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Abstract Algebra | The field of fractions of an integral domain. 

Michael Penn
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We present the notion of the field of fractions of an arbitrary integral domain, give some examples, and prove that we indeed have constructed the smallest field containing the original integral domain.
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1 май 2020

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Комментарии : 13   
@ImaginaryMdA
@ImaginaryMdA 3 года назад
This is lovely, and a great way to show that the field of rational polynomials is in fact a field, IMO. Doesn't require any fiddley details.
@xshortguy
@xshortguy 4 года назад
That awkward moment where the video is not well defined when proving that the field of fractions addition is well defined.
@niklasnetter2190
@niklasnetter2190 4 года назад
Just great! The speed is just perfect.
@jackmaibach8316
@jackmaibach8316 4 года назад
Great content as always!
@AKhoja
@AKhoja 4 года назад
Hey Michael, I really love your videos. I noticed that you cover a very broad range of topics on this channel, which is cool, but have you considered working on more chronological series that cover the foundations of different subjects in math? I would love to see, for example, a series building abstract algebra up from the ground, or seeing a series on the Zeta function and its properties in number theory. Maybe that's not the sort of content you'd be interested to make, but I thought it would be nice to suggest.
@MichaelPennMath
@MichaelPennMath 4 года назад
All of the videos that are titled in the form Subject Name | Topic are part of course materials that I put together for my teaching purposes. As such, most of them are part of big playlists that are more or less in order and start at the very beginning. For example, here is the full Abstract Algebra playlist: ru-vid.com/group/PL22w63XsKjqxaZ-v5N4AprggFkQXgkNoP
@AKhoja
@AKhoja 4 года назад
@@MichaelPennMath The playlist section on your channel is so extensive that I didn't spot them! Thank you
@ojas3464
@ojas3464 Месяц назад
It appears we only need that the Domain be commutative and cancelative, and the existence of multiplicative inverse could be waived. By defining the inverse image of the Diagonal of D X D of the imbedding map into the Quotient Field, a multiplicative identity for D could extracted, disregarding Set-Theoretic issues
@johnkevinpadro7819
@johnkevinpadro7819 7 месяцев назад
Hi Sir Michael, can you discuss about Algebraic Extensions of a Field??
@bishwajitsarma5768
@bishwajitsarma5768 11 месяцев назад
Which part proofs the uniqueness of the field of fraction?
@natepolidoro4565
@natepolidoro4565 4 года назад
Chek
@vadimpavlov6037
@vadimpavlov6037 19 дней назад
Jumpscare at 0:08
@kushagrasinghal8209
@kushagrasinghal8209 4 месяца назад
gg
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