A-Level Chemistry Sodium Thiosulfate and Iodine Titrations

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Mrs Lucas explains the sodium thiosulfate and iodine titration theory and calculation.
Apologies I didn’t balance the hydrogen ions in the first equations!!! There should be 6H+ ions to balance the 3H2O
NB: This is the first RU-vid tutorial Mrs Lucas has ever done so please be kind!! It was also filmed during lockdown so again, be kind!!

Опубликовано:

14 апр 2020

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Комментарии : 54

@jensychiang8352 8 месяцев назад

You have no idea how much this saved me. Thank you so much!

@tomiolasoji9712 3 года назад

I'm so happy I found this. This was so well explained, thank so much you for doing this!

@beauchampchemistry9031 3 года назад

Very welcome- glad you found it useful

@essie180 Год назад

This is so well explained, thankyou so much !!

@jenicagong5193 Год назад

Thank you so much for such a clear explanation. This video has been extremely helpful

@yousifmajeed9316 2 года назад

These are very good and clear explanations.

@MishaAisyah 3 года назад

thank you so much Mrs Lucas for the explanation!

@beauchampchemistry9031 3 года назад

Very welcome! Thanks for watching

@jeond9762 2 года назад

Thank you so much mrs lucas

@Anant_1939 2 года назад

Nice explanation!!

@athithyan3879 2 года назад

I want you to know i loved this vid, saved me for my practical thank you SOOOO much

@beauchampchemistry9031 2 года назад

So pleased it was helpful for you! 👍

@mattearthling1691 2 года назад

Thanks, really helped glad I found this.

@ophira4081 3 года назад

Thanks for such a amazing video . I wish I could have teachers like u in our university 😢 By the way it's amazing 👏

@beauchampchemistry9031 2 года назад

Thank you for your kind comment- so glad you found it useful!

@kevinkularatne327 3 года назад

Nicely Explained! Thank you!

@beauchampchemistry9031 3 года назад

Very welcome- thanks for watching!

@multi-talentwithgrace1761 Год назад

Thanks so much....I can't expressed how I feel bcos being an empty headed student in this topic just changed to a sensible student by watching ur video

@bakacheyounes9325 2 года назад

thank you so much

@obey8100 3 года назад

THANK YOU FOR THE EXPLANATION

@beauchampchemistry9031 3 года назад

Very welcome!

@amjedelnima2852 3 года назад

Great explanation!

@beauchampchemistry9031 3 года назад

Thanks so much!

@adrianaalejandrahernandezp8040 3 года назад

Greetings from México, thanks for this video now I understand

@beauchampchemistry9031 3 года назад

You are so very welcome- thanks for watching

@agborjames3375 8 месяцев назад

Thank you so much for the insight madam

@ayasamer7731 3 года назад

Thank u soo much❤ Finally I understand iodometric 😍❤ We want more practices to be able to calculate precisely

@angelkorbyn3038 3 года назад

I guess I am pretty off topic but does anybody know of a good place to watch new movies online ?

@thinkdontshoot8065 2 года назад

@@angelkorbyn3038 bruh

@oluwakemiodedina2858 2 года назад

@@angelkorbyn3038 there are much better places to ask this

@nainakaur9680 2 года назад

Thank you

@uchenduchigozie3488 Месяц назад

Thanks

@sherifhabbak8868 2 года назад

I have a commercial Povidone-Iodine solution that I would like to test to know the amount of free iodine in this solution. how do I prepare the Iodate solution? should I jump to equation 2 right away and start titrating with sodium thiosulphate without the previous reaction?

@aishworyaparajuli3949 3 года назад

do we need to know sodium thiosulfate redox calculations for aqa? thanks

@GangGang-dx7te 2 года назад

Could you help me how to solve this problem ? Ma'am.... One vitamin C tablet is dissolved in an acidic solution. Add 2 g of solid KI and 50.00 mL of the 0.01795 M KIO3 solution. The solution is titrated with a 0.1258 M thiosulfate solution and reaches the endpoint at 6.12 mL of titrant. What are the moles of triiodide consumed by the vitamin C tablet?

@golddrogershankskaido8614 Год назад

i love it....

@golddrogershankskaido8614 Год назад

make me more understand

@zahirahhannani7362 10 месяцев назад

I have a question regarding on redox titration experiment. Can you explain what is the purpose of standardisation on aknown concentration sodium thiosulphate solution?

@rume3137 8 месяцев назад

In the begging, we accept the concentration of sodium sulphate as 0.100 M but are we sure that this is the real concentration value of the sodium sulphate? For example; if the real value is 0.089, the number of moles will change and it will effect the results.My opinion is like that.

@Frederick-765 Год назад

What is the order of reaction

@willhales4553 3 года назад

I'm confused- in step 4 where 1.875x10^-3 is divided by 3 how do you get 3.958x10^-4? Isn't it 6.25x10^-4? Am I missing something?

@beauchampchemistry9031 3 года назад

Thanks Will- I have absolutely no idea how I got this wrong!! I shall blame lockdown brain! Thanks for spotting!! As long as everyone understands the process then hopefully it will still be useful!

@kamilakucerova1620 3 года назад

@@beauchampchemistry9031 First of all - thank you for this video, it really helped me! I think there's a mistake in the step 2 instead of step 4. I've tried to solve this task on my own and when I divided 2.375^-3 by 2, I got 1.1875^-3 instead of 1.875^-3. Then when I used 1.1875^-3 in step 4, I got 3.958x10^-4 as in the video. Is it right? :)

@ehandpiece 2 года назад

WoW! Your smart.. i don't understand this stuff and i am a MAN! I would not have known it was wrong. Weird? Thanks.:)

@RonnieHeuvel 4 месяца назад

@@kamilakucerova1620 What you did is correct. She didn't put 1 before the 875 in the video. But the numbers don't really matter if you just want to understand the process.

@OwnsYourFace204 3 года назад

Why is H+ added?

@thomasc886 3 года назад

the H+ takes place in the reaction by combining with the oxygen from the iodate ions to make water, and also, although it isn't shown, the anions (negative ions) that would have been bonded to the hydrogens in whatever acid they were part of would replace the iodide anions on the left side of the equation by bonding to the cations (positive ions) that they had come bonded to, most often sodium or potassium, though it could of course be others.

@agborjames3375 8 месяцев назад

Please step 7 is 0.847/1* 100