semester I try to get your class & it is ALWAYS FULL 😩😩. I love the way you teach these chemistry classes, THANK YOU 😁👏🏼😁
