90 FOR SURE! 

I like how the control warrior mirror match started at turn 6 with Justicar.

Just when you think missing the acolyte swap was bad enough, the opponent had to play his Yogg. Duel of legends.

Aww yes the control warrior mirror match....riveting.

Riveting Gameplay! Can't wait to see this match-up at Blizzcon.

You definitely dont play justicar there. Let the remaining ambushes get burned, delay fatigue and fewer minions to deal with in the long run. When they get burned, you don't draw the additional card like normal, so you basically add 2 cards to your deck.

The formula is: Total fatigue damage = (2f+n-1)*n/2 Where f is the fatigue damage he'll be taking on the first draw and n is the number of cards he draws.

The math relevant to fatigue dmg is "the Triangular Series". It's like the series of Perfect Squares, except the squares are triangles. I.e. the nth number of the series corresponds to "the total number of dots in an equilateral triangle, where: the length of its sides is n". E.g. a triangle with length (3) contains (6) dots - and coincidentally the 3rd Triangular Number is (6). O O O O O O The first twenty numbers are 0, 1, 3, 6, 10, 15, 21, 28, 36, 45, 55, 66, 78, 91, 105, 120, 136, 153, 171, 190, (etc) Like how we associate gravity with Issac Newton, mathematicians associate the Triangular Series with a dead German mathematician named Carl Gauss (arguably the greatest of all time). It's fabled that he invented a shortcut, which may resemble the formulas others have posted. The formula stacks the triangle on top of itself to form a rectangle, finds the area of the rectangle, then divides it in half. E.g. for (n := 3), the rectangle has a length of (3) and a width of (3 + 1). So the formula is (1/2) (3) (3 + 1), which reduces to (6). Therefore, the 3rd Triangular Number should be (6). O + + + O O + + O O O + T(n) = (1/2) (L) (W) = (1/2) (n) (n + 1) = (1/2) (n^2 + n) T(3) = (1/2) (3) (3 + 1) = (1/2) (9 + 3) = (6) The dmg generated by any given Mill Combo M(d, f) equals T(d + f + 1) - T(f), where: (f) is the turns of fatigue he's taken before the combo; and (d) is the card draw that the murlocs generate. E.g. Brann and two Murlocs generate (8) card draw, so (d := 8). You waited until the opponent had already taken (5) turns of fatigue, so (f := 5). The (+ 1) represents the opponent's extra tick of fatigue after you End Turn. T(f) represents the fatigue damage the opponent has taken before the combo. M(d, f) = T(d + f + 1) - T(f) M(8, 5) = T(8 + 5 + 1) - T(5) = T(14) - T(5) = 14 + 13 + (...) + 7 + 6 = (105) - (15) = (90) If you'd rather memorize a single clean formula rather than two formulas, we can expand T(d + f + 1) and T(f) then reduce M(d, f) to get (1/2) (d^2 + 3 d) + (f) (d + 1) + (1). For the sake of brevity, the derivation will be left as an exercise to the reader. M(d, f) = (1/2) (d^2 + 3 d) + (f) (d + 1) + (1) Sanity Check: M(8, 5) = (1/2) (8^2 + 3 * 8) + (5) (8 + 1) + (1) = (44) + (45) + (1) = (90) From this, we see that (d) scales polynomially while (f) scales linearly. This means that the dmg from the Murloc's card draw far exceeds the normal fatigue dmg taken from just sitting on the combo for an extra turn. Shield Block or Acolyte wouldn't have influenced the game one way or the other. Since the Exodia Combo E(f) probably won't change, we can assume that (d) remains constant at (8). E(f) = M(8, f) = (44) + (f) (9) + (1) = (45) + (9 f) = (9) (5 + f) So for this specific combo, the rule is "multiply fatigue by 9, then add 45". Or alternatively, "add 5 to fatigue, then multiply by 9".

Just multiply the highest number with the one exactly in the middle of the set (if there is none, just take the .5 step between the two middle ones) and you get the result. Example: 1+2+3+4+5 = 5 x 3 = 15. Or 1+2+3+4 = 4 x 2.5 = 10.

12:28 That Face Firebat made when he trusted in Twitch Chat and they were correct xD

6+7+8+9+10+11+12+13+14= 90.... Mathbat plz

It hurt when you said factorial. (Btw 9 factorial is 362880)

7:15 Got me so hard, nice editing Firebat :]

There is a thing called an Arithmetic sequence that would help. ------> Sum of values = ( 0.5xN ) x [ 2A + ( N - 1 )D ]

Yo, I made a JavaScript "program" to calculate the cards needed to kill your opponent, so you don't have to bother with maths. Just open Chrome (or any browser) and press F12, go to console and paste this: function calculateDraws(currHP, currFatigue) { var hp = currHP; var damage = currFatigue; var drawCount = 0; while (hp > 0) { hp -= damage; damage++; drawCount++; } console.log(drawCount); } calculateDraws(90, 6); Just make sure to replace the numbers in the brackets in the last row, the first number is your opponent's current HP and the second one is his current Fatigue, considering he is already at that point. I can make another where you can input the current card count in his deck if you want.

The opponent made some misplays here and there but the moment he dropped Yogg I couldn't wait for you to wreck him, Bat. He deserves every terrible thing that happens if he drops Yogg at that point.

Been subscribed for a bit now, and my favorite video by far! This just felt so intense, the clench was real.

Damn I just played a match with a variant of this deck and I was facing C'Thun Warrior, and we were both deep in to fatigue, he just took 6 damage from fatique last turn and he had 99 health in total, so I had exact lethal with the combo! FeelsGoodMan! (although i had a FieryWinAxe equipped for + 3 damage)

Love how everyone in this comment section thinks they're a math wizard, although my daughter could do the math lol. and i don't have a daughter. or a wife. or a life? fuck

Awesome dude!!! And thanks for the daily upload. You're the best

9!=1*2*3*...*9 You mean 1+2+3+...+9

1. Define starting value (x) = e.g in this game: x = 6 2. Define how many card draw (z) = e.g in this game: z = 9 3. Define ending value (y) = e.g in this game: y = 14 --------------------------------------------------------------------------------------- 4. Add the starting and ending value and divide it by 2= (x+y)/2 = (6+14)/2 = 20/2 = 10 5. Multiply that number with z = 10 * 9 = 90 p.s: if z is an even number, then x+y will always be odd, to make it easier, you don't need to divide x+y with 2 (because of the .5 thingy), just multiply x+y with z/2 for easier calculation

13:28 firebat pronounces "game" funny. hilarious.

How does this deck match up against classes that dont sit around waiting for death?

I love this deck. When I first saw in a Trolden video, I was so damn happy that it existed.

Love the editing around 7:18 misplay.

Hi Firebat. Here is the formula: Current fatigue = F. Cards to draw = D: (F + (F+D-1)) * D/2. Which can be written as (2F+D-1)*D/2. In your case: (2*6+9-1) * 9/2 --> 20*4.5 = 90.

It's amazing how well these clips age.

Just calculate the sum of the amount of cards drawn and then add the amount of cards times the already taken fatigue to the sum. i.e. 9 draws, opponent already took 5 fatigue at the last draw 9 draws = 1+2+3+4+5+6+7+8+9 = (1+9)+(2+8)+(3+7)+(4+6)+5 = 45 Alternatively: (9*(9+1))/2 = 45 [According to (n(n+1))/2] Now we just need to adjust for the already taken fatigue damage: 5*9+45 = 90 Or in short: (f*n)+((n(n+1))/2) = Damage (f = last fatigue damage taken; n = the number of draws) The most difficult part is getting the sum of the fatigue damage for the amount of card draws, to be honest. (And for that, one should get along pretty nicely in Hearthstone with just remembering the triangular numbers up to 10.)

So the formula for that combo is actually really easy, it's 45 plus an additional 9 for each additional turn they are in fatigue (if they are at 6 fatigue damage, 9*5=45 +45=90

guys, a easy way to do this math: he draw 9 cards; fatigue increase 1 damage for draw; 1st draw + 9st draw = 5st draw (x2), 2st draw + 8st draw = 5st draw (x2) ... so the damage is 5st draw (x9)

I guess you are talking about the fatigue combo: so you force the opponent to draw 5 cards, while fatiguing. So that means x, x+1, x+2, x+3, x+4. So we sum that up: 5x+10. So you will do a decent amount of damage.

That was amazing man ! Nice job :Dkeep the good work !

metapod used harden

fyi the fatigue formula is N(1+N)/2 N= number of cards he draws

factorial? no way Jose.

Just finished leper gnome otk and that reminded me of this video Decided to derive the fatigue formula, seems others have already, but it was a nice 8 minute distraction [d(2n+d+1)]/2 d = cards he's going to draw n= last fatigue damage he took

ResidentSleep- PogChamp

I feel like I've watched this video before. Is this a reupload?

Resident sleeper warrior now counters itself, good maybe the deck will fuck off the ladder now.

The easy calculation is the fatique damage of the fifth card multiplied by 9. You're welcome.

If the justicar wouldnt have been played, the 2 remaining nerubians would have buffered fatigue for another two rounds.

Well... that felt fucking satisfying

Hey dude, you do great work and I love your style of play and commentary. I have been trying to catch your stream live with no success, when do you normally stream and when do you think your next stream will be?

nice edits!! keep it up!! :D

when school math acctually applies to real world usage

I ran the number with spreadsheet, these are the "last fatigue" and "resulting next 9 card draws fatigue damage": 1 = 54 2 = 63 3 = 72 4 = 81 5 = 90 6 = 99 7 = 108 8 = 117 9 = 126 10 = 135

This is not the Twitch Chat you are looking for.

It's an arithmetic series.

Calculating fatigue damage simply requires knowledge of arithmetic progression.

triangular numbers are fun and interactive

So I think the easiest way to calculate that shit is to pre-emptively calculate the amount of damage he'll take from your full combo if he has taken no fatigue damage prior (45 in this case) and add the last amount of damage he took times the amount of cards you fatigue. So in this case (with F = last fatigue) 45 + 9 x F That isn't too bad right?

Awesome video, i thought you would miscount XD

How well would two violet illusionists work? On for fools bane and one for fatigue combo

he shouldnt have to play Justicar becouse in that case he burning 2 ambushs, so minus 2 4/4 and plus 2 turns without fatigue

Why isn't the Shield Block worth it? Even if we consider the eventual fatigue, it's basically worth (5 - (1 + n)) health - and the second one worth one less than that - where n is the difference between the cards in your opponent's deck and the cards in your deck. This is also not considering the huge drawback of milling Justicar.

If this deck isn't fun and interactive, then I don't know what is.

Gotta think of a joke im early Priest

the formula for the next games : n*(n-1)/2 + q*n where: n is the numer of cards that he will draw q is the fatigue damage that he will take at the first draw better know it when you play a fatigue deck

I'm fairly positive that Justicar is just a card

x + (x + 1) + (x + 2) + (x + 3) + (x + 4) + (x + 5) + (x + 6) + (x + 7) + (x + 8) = 9x + 36 = 9(x + 4) Hence if x = 6, he'll take 90 damage. Easy enough to calculate quickly!

Hey guys, what is Firebat's credit song please. I like his content, very nice

I expected one hell of a fail lol

Nine factorial damage?! That's 362880! Super OP! /s

7:27 nAAW

Because I don't thrust my math nor firebat's, I actually posed and made a "program" that calculate the damage for me.

its like watching two metapods

People are putting up these weird formulas, I'm not gonna bother checking if they work. It's 9x + 45 (and works for negative numbers, so it will kill a 30hp opponent with 1 card remaining). The +45 I had to math out (cheated and used a calculator cause lazy), but its obviously going to do 9x the fatigue they just took.

i was so sure he would miscalc haha

45 + 9x, where x is the last tick of fatigue dealt

thaths why i play hs with pen and paper near

Illusionist is going to make Warrior a tier 1 staple for a year and a half, mark my words. It is more consistent and powerful than Monkey because it has guaranteed results. Any normal control deck can throw in the 4 card combo and drop it at any time once fatigue hits. It allows Control to play a much more tempo oriented early and mid-game compared to, say, Murloc paladin, because you aren't dropping low impact murloc cards on the board. I bet it gets nerfed.

Firebat, are you coming to Indonesia for 8th ie-sf international e sports championship?

that deck looks so fun tbh

Formula is ---> n(n+1)/2. 9 draws is 9(10)/2=45

we math'ed hard, team.

Wait who uploaded this video first? I've seen this before :O

Brutal. Wow.

"fun and interactive"

such pro player

è una cagata pazzesca di mazzo!

Impressive !

RIP Control Warrior :(

Why Acolyte in this deck? Mb Doomsayers or Soggoth would be better?

just start typing in you chrome browser address bar. 6+7+8+9+10+11+12+13+14... It gives you the answer.

Miller Time.

you're not using malchezaar for the ultimately fat warrior? though, on second thought I suppose he fills the same role as violet illusionist here, and in addition stuffs your deck with 2 good, and 3 useless cards.

11 + 4 :thinking:

he shoulda sat on the justicar :(

holy smokes

did he need justicar? find out next time on firebat doesn't do the math

Lol someone in chat though the sum to 9 was 9! xD

never punished

Plox get a decklist that shows what you've drawn m8os.

Firebat y u no have elise or malchezaar? 😰

12:00 your welcome

There's a reason it says "legend" in the end. Nice math tho.

You said 9 factorial, but that would be 1x2x3x4x5x6x7x8x9, which is VERY far from the actual 1+2+3+4+5+6+7+8+9 damage Know your math, firebat

(x-8)4-((x(1+x))/2)=-90 x= cards overdrawn There you have your formula

Miss BM

got his ass hahhaahahahah