#8 : List Comprehensions | Hackerrank Python Solutions 

print([[i, j, k] for i in range(x+1) for j in range(y+1) for k in range(z+1) if i+j+k != n])

list=[[a,b,c] for a in range(x+1) for b in range(y+1) for c in range(z+1) if a+b+c != n] print(list)

Bro, they have clearly mentioned to not solve using this method. You haven't spoken about List Comprehensions at all. Just add a rick roll somewhere to this video.

although this is not list comprehensions way to solve problem but you made concept clear thanks!

1) using if loop only:(1 condition only) [ expression ---> loop ---> condition ] (for) (if)

Bhai at least second solution to mil Gaya ,Ty

good work buddy i know you did not use list comprehensions although I learn from your videos keep going

Dude they have told to not use this method. The point of this whole problem was to learn about list comphrehensions 🤦‍♀

what about list comprehension here???????

does anyone understand this list comprehension ? >>>> return 1 in [c in word for c in charlist] . I am not getting it.

we had to use list comprehension instead of loop

Great!

hello, buddy you didn't use list comprehensions man!😂👌👌 nice and simple

Thank you sir

Are list compression lagana tha lala, pr tere logic sahi tha

thanks bro, you are my hero

Thank you.

They mentioned in the question to try not to use for loop !!

Without using function how can you use return bro

Thank you!

Thanks for the solution

U R ! A Pythoneer

full_liste = [[a,b,c] for a in range(x+1) for b in range(y+1) for c in range(z+1)] new_full_liste = [] for liste_name in full_liste : if reduce(lambda a,b: a + b , liste_name ) != n : new_full_liste.append(liste_name) print(new_full_liste) #do not forget to import reduce from functools

Thankyou sir❤️❤️❤️❤️

x=int(input('enter the value of x')) y=int(input('enter the value of y')) z=int(input('enter the value of z')) n=int(input('enter the value of n')) list=[[a,b,c] for a in range(x+1) for b in range(y+1) for c in range(z+1) ] list1=[[a,b,c] if a+b+c==n else [] for a in range(x+1) for b in range(y+1) for c in range(z+1)] i=0 while i

Hi everyone please try this one, this solution is using list comprehension and this will work for you 100%: l = [[i,j,k] for i in range(x+1) for j in range(y+1) for k in range(z+1) if (i+j+k) != n] print(l)

how we can use this problem in real life situations

list comprehension likha hai for loop use kar raha hai

what os is this thanks!

for god sake improve your English or talk in Hindi

time kharaab krdiya bhai tu..