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Your work is immaculate efficient and you are truly an inspiration. I was not doing well at all at University of but now you have given Me new hope. Thank you!!!
@@user-tz1wb2gt7n actually wound up in Fall: 1B in the "C" programing and 1C for Calculus dropped psychology, But in Spring '23 all A's for 4classes 12 semester hours the 2nd Semester, I left that University to become a pilot all A's Fall Semester start ground and flight ✈️ labs Jan '24, Thanks for asking! Hope you are well and thank you for being there.
Thank youuu it was helpfull int main() { double number; printf("Enter The Number:"); scanf("%lf",&number); if (number>0){ printf("The Number is Positive!"); } else if(number
/* Can you create a program to check whether a number is positive or negative or 0? To create this program, create a variable named number and assign a double value to it based on the user input. Then using an if statement, check if the number variable is positive or negative or 0. > If number is positive, print"The number is positive" > If number is negative, print"The number is negative" > If number is 0, print "The number is Zero" */ #include int main() { double number; printf("Please write your number and I will let you know if its positive number, zero, or negative number: "); scanf("%lf", &number); if (number < 0){ printf("The number is negative."); } else if (number == 0){ printf("The number is Zero."); } else if (number > 0){ printf("the number is positive."); } return 0; }
A real beginner - #include int main(){ double number; printf("Enter any number "); scanf("%lf", &number); if(number>=1){ printf("The number is positive"); }else if(number
PROGRAMIZ QUIZ ANSWER: OPTION(A) Inside if PROGRAMMING TASK GIVEN BY MAM: #include int main() { double num1; printf("Enter a number here: "); scanf("%lf", &num1); if (num1>0){ printf("The number is positive."); } else if (num1==0){ printf("The number is neutral(It is 0)."); } else { printf("The number is negative."); } return 0; }
#include int main() { int a=-5; if (a0){ printf("The number is positive"); } else { printf("The number is 0"); } return 0; } Mam,Your classes are very helpful us thank you so much mam
Mam these videos are very useful. Thank you for helping us. If possible please make a series on c++ language and dsa in it. this will be very benificial for me and many more like me. Thank you.]
my answer for the question at the end: #include int main() { int number = -1; if(number == 0) printf("zero"); else if(number > 0) printf("positive"); else if(number < 0) printf("negative"); return 0; }
#include int main() { double number; printf ("Enter a number:"); scanf ("%lf", &number); if (number>0){ printf ("The number %0.2lf is positive",number); } else if (number
Q. What is the output of the following code? #include int main() { int a = 5; if (!(a % 2 == 0)) { printf("Inside if"); } else { printf("Inside else"); } return 0; }
@@arhitjoseph9681 a%2=1 ! (a%2==0) condition is true because a%2 is not equal to zero, so body of if statement exicuted , hence we can say , "inside if" printed .
Programming task :--- #include int main() { double number; printf("Enter number : "); scanf("%lf",&number); if (number > 0) printf("The number is positive"); else if(number < 0) printf("The number is negative"); else if(number == 0) printf("The number is zero"); return 0; }
// Online C compiler to run C program online /*This is a program to check whether a number is a positive, negative or a zero.*/ #include int main() { double number; printf("Enter any number: "); scanf("%lf", &number); if(number>0) { printf("The number %.2lf is positive.",number); } if(number==0) { printf("The number %.2lf is Zero.",number); } if(number
Answer to quiz is A #include int main() { // Write C code here double number; printf("what is your number? "); scanf("%lf", &number); if(number > 0){ printf("The number is positive"); } if(number < 0){ printf("The number is negative"); } if(number ==0){ printf("The number is 0"); } return 0; }
here the answer for your task mam thanks for teaching c easily #include int main() { double num; printf("enter the number :"); scanf("%lf", &num); if(num > 0) { printf("positve"); } if(num == 0) { printf("the number is 0"); } else if(num
its inside if, because the ! is logical not true and since the operative number is 0 than its right, unless the operative number is not 0. correct me if I missed something.
ANSWERS Task: double number; printf("please enter a number: "); scanf("%lf", &number); if (number > 0) { printf("this number is positive"); } else if (number < 0) { printf("this number is negative"); } else { printf("this number is 0"); } Quiz: inside if
#include #include int main() { double number ; printf("Input number:"); scanf("%lf",&number); if(number > 0){ printf("The number is positive"); } if(number == 0){ printf("The number is zero"); } if(number < 0){ printf("The number is negetive"); } }
else if condition is used in if else statement only if there are multiple conditions and else if condition is executed only "if condition" was false. There are many differences you can visit our tutorial to get more ideas. www.programiz.com/c-programming/c-if-else-statement
