for the last one if you just put those to points in a table then use a regression y1~ax1^2+bx1+c and then add a=2 in the line under that it will give you the value of B as -8
Do you think that this math was harder than practice tests 1-4? And or comparable to Math section on March DSAT? I got a 700 on this which Is my goal for June sat in two days.
@@Seaborg-sv9ffDEFINITELY. my score was really similar on the actual digital SAT to the practice test one on blue book. i score 10 points higher than they predicted, really close
Question 16 31:05 is not asking for the denominator to be trees that are 20 feet or taller. It is asking for a maple tree that is 20 feet or taller as the numerator. “ What is the probability of a selecting a maple tree, GIVEN that THE tree is 20 feet or taller?” The word GIVEN above is not describing the denominator as trees that are 20 feet or taller. It is describing THE maple tree that precedes it because of the following words “THE tree”. The word THE refers to the maple tree. I can rewrite the question as: “What is the probability of selecting a maple tree that is 20 feet or taller?” This question gives a different denominator (total number of trees). The question should be rephrased as: “What is the probability of selecting a maple tree, given trees that are 20 feet or taller?”
how do you know that you have to use a tilday in #20 module 2 (37:43)? also does this seem like a question that will appear on the test bc i feel like the previous practices haven’t included qs like this?
Cant we do this? f(x)=a(x-7)(x+7) so then it would be f(x)=ax^2-4ax-21a so therefore a+b would equal a -4a which would equal -3a so then our answer would have to be a negative multiple of -3 that isn't -3 itself, therefore -6 the only answer?
@@ManiH810 It's easier to say that the sum of solutions, which is 4, can be found using the formula -b/a. So, since -b/a = 4, b = -4a. From this, it is conceptually easy to understand that if a is an integer greater than 1, let's say 2, b would automatically be -8 (since b = -4a). Thus, a+b is -6.
what i meant is, in the video, when you solved the second module, was it the harder one that you get from getting most answers correct on the first module? or was it the easier version you get if you dont answer or get most wrong on the first module. i hope that makes sense- english is not my first language i apologize for any errors
The second module is usually harder and when you're taking the real thing it'll be adaptive so if you do well on the first one you'll the second module will be a lot harder.
For module 2 question 19, using the slider isn’t a very good method. Imagine the answer was 3.333, since it can only include real numbers, you wouldn’t known using the slider and 3.3 would look parallel. Just solve for p!
34:35 in your workbook you didnt say anything about the fact that dioganal is equal to diameter when rectanglular is inscribes in the circle, i am not complaining and not respecting your work I just dont understant how I supposed to solve this without any information about the similarity of dioganal and diammeter
I mean mate, you can kind of interpret that just by looking at it. The line of the diagonal of the rectangle shows two points equidistant from one another. Thus, it must be the equal to the diameter of the circle. You can also just look at the line and see that it splits the circle perfectly in half.
@@StrategicTestPrep me for sure. Thank you for doing these videos my sat is tomorrow and I've been going over this just as a quick refresher from the night before of the types of math that will be on the test. I will recommend this channel to anyone struggling to study for the SAT or anyone who doesn't know where to start. Thank you for your help and hard work!
