A Beautiful Equation from Romania, probably

Подписаться 150 тыс.

Просмотров 4,3 тыс.

50% 1

🤩 Hello everyone, I'm very excited to bring you a new channel (aplusbi)
Enjoy...and thank you for your support!!! 🧡🥰🎉🥳🧡
/ @sybermathshorts
/ @aplusbi
⭐ Join this channel to get access to perks:→ bit.ly/3cBgfR1
My merch → teespring.com/...
Follow me → / sybermath
Subscribe → www.youtube.co...
⭐ Suggest → forms.gle/A5bG...
If you need to post a picture of your solution or idea:
in...
#polynomials #polynomialequations #algebra
via @RU-vid @Apple @Desmos @NotabilityApp @googledocs @canva
PLAYLISTS 🎵 :
Number Theory Problems: • Number Theory Problems
Challenging Math Problems: • Challenging Math Problems
Trigonometry Problems: • Trigonometry Problems
Diophantine Equations and Systems: • Diophantine Equations ...
Calculus: • Calculus

Опубликовано:

15 сен 2024

Ссылка:

Скачать:

Готовим ссылку...

Добавить в:

Мой плейлист

Посмотреть позже

Комментарии : 15

@hookahsupplier.5155 7 месяцев назад

Amazing question, didn't solve it but had fun watching the solution!

@nasrullahhusnan2289 7 месяцев назад

I think it is simpler to work this way: Move all terms in one side (x^x)²-x²(x^x)-(x^x)x+x³=0 Factorize (x^x)[(x^x)-x²]-x[(x^x)-x²]=0 [(x^x)-x²][(x^x)-x]=0 (x^x)=x² --> x^(x-2)=1 x=1 or x=2 (x^x)=x --> x=±1 Thus x={-1,1 2}

@williamspostoronnim9845 Месяц назад

Ничего себе примерчик!

@MATHUP869 7 месяцев назад

Thank you for your shareing Master

@SyberMath 7 месяцев назад

My pleasure

@scottleung9587 7 месяцев назад

I got 1 and 2 but didn't consider -1.

@leif1075 7 месяцев назад

Youbforgot zero too..also a valid solution..and maybe i in the complex world

@altosrule6387 7 месяцев назад

@@leif1075 Zero is not a valid solution. The limit as x goes to 0 of x^(2x) is 1, while the other terms all equal zero. I don't think i is a valid solution either.

@Mdsamim-go8rp 7 месяцев назад

Beautiful equation with Beautiful explanation ❤❤

@SyberMath 7 месяцев назад

Thanks a lot 😊❤️

@markener4316 7 месяцев назад

What would if theroaticlly possible a integrated matrix be?

@markener4316 7 месяцев назад

@IonRuby my grammer is so good i swear

@rakenzarnsworld2 7 месяцев назад

x = 2

@SidneiMV 2 месяца назад

(xˣ)² - x²xˣ - x¹xˣ + x³ = 0 (xˣ)² - (x² + x)xˣ + x³ = 0 xˣ = [(x² + x) ± (x² - x)]/2 xˣ = x² xlnx = 2lnx (x - 2)lnx = 0 *x = 2* lnx = 0 => *x = 1* xˣ = x xlnx = lnx (x - 1)lnx = 0 x = 1 lnx = 0 => x = 1

@SidneiMV 2 месяца назад

my method ommits x = -1 .....