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A Very Nice Math Olympiad Problem | Solve for a 

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In this video, I'll be showing you step by step on how to solve this Olympiad Maths Exponential problem using a simple trick.
Please feel free to share your ideas in the comment section.
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24 сен 2024

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Комментарии : 4   
@Nikioko
@Nikioko 15 дней назад
5³ᵃ = 10 3a · lg(5) = 1 a = 1 / [3 · lg(5)] a ≈ 0,477 (which is very close to lg(3), by coincidence)
@freepointsgals609
@freepointsgals609 16 дней назад
a=ln(10)/(3ln(5)). This is pretty easy to generalize.
@Nikioko
@Nikioko 15 дней назад
Why ln? If you use lg instead, you get a = 1 / (3 · lg(5)).
@Mathslover666
@Mathslover666 14 дней назад
Yah he is making it more complex.
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