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A Weird Problem to Simplify 

Brian McLogan
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Here is a problem that confuses students everytime I give it. It is important to learn how to break it down so that you can simplify on your own.
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28 сен 2024

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Комментарии : 29   
@Sultan_A
@Sultan_A 5 месяцев назад
💎 Very Good, Brian McLogan, Keep It Up 💎
@abshariadam
@abshariadam 5 месяцев назад
I used the property of subtracting the exponent when it's an exponent is devided by the same base, so 3^(-2)/3^(-3) is just 3^(-2-(-3)) = 3^(1) Then doing it the same way to the denominator and we would get 3^(1)/3^(-4) = 3^(1-(-4)) = 3^5 = 243
@benharland1986
@benharland1986 5 месяцев назад
do you think you could make an in depth video about functions of 2 variables? i cant seem to find a good explanation for it (all from domain to contour lines)
@baldusi
@baldusi 5 месяцев назад
Totally unnecessary. When you have pure multiplications/divisions the order is irrelevant. And as you have the same base, you just sum the two divisor exponents (-3) + (-4) = -7. Then you swap the sign of the exponent of (-7) so you can do a sum with the exponent of the denominator (-2), -2 + 7, and you end up with 3^5.
@hanskaminsky812
@hanskaminsky812 5 месяцев назад
You can't add exponent -4 to -3 (and get 3 raised to -7) when you start evaluating the bottom division. it should be +4 to -3,. So the problem is reduced to 3 raised to -2, divided by 3 raised to +1. The result is 3 raised to -3 = 1/27 which is the final answer.
@baldusi
@baldusi 5 месяцев назад
@@hanskaminsky812 You have to go back to the basics of arithmetic: multiplication and division are commutative. You absolutely can. In fact, just by looking at it the equation is trivial 3^(-2) x 3^3 x 3^4. The only way it would be different is if it had been written as 3^(-2) / [3^(-3) / 3^(-4)]. But it wasn't.
@jillianwinkelspecht1182
@jillianwinkelspecht1182 5 месяцев назад
THANK YOU SO MUCH!!! Online math is hard and you make it so much easier
@kusinaniatesel
@kusinaniatesel 5 месяцев назад
Thanks sir for helping me in that problem! Godbless you sir!
@chemistrywithsirraphael534
@chemistrywithsirraphael534 5 месяцев назад
Well explained and solved❤❤
@charlesmitchell5841
@charlesmitchell5841 5 месяцев назад
Good step by step explanation. Thanks
@AubreyForever
@AubreyForever 5 месяцев назад
How does this video work? Is he writing on a mirror or glass?
@cstockman3461
@cstockman3461 5 месяцев назад
He's writing on glass, which is then reflected in a mirror, and he is filming the mirror
@MicoAquinoComposer
@MicoAquinoComposer 5 месяцев назад
Great explanation! Thank you
@yungogthathoop7475
@yungogthathoop7475 5 месяцев назад
Nice one🎉
@hanskaminsky812
@hanskaminsky812 5 месяцев назад
Your answer is incorrect! It should be 1 divided by 27. You can't replace two divisions by 2 multiplications.
@hanskaminsky812
@hanskaminsky812 5 месяцев назад
(and change the sign of the exponent)
@johnnolen8338
@johnnolen8338 5 месяцев назад
McLogan did it right. The problem seems more complicated than it actually is. As originally written: 3^-2/3^-3/3^-4 can be rewritten as 3^-2·3^3·3^4 = 3^(-2 + 3 + 4) = 3^5 = 243◼ Multiplication and Division have the same level of precedence in the order of operations.
@hanskaminsky812
@hanskaminsky812 5 месяцев назад
Nope, he's not. You have to start evaluating the bottom division, which is 3. Then you have 1/9 divided by 3, which is 1/27.
@jesther4140
@jesther4140 5 месяцев назад
@@hanskaminsky812 What then, did you arrive at for a final answer?
@hanskaminsky812
@hanskaminsky812 5 месяцев назад
Yes, 1/27 is the final answer.
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